Systems of Particles and Rotational Motion Test

Result

Systems of Particles and Rotational Motion Test - 39

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Question 1
4 / -1

A cylinder of mass M has length L that is √3 times its radius what is the ratio of its moment of inertia about its own axis and that about an axis passing through its centre and perpendicular to its axis?

A
1

B

C

D

Solution
Question 2
4 / -1

A thin uniform rod AB of mass M and length L is hinged at one end A to the horizontal floor. Initially it stands vertically. It is allowed to fall freely on the floor in the vertical plane. The angular velocity of the rod when its end B strikes the floor is ____

A

B

C

D

Solution
Question 3
4 / -1

If a is aerial velocity of a planet of mass M its angular momentum is

A
M

B
2 MA

C
A²M

D
AM²

Solution
Question 4
4 / -1

A wheel having moment of inertia 2 kg M² about its vertical axis, rotates at the rate of 60 rpm about this axis. The torque which can stop the wheels rotation in one minute will be..

A

B

C

D

Solution
Question 5
4 / -1

A wheel is rotating at 900 rpm about its axis. When power is cut off it comes to rest in 1 minute, the angular retardation in rad / sec is ___

A

B

C

D

Solution
Question 6
4 / -1

A wheel is subjected to uniform angular acceleration about its axis. Initially its angular velocity is zero. In the first two second it rotate through an angle θ₁, in the next 2 sec. it rotates through an angle θ₂, find the ratio θ₁/θ₂ =

A
1

B
2

C
3

D
4

Solution
Question 7
4 / -1

Where will be the centre of mass on combining two masses m and M (M > m)?

A
Towards m

B
Towards M

C
Between m and M

D
Anywhere
Question 8
4 / -1

Two spherical bodies of mass M and 5M and radii R and 2R respectively are released in free space with initial separation between their centres equal to 12R. If they attract each other due to gravitational force only, then the distance covered by the smaller body just before collision is

A
1.5R

B
2.5 R

C
4.5R

D
7.5 R

Solution
Question 9
4 / -1

In the HCl molecule, the separation between the nuclei of two atoms is about 1.27 Å (1Å = 10^–10 m). The approximate location of the centre of mass of the molecule, assuming the chlorine atom to be about 35.5 times massive as hydrogen is

A
1 Å

B
2.5 Å

C
1.24 Å

D
1.5 Å

Solution
Question 10
4 / -1

The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is 1.1 Å. Given mass of carbon atom is 12 a.m.u., and mass of oxygen atoms is 16 a.m.u. calculate the position of the centre of mass of the carbon monoxide molecule,

A
6.3 Å from the carbon atom

B
1 Å from the oxygen atom

C
0.63 Å from the carbon atom

D
0.12 Å from the oxygen atom

Solution