(A) Sodium carbonate is manufactured by Solvay process \(\Rightarrow\) (iv) of List-II.
Solvay process's reactions are as follows
In Solvay's process, first ammonia \(\left(\mathrm{NH}_3\right.\) ) reacts with \(\mathrm{CO}_2\) and \(\mathrm{H}_2 \mathrm{O}\) to give ammonium bicarbonate \(\left(\mathrm{NH}_4 \mathrm{H} \mathrm{CO}_3\right)\).
This bicarbonate react with \(\mathrm{N} \mathrm{aCl}\) to give sodium bicarbonate \((\mathrm{NaHCO})_3\) along with ammonium chloride \(\left(\mathrm{NH}_4 \mathrm{Cl}\right)\).
At last, \(\mathrm{NaH} \mathrm{CO}_3\) is heated to form sodium carbonate as major product.
\(\mathrm{NH}_3+\mathrm{CO}_2+\mathrm{H}_2 \mathrm{O} \rightarrow \mathrm{NH}_4 \mathrm{HCO}_3 \)
\(\mathrm{NH}_4 \mathrm{HCO}_3+\underset{\text { (Brine) }}{\mathrm{NaCl}} \rightarrow \mathrm{NaHCO}_3 \downarrow+\mathrm{NH}_4 \mathrm{Cl} \)
\(2 \mathrm{NaHCO}_3 \rightarrow \Delta_2 \rightarrow \underset{\text { Sodium carbonate }}{\mathrm{Na}_2 \mathrm{CO}_3}+\mathrm{CO}_2+\mathrm{H}_2 \mathrm{O}\)
(B) Titanium is purified by van-Arkel method \(\Rightarrow\) (iii) of List-II
van-Arkel method
Crude titanium \(\xrightarrow[\mathrm{I}_2]{\mathrm{780 \textrm {K }}} \mathrm{Til}_4(\mathrm{~g}) \xrightarrow{1800 \mathrm{~K}} \underset{\text { (Pure) }}{\mathrm{Ti}}+2 \mathrm{I}_2\)
(C) Chlorine is manufactured by Deacon process ⇒ (i) of List-II.
Deacon process
\(4 \mathrm{HCl}(\mathrm{g})+\underset{\text {[Air]}~~~~~~~~~~~~~\text{ 723k }~~~~~~~~~}{\mathrm{O}_2(\mathrm{~g}) \xrightarrow{\mathrm{CuCl}_2 \text { (catalyst) }}} \underset{\text { Chlorine gas }}{2 \mathrm{Cl}_2}+2 \mathrm{H}_2 \mathrm{O}(\mathrm{g})\)
(D) Sodium hydroxide is manufactured by Castner-Kellner cell \(\Rightarrow\)
(ii) of List-II.
Castner-Kellner cell reaction
Electrolyte used is brine, saturated \(\mathrm{NaCl}\) solution. Cathode \((\mathrm{Hg})\) :
\(\mathrm{Na}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Na} \xrightarrow{\mathrm{Hg}} \mathrm{Na} / \mathrm{Hg}\)
Anode (carbon): \(\mathrm{Cl}^{-}+\mathrm{e}^{-} \rightarrow \frac{1}{2} \mathrm{Cl}_2 \uparrow\)
\(2 \mathrm{Na} / \mathrm{Hg}+2 \mathrm{H}_2 \mathrm{O} \rightarrow \underset{\text { Sodium hydroxide }}{2 \mathrm{NaOH}}+2 \mathrm{Hg}+\mathrm{H}_2 \uparrow\)