Laws of Motion ...

Two masses M and M/2 are joined together by means of light inextensible string passed over a frictionless pulley as shown in the figure. When the bigger mass is released, the small one will ascend with an acceleration of

The pulleys and strings shown in the figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle θ should be

A block B is pushed momentarily along a horizontal surface with an initial velocity v. If μ is the coefficient of sliding friction between B and the surface, block B will come to rest after a time

A body is coming with a velocity of 72 kmh^-1 on a rough horizontal surface of coefficient of friction 0.5. If the acceleration due to gravity is 10 ms^-2 , find the minimum distance, it can be stopped.

In the arrangement shown in figure, the strings are light and inextensible. The surface over which blocks are placed is smooth. What is the acceleration of each block?

A block of mass 2 kg rests on a horizontal surface. If a horizontal force of 5 N is applied on the block, the frictional force on it is ( take, µ_k = 0.4 , µ_s = 0.5 )

In the given figure, the pulley is assumed massless and frictionless. If the friction force on the object of mass m is f, then its acceleration in terms of the force F will be equal to

A block moving on a surface with velocity 20 ms^-1 comes to rest because of surface friction over a distance of 40 m. The coefficient of dynamic friction is (take, g =10 ms^-2)

Two blocks of masses M and m are connected by a string passing over a pulley as shown in the figure. The downward acceleration of the block with mass m is