Chemistry Test

Result

Chemistry Test - 19

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Which of the following is a repeating unit of synthetic rubber?

A
PVC

B
Chloroprene

C
Neoprene

D
Vinyl cyanide

Solution

Synthetic rubber can be made from the polymerization of a variety of monomers including isoprene (2-methyl-1,3-butadiene), 1,3-butadiene, chloroprene (2-chloro-1,3-butadiene), and isobutylene (methylpropene) with a small percentage of isoprene for cross-linking.
Question 2
1 / -0

Formation of terylene is an example of

A
condensation polymerisation

B
addition polymerisation

C
esterification

D
saponification

Solution

Terylene (a polyester) is formed by condensation polymerization and the structure of Terylene represented as

This is the same kind of 'ester linkage' (-COOC-) found in fats which are combination of long chain fatty carboxylic acids and glycerol (alcohol with 3 -OH groups, a 'triol').
Question 3
1 / -0

Dacron is a polymer of

A
glycol and formaldehyde

B
glycol and phenol

C
glycol and phthalic acid

D
glycol and terepthalic acid

Solution

Dacron is synthesized by transesterification of two monomers: Ethylene glycol and Dimethyl terephthalate.
Question 4
1 / -0

Which of the following elements is present in teflon?

A
C

B
Cl

C
F

D
Br

Solution

Fluorine is present in teflon. Teflon has the following structure:
Question 5
1 / -0

The various processes, involved in the extraction of metals from their ores and refining, are known as

A
metallurgy

B
cosmology

C
chemotherapy

D
None of these

Solution

The Process of Extraction of Metals from their Ores and refining them is known as Metallurgy.
Question 6
1 / -0

A
16.761

B
26.383

C
13.260

D
23.484

Solution
Question 7
1 / -0

A
0.0072 mol L^-1 s^-1

B
0.0288 mol L^-1s^-1

C
0.0072 mol L^-1s^-1

D
0.0144 mol L^-1 s^-1

Solution
Question 8
1 / -0

The rate of a reaction can be increased in general by all the factors except by

A
using a catalyst

B
increasing temperature

C
increasing the activation energy

D
increasing the concentration of reactant

Solution

This option is correct because, it is the minimum amount of energy required by reactant molecule to get converted into product. Hence this option is correct.
Question 9
1 / -0

The concentration of reactant changes from 0.06 mol L^-1to 0.05 mol L^-1 in 25 minutes. Calculate the average rate of reaction.

A
4 x 10^-4mol L^-1min^-1

B
- 4 x 10^-4mol L^-1 min^-1

C
0.04 mol L^-1 min^-1

D
- 0.04 mol L^-1 min^-1

Solution

This option is correct because, rate of reaction is given by, Rate = - (change in concentration of reactants) / time. ( 0.06 - 0.05) / 25 = 4 x 10^-4 mol L^-1 min ^-1. Hence this option is correct.
Question 10
1 / -0

5A→ 2B

If there were 1.5 moles of 'A' 2 L solution in the beginning of the reaction, what is the concentration of 'B' when 'A' is 20% consumed?

A
0.75 M

B
0.06 M

C
0.15 M

D
0.03 M

Solution
Question 11
1 / -0

The rate constants were found to be K₁and K₂, when a reaction was carried out at 310 K and 290 K respectively.
The two rate constants are related as:

A
K₂ = 0.25 K₁

B
K₂ = 4 K₁

C
K₁ = 2 K₂

D
K₂ = 2 K₁

Solution

This option is correct because for every 10 degree rise in temprature, rate constant doubles.
Aince, T₁ = T₂ + 20
Hence, K₁ = 4 K₂
=> K₂ = 0.25 K₁
Hence, this option is correct.
Question 12
1 / -0

R₁ is the rate of a simple reaction, 2NO + O₂ 2NO₂.

If the volume of the reaction vessel is doubled, the rate of the reaction becomes

A
(1/8)R₁

B
8R₁

C
R₁

D
(1/2)R₁

Solution
Question 13
1 / -0

Which of the following covalent bonds has the highest ionic character?

A
H-Cl

B
H-NH₂

C
H-OH

D
H-SH

Solution

Among the given options, the difference in electronegativity between the H and O is the highest. So, this bond will have the highest ionic character.
Question 14
1 / -0

Which of the following statements correctly represents one of the characteristic of the lanthanides?

A
Most of the their ions are coloured.

B
They have greater tendency towards complex formation.

C
Their compounds are more basic.

D
They are generally non radioactive

Solution

This is correct as except promethium, lanthanides are non radioactive.
Question 15
1 / -0

Which of the following statements is correct about potassium permanganate?

A
It acts as strong reducing agent.

B
It is not suitable to be used in volumetric analysis.

C
It is used as a disinfectant

D
In it, four oxygen atoms are arranged in square planar arrangment.

Solution

Potassium permanganate is also widely used as a disinfectant and germicide.

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Chemistry Test - 19

Result

Chemistry Test - 19

Score

-

Rank

-

SHARING IS CARING

Question 1

PVC

Chloroprene

Neoprene

Vinyl cyanide

Solution

Question 2

condensation polymerisation

addition polymerisation

esterification

saponification

Solution

Question 3

glycol and formaldehyde

glycol and phenol

glycol and phthalic acid

glycol and terepthalic acid

Solution

Question 4

C

Cl

F

Br

Solution

Question 5

metallurgy

cosmology

chemotherapy

None of these

Solution

Question 6

16.761

26.383

13.260

23.484

Solution

Question 7

0.0072 mol L-1 s-1

0.0288 mol L-1 s-1

0.0072 mol L-1 s-1

0.0144 mol L-1 s-1

Solution

Question 8

using a catalyst

increasing temperature

increasing the activation energy

increasing the concentration of reactant

Solution

Question 9

4 x 10-4mol L-1min-1

- 4 x 10-4 mol L-1 min-1

0.04 mol L-1 min-1

- 0.04 mol L-1 min-1

Solution

Question 10

0.75 M

0.06 M

0.15 M

0.03 M

Solution

Question 11

K2 = 0.25 K1

K2 = 4 K1

K1 = 2 K2

K2 = 2 K1

Solution

Question 12

(1/8)R1

8R1

R1

(1/2)R1

Solution

0.0072 mol L^-1 s^-1

0.0288 mol L^-1s^-1

0.0072 mol L^-1s^-1

0.0144 mol L^-1 s^-1

4 x 10^-4mol L^-1min^-1

- 4 x 10^-4mol L^-1 min^-1

0.04 mol L^-1 min^-1

- 0.04 mol L^-1 min^-1

K₂ = 0.25 K₁

K₂ = 4 K₁

K₁ = 2 K₂

K₂ = 2 K₁

(1/8)R₁

8R₁

R₁

(1/2)R₁

H-NH₂