Semiconductor Devices Test

Result

Semiconductor Devices Test - 57

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Weekly Quiz Competition

Question 1
4 / -1

In the case of constants α and β of a transistor

A
α = β

B
β < 1, α > 1

C
α β = 1

D
β > 1, α < 1
Question 2
4 / -1

If l₁, l₂, l₃ are the lengths of the emitter, base and collector of a transistor, then

A
l₁ = l₂ = l₃

B
l₃ < l₂ > l₃

C
l₃ < l₁ < l₂

D
l₃ > l₁ > l₂
Question 3
4 / -1

In an NPN transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, the emitter current (i_E) and base current (i_B ) are given by

A
i_E = –1 mA, i_B = 9 mA

B
i_E = 9 mA, i_B = –1 mA

C
i_E = 1 mA, i_B = 11 mA

D
i_E = 11 mA, i_B = 1 mA

Solution
Question 4
4 / -1

Least doped region in a transistor

A
Either emitter or collector

B
Base

C
Emitter

D
Collector
Question 5
4 / -1

The transistors provide good power amplification when they are used in

A
Common collector configuration

B
Common emitter configuration

C
Common base configuration

D
None of the above
Question 6
4 / -1

The transfer ratio of a transistor is 50. The input resistance of the transistor when used in the common-emitter configuration is 1 k Ω. The peak value for an A.C input voltage of 0.01 V of collector current is

A
100 µA

B
0.01 mA

C
0.25 mA

D
500 µA

Solution
Question 7
4 / -1

For a transistor the parameter β = 99. The value of the parameter a is

A
0.9

B
0.99

C
1

D
9

Solution
Question 8
4 / -1

In a PNP transistor the base is the N-region. Its width relative to the P-region is

A
Smaller

B
Larger

C
Same

D
Not related
Question 9
4 / -1

A common emitter amplifier is designed with NPN transistor (α = 0.99). The input impedance is 1 k Ω and load is 10 k Ω. The voltage gain will be

A
9.9

B
99

C
990

D
9900

Solution
Question 10
4 / -1

The symbol given in figure represents

A
NPN transistor

B
PNP transistor

C
Forward biased PN junction diode

D
Reverse biased NP junction diode

Solution