Dual Nature of Radiation and Matter Test

Result

Dual Nature of Radiation and Matter Test - 44

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Weekly Quiz Competition

Question 1
4 / -1

If the momentum of a photon is p, then its frequency is Where m is the rest mass of the photon

A

B

C

D

Solution
Question 2
4 / -1

A
E/p

B
Ep

C

D
3 × 10⁸ m/s

Solution
Question 3
4 / -1

An important spectral emission line has a wavelength of 21 cm. The corresponding photon energy is (h = 6.62 × 10^–34 Js; c = 3 × 10⁸ m/s)

A
5.9 × 10^–4 eV

B
5.9 × 10^–6 eV

C
5.9 × 10^–8 eV

D
11.8 × 10^–6 eV

Solution
Question 4
4 / -1

The momentum of a photon in an X-ray beam of 10^–10 metre wavelength is

A
1.5 × 10^–23 kg-m/s

B
6.6 × 10^–24 kg-m/s

C
6.6 × 10^–44 kg-m/s

D
2.2 × 10^–52 kg-m/s

Solution
Question 5
4 / -1

The energy of a photon of light with wavelength 5000 Å is approximately 2.5 eV. This way the energy of an X-ray photon with wavelength 1 Å would be

A
2.5/5000 eV

B
2.5/(5000)² eV

C
2.5 × 5000 eV

D
2.5 × (5000) ² eV

Solution
Question 6
4 / -1

Energy of a quanta of frequency 10¹⁵ Hz and h = 6.6 × 10^–34 J-s will be

A
6.6 × 10^–19 J

B
6.6 × 10^–12 J

C
6.6 × 10^–49 J

D
6.6×10^–41 J

Solution
Question 7
4 / -1

Wavelength of a 1 keV photon is 1.24 × 10^–9 m. What is the frequency of 1 MeV photon

A
1.24 × 10¹⁵ Hz

B
2.4 × 10²⁰ Hz

C
1.24 × 10¹⁸ Hz

D
2.4 × 10²³ Hz

Solution
Question 8
4 / -1

What is the momentum of a photon having frequency 1.5 × 10¹³ Hz?

A
3.3 × 10^–29 kg m/s

B
3.3 × 10^–34 kg m/s

C
6.6 × 10^–34 kg m/s

D
6.6 × 10^–30 kg m/s

Solution
Question 9
4 / -1

Which of the following statements is not correct?

A
Photographic plates are sensitive to infrared rays

B
Photographic plates are sensitive to ultraviolet rays

C
Infra-red rays are invisible but can cast shadows like visible light

D
Infrared photons have more energy than photons of visible light

Solution
Question 10
4 / -1

If we express the energy of a photon in KeV and the wavelength in angstroms, then energy of a photon can be calculated from the relation

A
E= 12.4 hv

B
E =12.4 h/λ

C
E = 12.4 / λ

D
E = hv

Solution