Systems of Part...

The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with a velocity of 2 m/s without slipping is 32.8 J. The radius of gyration of the body is

A ring of radius 0.5 m and mass 10 kg is rotating about its diameter with angular velocity of 20 rad/s. Its kinetic energy

A sphere of mass 0.5 kg and diameter 1m rolls without sliding with a constant velocity of 5 m/s, calculate what is the ratio of the rotational K.E. to the total kinetic energy of the sphere

The moment of inertia of two freely rotating bodies A and B are I_A and I_B respectively. I_A > I_B and their angular momentum are equal. If K_A and K_B are their kinetic energies, then

. A thin hollow cylinder open at both ends
(i) Sliding without rolling
(ii) Rolls without slipping, with the same speed The ratio of kinetic energy in the two cases is

A body of moment of inertia of 3 kg–m² rotating with an angular velocity of 2 rad/sec has the same kinetic energy as a mass of 12 kg moving with a velocity of

If the angular momentum of a rotating body about a fixed axis is increased by 10%. Its kinetic energy will be increased by

A body is rolling down an inclined plane. If K.E. of rotation is 40% of K.E. in translatory state, then the body is a

A flywheel is in the form of solid circular wheel of mass 72 kg and radius of 0.5 m and it takes 70 r.p.m., then the energy of revolution is

A body having moment of inertia about its axis of rotation equal to 3 kg–m² is rotating with angular velocity equal to 3 rad/s. Kinetic energy of this rotating body is the same as that of body of mass 27 kg moving with a speed of