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Oscillations Test - 52

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Oscillations Test - 52
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  • Question 1
    4 / -1
    Time period of a simple pendulum of length l is T1 and time period of a uniform rod of the same length l pivoted about one end and oscillating in a vertical plane is T2. Amplitude of oscillations in both the cases in small. Then T1/T2 is
  • Question 2
    4 / -1
    What will be the force constant of the spring system shown in fig.

  • Question 3
    4 / -1
    Two simple harmonic motions with the same frequency act on a particle at right angles i.e., along x and y. axis. if the two amplitudes are equal and the phase difference is π/2, the resultant motion will be
  • Question 4
    4 / -1
    A particle, with restoring force proportional to displacement and resisting force proportional to velocity is subjected to a force F sin ωt. If the amplitude of the particle is maximum for ω = ω1 and the energy of the particle is maximum for ω = ω2 then
  • Question 5
    4 / -1
    A uniform circular disc of mass 12 kg is held by two identical springs as shown in the figure. When the disc pressed down slightly and released, it executes SHM with a time period of 2s. The force constant of each spring is

    Solution

  • Question 6
    4 / -1
    A particle executes simple harmonic motion with an angular velocity and maximum acceleration of 3.5 rad/sec and 7.5 m/s2 respectively. Amplitude of the oscillation is
    Solution

  • Question 7
    4 / -1
    A coin is placed on a horizontal platform, which undergoes vertical S.H.M. of angular frequency ω. The amplitude of oscillations is gradually increased. The coin will have contact with the platform for the first time. (i) at the higher position of the platform (ii) at the mean position of the platform (iii) for an amplitude of g/ω2 (iv) for an amplitude of √2/ω
    Solution

  • Question 8
    4 / -1
    a simple pendulum of length I has a bob of mass m, with a charge q on it.A vertical sheet of charge with surface charge density σ passes through the point of suspension. At equilibrium, the spring makes an angle θ with the vertical. Its time period of oscillations T in this position. Then
    Solution

  • Question 9
    4 / -1
    A particle executes simple harmonic motion between x = –A and x = +A. the time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then
  • Question 10
    4 / -1
    A mass is suspended separately by two different springs in successive order then time periods is t1 and t2 respectively. If t is connected by both springs as shown in Fig., then time period is t0, the correct relation is

    Solution

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