Atoms and Nuclei Test

Result

Atoms and Nuclei Test - 110

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Weekly Quiz Competition

Question 1
4 / -1

The force acting between proton and proton inside the nucleus is

A
Coulombic

B
Nuclear

C
Both

D
None of these
Question 2
4 / -1

For a nucleus to be stable, the correct relation between neutron number N and proton number Z is

A
N > Z

B
N = Z

C
N < Z

D
N ≥ Z

Solution
Question 3
4 / -1

M_n and M_p represent mass of neutron and proton respectively. If an element having atomic mass M has N-neutrons and Z-protons, then the correct relation will be

A
M <[NM_n + ZM_p]

B
M >[NM_n + ZM_p]

C
M =[NM_n + ZM_p]

D
M n + ZM_p]
Question 4
4 / -1

The radius of a nucleus of a mass number A is directly proportional to

A
A³

B
A

C
A^2/3

D
A^1/3

Solution
Question 5
4 / -1

The mass and energy equivalent to 1 amu are respectively

A
1.67 × 10^–27gm, 9.30 MeV

B
1.67 × 10^–27 kg, 930 MeV

C
1.67 × 10^–27 kg, 1 MeV

D
1.67 × 10^–34 kg, 1 MeV
Question 6
4 / -1

As compared ¹²C atom, ¹⁴C atom has

A
Two extra protons and two extra electrons

B
Two extra protons but no extra electrons

C
Two extra neutrons and no extra electrons

D
Two extra neutrons and two extra electrons

Solution
Question 7
4 / -1

Two protons exert a nuclear force on each other, the distance between them is

A
10^–14 m

B
10^–10 m

C
10^–12 m

D
10^–8 m
Question 8
4 / -1

If m, m_n, and m_pare the masses of _ZX^A nucleus,neutron and proton respectively, then

A
m <(A – Z)m_n + Zm_p

B
m = (A – Z)m_n + Zm_p

C
m = (A – Z)m_p + Zm_n

D
m >(A – Z)m_n + Zm_p

Solution
Question 9
4 / -1

The mass defect in a particular nuclear reaction is 0.3 grams. The amount of energy liberated in kilowatt hours is (Velocity of light = 3 × 10⁸ m/s)

A
1.5 × 10⁶

B
2.5 × 10⁶

C
3 × 10⁶

D
7.5 × 10⁶

Solution
Question 10
4 / -1

On the bombardment of neutron with Boron. a-particle is emitted and product nuclei formed is

A
₆C¹²

B
₃Li⁶

C
₃Li⁷

D
₄Be⁹

Solution

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Atoms and Nuclei Test - 110

Result

Atoms and Nuclei Test - 110

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Question 1

Coulombic

Nuclear

Both

None of these

Question 2

N > Z

N = Z

N < Z

N ≥ Z

Solution

Question 3

M <[NMn + ZMp]

M >[NMn + ZMp]

M =[NMn + ZMp]

M n + ZMp]

Question 4

A3

A

A2/3

A1/3

Solution

Question 5

1.67 × 10–27gm, 9.30 MeV

1.67 × 10–27 kg, 930 MeV

1.67 × 10–27 kg, 1 MeV

1.67 × 10–34 kg, 1 MeV

Question 6

Two extra protons and two extra electrons

Two extra protons but no extra electrons

Two extra neutrons and no extra electrons

Two extra neutrons and two extra electrons

Solution

Question 7

10–14 m

10–10 m

10–12 m

10–8 m

Question 8

m <(A – Z)mn + Zmp

m = (A – Z)mn + Zmp

m = (A – Z)mp + Zmn

m >(A – Z)mn + Zmp

Solution

Question 9

1.5 × 106

2.5 × 106

3 × 106

7.5 × 106

Solution

Question 10

6C12

3Li6

3Li7

4Be9

Solution

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M <[NM_n + ZM_p]

M >[NM_n + ZM_p]

M =[NM_n + ZM_p]

M n + ZM_p]

A³

A^2/3

A^1/3

1.67 × 10^–27gm, 9.30 MeV

1.67 × 10^–27 kg, 930 MeV

1.67 × 10^–27 kg, 1 MeV

1.67 × 10^–34 kg, 1 MeV

10^–14 m

10^–10 m

10^–12 m

10^–8 m

m <(A – Z)m_n + Zm_p

m = (A – Z)m_n + Zm_p

m = (A – Z)m_p + Zm_n

m >(A – Z)m_n + Zm_p

1.5 × 10⁶

2.5 × 10⁶

3 × 10⁶

7.5 × 10⁶

₆C¹²

₃Li⁶

₃Li⁷

₄Be⁹