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Mathematics Test - 50

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Mathematics Test - 50
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  • Question 1
    1 / -0

    In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

    Solution
    Total number of balls
    \(=(8+7+6)\)
    \(=21\)
    Let \(E=\) event that the ball drawn is neither red nor green
    = event that the ball drawn is blue \(\therefore n(E)=7\)
    \(\therefore P(E)=\frac{n(E)}{n(S)}=\frac{7}{21}=\frac{1}{3}\)
  • Question 2
    1 / -0

    How many Permutations of the letters of the word APPLE are there?

    Solution
    APPLE = 5 letters.
    But two letters PP is of same kind.
    Thus, required permutations,
    =5!/2!
    =120/2
    =60
  • Question 3
    1 / -0

    Two pipes A and B can fill a cistern in 3712minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after:

    Solution
    Let \(B\) be turned off after \(x\) minutes.
    Then, Part filled by \((A+B)\) in \(x\) min. \(+\) Part filled by \(A\) in \((30-x)\) min. \(=1\) \(\therefore x\left(\frac{2}{75}+\frac{1}{45}\right)+(30-x) \cdot \frac{2}{75}=1\)
    \(\Rightarrow \frac{11 x}{225}+\frac{(60-2 x)}{75}=1\)
    \(\Rightarrow 11 x+180-6 x=225\)
    \(\Rightarrow x=9\)
  • Question 4
    1 / -0

    Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

    Solution
    Here, \(\mathrm{S}=\{1,2,3,4, \ldots, 19,20\}\)
    Let \(E=\) event of getting a multiple of 3 or 5 \(=\{3,6,9,12,15,18,5,10,20\}\)
    \(\therefore P(E)=\frac{n(E)}{n(S)}=\frac{9}{20}\)
  • Question 5
    1 / -0
    \(\frac{d}{d x}\left(x^{2} e^{x} \sin x\right)=\)
    Solution
    \(\frac{d}{d x}\left(x^{2} e^{x} \sin x\right)=x^{2} \frac{d}{d x}\left(e^{x} \sin x\right)+e^{x} \sin x \frac{d}{d x}\left(x^{2}\right)\)
    \(=x e^{x}(2 \sin x+x \sin x+x \cos x)\)
  • Question 6
    1 / -0
    If \(y=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\ldots . .+\frac{x^{n}}{n !},\) then \(\frac{d y}{d x}=\)
    Solution
    \(y=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\ldots .+\frac{x^{n}}{n !}\)
    \(\left[(\log \tan x+1)+\frac{1}{\tan x \log \tan x}\right] \quad\)
    \(\frac{d y}{d x}+\frac{x^{n}}{n !}=1+x+\frac{x^{2}}{2 !}+\ldots+\frac{x^{n}}{n !}\) \(\frac{d y}{d x}=y-\frac{x^{n}}{n !}\)
  • Question 7
    1 / -0

    Find the average of first 97 natural numbers.

    Solution
    \(1^{\text {st }}\) Method:
    Average of \(1^{\text {st }}\) n natural number is given by \(=\frac{\left(\frac{|\mathrm{n} \times(\mathrm{n}+1)|}{2}\right)}{\mathrm{n}}\)
    Average of \(1^{\text {st }}\) 97 natural number is given by
    \[
    \left.\begin{array}{l}
    \left\{\frac{\left(\frac{|97 \times(97+1)|}{2}\right)}{97}\right\} \\
    =49
    \end{array}\right\}
    \]
    \(2^{\text {st }}\) Method:
    These numbers are in AP series so average \(=\frac{(\text { sum of corresponding term })}{2}\)
    \(=\frac{(1+97)}{2}=49\)
    or \(, \frac{(2+96)}{2}=49\)
    or \(, \frac{(3+95)}{2}=49\)
    And so on.
  • Question 8
    1 / -0

    If sin (90−θ)  + cosθ  = √2cos(90−θ), then the value of cosecθ is?

    Solution
    \(\sin \left(90^{\circ}-\theta\right)+\cos \theta=\sqrt{2} \cos \left(90^{\circ}-\theta\right)\)
    \(\Rightarrow \cos \theta+\cos \theta=\sqrt{2} \sin \theta\)
    \(\Rightarrow \frac{2 \cos \theta}{\sin \theta}=\sqrt{2}\)
    \(\Rightarrow \cot \theta=\frac{1 \rightarrow B}{\sqrt{2} \rightarrow P}\)
    So, \(\mathrm{H} \rightarrow\)
    \(\therefore \operatorname{cosec} \theta=\frac{\mathrm{H}}{\mathrm{P}}=\frac{\sqrt{3}}{\sqrt{2}}\)
    \(=\sqrt{\frac{3}{2}}\)
  • Question 9
    1 / -0

    log√8/log8 is equal to:

    Solution
    \(\frac{\log \sqrt{8}}{\log 8}=\frac{\log (8)^{\frac{1}{2}}}{\log 8}\)
    \(=\frac{\frac{1}{2} \log 8}{\log 8}\)
    \(=\frac{1}{2}\)
  • Question 10
    1 / -0
    \(\frac{d}{d x} \log (\log x)=\)
    Solution
    \(\frac{d}{d x} \log (\log x)=\frac{1}{x} \cdot \frac{1}{\log x}=(x \log x)^{-1}\)
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