Semiconductor Devices Test

Result

Semiconductor Devices Test - 79

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Weekly Quiz Competition

Question 1
4 / -1

Pure sodium (Na) is a good conductor of electricity because the 3s and 3p atomic bands overlap to form a partially filled conduction band. By contrast the ionic sodium chloride (NaCl) crystal is

A
Insulator

B
Conductor

C
Semiconductor

D
None of these
Question 2
4 / -1

Would there be any advantage to adding n-type or p-type impurities to copper

A
Yes

B
No

C
May be

D
Information is insufficient
Question 3
4 / -1

In the following common emitter circuit if β = 100, V_CE = 7V, V_BE = negligible, R_C = 2kΩ then I_B = ?

A
0.01 mA

B
0.04 mA

C
0.02 mA

D
0.03 mA

Solution
Question 4
4 / -1

When a battery is connected to a P-type semiconductor with a metallic wire, the current in the semiconductor (predominantly), inside the metallic wire and that inside the battery respectively is due to

A
Holes, electrons, ions

B
Holes, ions, electrons

C
Electrons, ions, holes

D
Ions, electrons, holes
Question 5
4 / -1

In circuit in following fig. the value of Y is

A
0

B
1

C
Fluctuates between 0 and 1

D
Indeterminate as the circuit can't be realized

Solution
Question 6
4 / -1

In the following circuit, a voltmeter V is connected across a lamp L . What change would occur in voltmeter reading if the resistance R is reduced in value?

A
Increases

B
Decreases

C
Remains same

D
None of these

Solution
Question 7
4 / -1

For given electric voltage signal DC value is

A
6.28 V

B
3.14 V

C
4 V

D
0 V

Solution
Question 8
4 / -1

When a silicon PN-junction is in forward biased condition with series resistance, it has knee voltage of 0.6 V. Current flow in it is 5 mA, when PN-junction is connected with 2.6V battery, the value of series resistance is

A
100 Ω

B
200 Ω

C
400 Ω

D
500 Ω

Solution
Question 9
4 / -1

In the following circuit the equivalent resistance between A and B is 4Q 6Q

A

B

C

D

Solution
Question 10
4 / -1

In the following circuit of PN-junction diodes D₁, D₂ and D₃ are ideal then i is

A
E/R

B
E/2R

C
2E/3R

D
Zero

Solution