Gravitation Tes...

The depth d at which the value of acceleration due to gravity becomes 1/n times the value at the surface, is [R = radius of the earth]

If the density of a small planet is the same as that of earth, while the radius of the planet is 0.2 times that of the earth, the gravitational acceleration on the surfaceof that planet is

Let g be the acceleration due to gravity at earth\'s surface and K be the rotational kinetic energy of the earth. Suppose the earth\'s radius decreases by 2% keeping all other quantities same, then

A body weighs 500 N on the surface of the earth. How much would it weigh half way below the surface of the earth

The speed of earth\'s rotation about its axis is o). Its speed is increased to x times to make the effective acceleration due to gravity equal to zero at the equator.Then x is

If mass of a body is M on the earth surface, then the mass of the same body on the moon surface is

At what depth below the surface of the earth, acceleration due to gravity g will be half its value 1600 km above the surface of the earth

An object weighs 72 N on earth. Its weight at a height of R/2 from earth is

The angular velocity of the earth with which it has to rotate so that acceleration due to gravity on 60° latitude becomes zero is (Radius of earth = 6400 km. At the poles g = 10 ms^–2)

Assuming earth to be a sphere of a uniform density, what is the value of gravitational acceleration in a mine 100 km below the earth\'s surface (Given R = 6400 km)