Laws of Motion ...

A mass M of 100 kg is suspended with use of strings A, B and C as shown in fig. where W is vertical wall and R is a rigid horizontal rod. The tension in string B is

A block A of mass 7 kg is placed on a frictionless table. A thread tied to it passes over a frictionless pulley and carries a body B of mass 3 kg at the other end. The acceleration of the system is (given g = 10 m /s²)

A horizontal force of 10 N is necessary to just hold a block stationary against a wall. The coefficient of friction between the block and wall is 0.2. The weight of the block is

Two masses M and M/2 are joined together by means of light inextensible string passed over a Frictionless pulley as shown in Fig. When the bigger mass is released, the small one will ascend with an acceleration of

In fig., block A is released from rest, when spring is at its natural unstretched length. For block B of mass M to leave contact with the ground at some stage, the minimum mass of A must be

Consider the system shown in Fig. the pulley and the string are light and all The surfaces are frictionless. The tension in the string is (take g =10 m/ s²)

In fig., the pulley P₁ is fixed and pulley P₂ is movable. If W₁= W₂ = 100 N, what is the angle AP₂ P₁ ? The pulleys are frictionless.

A simple pendulum of length I and mass of bob m is oscillating in a plane about a vertical line between angular limits – θ and +θ. For an angular displacement θ, the tension in the string having velocity v is

A constant force acts on a body of mass m at rest. The velocity V acquired in traversing a specific distance depends on m as

Four equal and parallel forces are acting on a rod, as shown in Fig., at distances of 20 cm, 40 cm, 60 cm and 80 cm respectively from one end of the rod. Under the influence of these forces, the rod, (neglecting its weight)