Dual Nature of ...

For the Bohr\'s first orbit of circumference 2πr, the de-Broglie wavelength of revolving electron will be

What is the de-Broglie wavelength of the α–particle accelerated through a potential difference V?

The energy that should be added to an electron, to reduce its de-Broglie wavelength from 10^–10m to0.5 × 10^–10 m, will be

If particles are moving with same velocity, then maximum de-Broglie wavelength will be for

If an electron and a photon propagate in the form of waves having the same wavelength, it implies that they have the same

The de-Broglie wavelength is proportional to

Particle nature and wave nature of electromagneticwaves and electrons can be shown by

The de-Broglie wavelength of a particle moving with a velocity 2.25 × 10⁸ m/s is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is (velocity of light is 3 × 10⁸ m/s)

According to de-Broglie, the de-Broglie wavelength for electron in an orbit of (radius 5.3 × 10¹¹ m) hydrogen atom is 10^–10 m. The principle quantum number of this electron is

The speed of an electron having a wavelength of10^–10 m is