Rotational Motion Test

Result

Rotational Motion Test - 4

Score
-
out of -
Rank
-
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TIME Taken - -

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Question 1
1 / -0

In an arrangement four particles, each of mass 2 gram are situated at the coordinate points (3, 2, 0), (1, –1, 0), (0, 0, 0) and (–1, 1, 0). The moment of inertia of this arrangement about the Z-axis will be-

A
8 units

B
16 units

C
43 units

D
34 units

Solution

For particle 1 I_z = I_x + I_y
= mr_x² + mr_y²
= m(r_x² + r_y²)
= 2(3² + 2²) = 26 unit
For particle 2, m [1² + (–1)²] = 2 × (2) = 4 unit
For particle 3, m[1² + 1²] = 2 × (2) = 4 unit
For particle 4, m (0) = 0
Total inertia = 26 + 4 + 4 = 34 unit