Quantitative Aptitude Test

Result

Quantitative Aptitude Test - 1

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Question 1
4 / -1

A takes 2 hours more than B to cover a distance of 40 km. If A doubles his speed, he takes hours more than B to cover 80 km. To cover a distance of 90 km, how much time will B take travelling at his same speed?

A

B

C

D

Solution
Question 2
4 / -1

The LCM of the prime numbers between 1 to 12 is____.

A
1000

B
2020

C
2310

D
1010

Solution
Question 3
4 / -1

If 16 sec²⁡ θ − 40sec⁡ θ + 25 = 0 and θ is an acute angle, then what will be the value of tanθ?

A
3/4

B
4/5

C
4/3

D
3/5

Solution
Question 4
4 / -1

A
2702

B
5774

C
2706

D
2500

Solution
Question 5
4 / -1

If the number “741259 AB” is divisible by 40, then for the least value of A, the value of 5A + 3B is:

A
8

B
10

C
15

D
25

Solution

Given:

“741259AB” is divisible by 40

741259AB

Checking for 5:

The value of B has to be 0 or 5 to be divisible by 5

As it has to be divisible by 40, it has to be even. So, B has to be 0

Number becomes 741259A0

Now checking for 8:

Last 3 digits = 9A0

Dividing 9A0 by 8, A has to be 2 or 6 (as 1 will remains when 9 will be divided by 8) for it to be completely divisible by 8.
Question 6
4 / -1

Several litres of milk was drawn off a 27 litre container full of milk which was replaced by an equal amount of water. The same volume of the mixture was drawn off again and replaced with water. Finally, the container contained 12 litres of milk. How much milk was initially drawn?

A
8 litres

B
9 litres

C
10 litres

D
15 litres

Solution
Question 7
4 / -1

A rectangular plot is 122 m long and 88 m wide. It has a path 2 m wide all around it on the outside. Find the cost of constructing it at Rs. 2 per square meter.

A
Rs. 2117

B
Rs. 1712

C
Rs. 712

D
Rs. 856

Solution

Given:

Length of plot = 122 meters

Plot width = 88 meters

Width of path = 2 meters

Cost of construction of path = Rs 2 per square meter

Length = 122 m, Breadth = 88 m, Width = 2 m

Cost of the construction of the path = Rs 2 per sq m

Area of the rectangle = Length × breadth

Area of the path = Area of the plot including path – Area of the plot

Area of the path= (122 + 4) × (88 + 4) – 122 × 88 = 856 m2

∴ Cost of constructing = 856 × 2 is Rs 1712
Question 8
4 / -1

The length of the base of a triangle is 5/7 of the base of a parallelogram. The area of the triangle and the parallelogram is the same. Find the ratio of the respective heights of the triangle and the parallelogram.

A
5 : 3

B
7 : 5

C
14 : 5

D
21 : 10

Solution

∴ The required ratio of the respective heights of the triangle and the parallelogram is 14 ∶ 5.
Question 9
4 / -1

The mean of 8 observations is 25. The 7 observations are 30, 24, 27, 22, 18, 26, 32. What is the 8th observation?

A
20

B
21

C
22

D
23

Solution
Question 10
4 / -1

Internal bisector of ∠XYZ and ∠XZY of △XYZ meet each other at k. If ∠YKZ = 125^∘, then ∠YXZ is equal to:

A
55°

B
80°

C
65°

D
70°

Solution