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Dual Nature of Radiation and Matter Test - 107

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Dual Nature of Radiation and Matter Test - 107
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  • Question 1
    4 / -1
    An X – ray tube is operating at 15 kv. The lower limit of the wavelength of X – rays produced is
    Solution

  • Question 2
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    Light of wavelength 5000Å falls on a sensitive plate with photoelectric work function of 1.9 eV. The kinetic energy of the photoelectron emitted will be
    Solution

  • Question 3
    4 / -1
    Two radiations containing photons of energy twice and five times the work function of a metal are incident successively on the metal surface. The ratio of the maximum velocities of the emitted electrons in the two cases will be
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  • Question 4
    4 / -1
    Electron with energy 80 ke V are incident on the tungsten target of an X – ray tube. K shell electrons of tungsten have –72.5 Ke V energy .X –rays emitted by the tube contain only
    Solution

  • Question 5
    4 / -1
    An ionised gas contains both positive and negative ions. If it is subjected simultaneously to an electric field along the +x direction and a magnetic field along the +z direction, then
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  • Question 6
    4 / -1
    Find the kinetic energy of the photoelectrons emitted when light of wavelength 4000Å is incident on a metal of work function 2eV (find approximately)
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  • Question 7
    4 / -1
    If the potential difference applied across X – ray tube is V volt, then approximately minimum wavelength of the emitted X – rays will be
    Solution

  • Question 8
    4 / -1
    A proton and an alpha particle are accelerated through a potential difference of 100 V. The ratio of the wavelength associated with the proton to that associated with an alpha particle is
    Solution

  • Question 9
    4 / -1
    Two identical photo – cathodes receive light of frequencies f1 and f2. If the velocities of the photoelectrons ( of mass m) coming out are respectively v1 and v2,then.
    Solution

  • Question 10
    4 / -1
    An X – ray tube is operated at a constant potential difference and it is required to get X – rays of wavelength not less than 0.2 nano-meter. Then the potential difference in kilo volt is (h = 6.63 × 10–34 Js ; e = 1.6 × 10-19 C, c = 3 × 108 m/s)
    Solution

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