Self Studies

Biology Test - 8

Result Self Studies

Biology Test - 8
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0

    Give the correct descending order of organisms with reference to their estimated number found in Amazon forest.

    (a) Plants

    (b) Invertebrates

    (c) Fishes

    (d) Mammals

    (e) Birds

    Choose the correct answer from the options given below

    Solution

    Insects count-2.5 million species
    Plants species-50,000
    Fishes- 3000
    Birds 1300
    Mammals 430

  • Question 2
    1 / -0

    Which of the following is the incorrect match with respect to vegetative propagules in the stem?

    Column I

    Column II

    1. Offset

    Water hyacinth

    2. Aerial

    Opuntia

    3. Rhizome

    Ginger

    4. Bulbil

    Bryophyllum

    Solution

    The natural methods of vegetative reproduction in stem include:

    1. Offsets: Short horizontal branch producing a cluster of leaves above and the clusters of roots below.

    e.g. Water hyacinth

    2. Aerials shoot: Each segment of the stem having at least one node can form new plants

    e.g. Opuntia

    3. Rhizome: It is the main underground perennial stem buds present on the nodes take part for the formation of the new aerial shoot during the favourable season of growth.

    e.g. Ginger

    4. Bulbils: these are large size fleshy buds which are specialized for vegetative propagation

    e.g. In agave bulbils are modified buds develop on the floral axis.

    Bryophyllum has adventitious buds arise from notches present at the margin of leaves that help in vegetative reproduction.

  • Question 3
    1 / -0

    The enzymes hexokinase which catalyses glucose to glucose-\(6\)-phosphate in glycolysis is inhibited by glucose-\(6\)-phosphate. This is an example of:

    Solution

    The enzymes hexokinase which catalyses glucose to glucose-6-phosphate in glycolysis is inhibited by glucose-\(6\)-phosphate. This is an example of feedback allosteric inhibition.Hexokinase is a protein that phosphorylates a six-carbon sugar, a hexose, to a hexose phosphate. In many tissues and creatures, glucose is the most significant substrate of hexokinases, and glucose \(6\)-phosphate the most significant item.Hexokinase has a high proclivity for glucose, the hexokinase is allosterically hindered by its item which is glucose-6-phosphate. At the point when the centralization of glucose-6-phosphate expands, it ties with the compound at its allosteric site and achieves the conformational change in the protein.

  • Question 4
    1 / -0

    The minimum number of meiotic divisions required to obtain 100 pollen grain of wheat is:

    Solution

    The minimum number of meiotic divisions required to obtain 100 pollen grain of wheat is 25.

    During sexual reproduction in angiosperms, meiosis occurs in microspore and megaspore mother cells. In one meiotic division, one microspore mother cell in the anther forms 4 microspores, each of which develops as a pollen grain. When there are 100 pollen grains, the meiotic divisions which will be required are \(\frac{100}{4}\) \(=25\). The number of meiotic divisions for 100 pollen grains is 25.

  • Question 5
    1 / -0

    If the head of the cockroach is removed, it may live forfew days because:

    Solution

    The nervous system of the cockroach is distributed very little in the head and most of the nervous system along the ventral part of the body of the cockroach. This is the reason cockroaches may live for few days even after removal of the head from the body.

    The nervous system of the cockroach is spread throughout the body. The head holds a bit of nervous system while the rest is situated along the ventral (belly-side) part of its body.

  • Question 6
    1 / -0
    \(\mathrm{O}_{2}\) dissociation curve of \(\mathrm{Hb}\) is:
    Solution

    \(\mathrm{O}_{2}\) dissociation curve of \(\mathrm{Hb}\) is Sigmoid.

    A sigmoid curve is obtained when the percentage saturation of haemoglobin with \(\mathrm{O}_{2}\) is plotted against the \(\mathrm{pO}_{2}\). This curve is called the Oxygen dissociation curve. The binding of oxygen with haemoglobin is primarily related to the partial pressure of \(\mathrm{O}_{2}\), the partial pressure of \(\mathrm{CO}_{2}\), hydrogen ion concentration and temperature are the other factors that can interfere with this binding.

  • Question 7
    1 / -0

    What are the cysts containing sticky gel-like substances in an ovary called?

    Solution

    The cysts containing sticky gel-like substances in an ovary called Cystadenomas.

    Cystadenomas can develop from cells on the outer surface of a woman's ovary. The cysts are many times filled with a thick and sticky gel or watery fluid. The cysts may become large, causing the woman pain.

  • Question 8
    1 / -0

    Phosphorous is a constituent of 

    A. Cell membrane

    B. Nucleic acids 

    C. cellwall 

    D.chlorophyll

    Solution

    Phosphorus is a constituent of cell membranes, certain proteins, all nucleic acids and nucleotides

  • Question 9
    1 / -0

    A thiobacillus is a group of bacteria helpful in carrying out _________.

    Solution

    Thiobacillus denitrificans is chemolithoautotrophic bacteria that denitrifies nitrate during oxidation of FeSX compounds.

    Denitrification is the process that converts nitrate to nitrogen gas, thus removing bioavailable nitrogen and returning it to the atmosphere. Dinitrogen gas (N2) is the ultimate end product of denitrification, but other intermediate gaseous forms of nitrogen existed.

  • Question 10
    1 / -0

    Expressed Sequence Tags (ESTs) refers to______.

    Solution

    Expressed Sequence Tags (ESTs) are DNA sequences (genes) that are expressed as mRNA for protein synthesis. These are used in the human genome project for gene mapping.

    Expressed sequence tags (ESTs) are fragments of mRNA sequences derived through single sequencing reactions performed on randomly selected clones from cDNA libraries. To date, over 45 million ESTs have been generated from over 1400 different species of eukaryotes.

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now