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Gravitation Test - 76

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Gravitation Test - 76
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Weekly Quiz Competition
  • Question 1
    4 / -1
    Assuming the earth to have a constant density, point out which of the following curves show the variation of acceleration due to gravity from the centre of earth to the points far away from the surface of earth
    Solution

  • Question 2
    4 / -1
    The diagram showing the variation of gravitational potential of earth with distance from the centre of earth is
    Solution

  • Question 3
    4 / -1
    By which curve will the variation of gravitational potential of a hollow sphere of radius R with distance be depicted
    Solution

  • Question 4
    4 / -1
    A sphere of mass M and radius R2has a concentric cavity of radius R1 as shown in figure. The force fexerted by the sphere on a particle of mass m located at a distance r from the centre of sphere varies as (0 ≤ r ≤∞)

    Solution

  • Question 5
    4 / -1
    Which one of the following graphs represents correctly the variation of the gravitational field (F) with the distance (r) from the centre of a spherical shell of mass M and radius a?
    Solution

  • Question 6
    4 / -1
    Suppose, the acceleration due to gravity at the earth\'s surface is 10 m/s2 and at the surface of Mars it is 4.0 m /s2. A 60 kg passenger goes from the earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of figure best represents the weight (net gravitational force)of the passenger as a function of time.

    Solution

  • Question 7
    4 / -1
    The curves for potential energy (U) and kinetic energy (Ex) of a two particle system are shown in figure. At what points the system will be bound?

  • Question 8
    4 / -1
    The correct graph representing the variation of total energy (E), kinetic energy (K) and potential energy (U) of a satellite with its distance from the centre of earth is
    Solution

  • Question 9
    4 / -1
    A shell of mass M and radius R has a point mass m placed at a distance r from its centre. The gravitational potential energy U (r) vsr will be
    Solution

  • Question 10
    4 / -1

    Solution

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