Systems of Part...

A circular thin disc of mass 2 kg has a diameter 0.2 m. Calculate its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc (in kg–m²)

The moment of inertia of a uniform ring of mass M and radius r about a tangent lying in its own plane is

The moment of inertia of a sphere of mass M and radius R about an axis passing through its centre is 2/5MR². The radius of gyration of the sphere about a parallel axis to the above and tangent to the sphere is

Radius of gyration of a body depends on

If solid sphere and solid cylinder of same radius and density rotate about their own axis, the moment of inertia will be greater for (L = R)

One circular ring and one circular disc, both are having the same mass and radius. The ratio of their moments of inertia about the axis passing through their centres and perpendicular to the planes, will be

Three rings each of mass M and radius R are arranged as shown in the figure. The moment of inertia of the system about YY’ will be

Consider a uniform square plate of side ‘a’ and mass ‘m’. The moment of inertia of this plate about an axis perpendicular to its plane and passing through one of its corners is

A disc is of mass M and radius r. The moment of inertia of it about an axis tangential to its edge and in plane of the disc or parallel to its diameter is

Radius of gyration of uniform thin rod of length L about an axis passing normally through its centre of mass is