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Chemistry Test - 7

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Weekly Quiz Competition

Question 1
1 / -0

Lanthanides are

A
14 elements in the sixth period (atomic no. = 90 to 103) that are filling 4f sub-level

B
14 elements in the seventh period (atomic no. = 90 to 103) that are filling 5f sub-level

C
14 elements in the sixth period (atomic no. = 58 to 71) that are filling 4f sub-level

D
14 elements in the seventh period (atomic no. = 58 to 71) that are filling 4f sub-level

Solution

The lanthanide series comprises the fifteen metallic chemical elements with atomic numbers 57 through 71, from lanthanum through lutetium. These fifteen elements, along with the chemically similar elements scandium and yttrium, are often collectively known as the rare earth elements.
Question 2
1 / -0

Which of the following gases is evolved on heating ammonium dichromate?

A
Oxygen

B
Ammonia

C
Nitrous oxide

D
Nitrogen

Solution

Nitrogen gas is evolved as the following reaction takes place:
(NH₄)₂ Cr₂O₇ Cr₂O₂ + N₂ + 4H₂O
Question 3
1 / -0

Excited state configuration of Mn²⁺ is

A
t₂g⁵

B
t₂g³eg²

C
t₂g⁴eg²

D
t₂g⁵eg⁰

Solution

The configuration for Mn is [Ar] 4s²3d⁵. In the excited state, the distribution of electrons in d orbitals is shown as t₂g³eg².
Question 4
1 / -0

Which of the following reagents cannot be used to identify nickel ion?

A
Resorcinol

B
Dimethyl glyoxime

C
Diphenyl benzidine

D
Potassium ferrocynide

Solution

Besides diphenyl benzidine, all other chemicals can be used to identify nickel ion.
Question 5
1 / -0

Vanadium (III) oxide is a strong _________.

A
drying agent

B
oxidizing agent

C
reducing agent

D
wetting agent

Solution

Vanadium (III) oxide acts as a strong reducing agent in many type of reactions due to strong reducing nature of V³⁺ ions.
Question 6
1 / -0

The correct order for the wavelengths of absorption of the complexes of nickel in the visible region is

A
[Ni(NO₂)₆]^4- < [Ni(NH₃)₆]²⁺ < [Ni(H₂O)₆]²⁺

B
[Ni(NO₂)₆]^4- < [Ni(NH₃)₆]²⁺ < [Ni(NH₃)₆]²⁺

C
[Ni(H₂O)₆]²⁺ < [Ni(NH₃)₆]²⁺ < [Ni(NO₂)₆]^4-

D
[Ni(NH₃)₆]²⁺ < [Ni(H₂O)₆]²⁺ < [Ni(NO₂)₆]^4-

Solution

The order of the ligands in terms of splitting caused by them (Spectrochemical series) is H₂O < NH₃ < NO₂.
Greater the octahedral splitting, higher will be the energy barrier created for the electrons showing the d-d transitions, and shorter the wavelength of the light adsorbed.
The correct order of the wavelengths of absorption of complexes of nickel in the visible region is [Ni(NO₂)₆]^4- < [Ni(NH₃)₆]²⁺ < [Ni(H₂O)₆]²⁺.
Question 7
1 / -0

One mole of a complex compound Co(NH₃)₅Cl₃ gives 3 moles of ions on disssolution in water. One mole of the same complex reacts with two moles of AgNO₃ solution to yield two moles of AgCl (s). The structure of the

A
[Co(NH₃)₅Cl]Cl₂

B
[Co(NH₃)₃Cl₂].2NH₃

C
[Co(NH₃)₄Cl₂]Cl.NH₃

D
[Co(NH₃)₄Cl]Cl₂.NH₃

Solution
Question 8
1 / -0

The number of unpaired electrons in the complexion [CoF₆]^3- (Atomic number Co = 27) is

A
4

B
3

C
2

D
0

Solution

Valence shell electronic configuration of Co(27) = [Ar] 3d⁷, 4s²
Valence shell electronic configuration of Co³⁺(24) = [Ar] 3d⁶, 4s⁰
The number of unpaired electrons in the complex ion [CoF₆]^3- is 4.
Question 9
1 / -0

Assign the hybridization, shape and magnetic moment of K₂[Cu (CN)₄].

A
sp³, tetrahedral, 1.73 BM

B
dsp², square planar, 1.73 BM

C
sp³, tetrahedral, 2.44 BM

D
dsp², square planar, 2.44 BM

Solution

In this complex copper is in +2 oxidation state. Cu²⁺ has electronic configuration is [Ar] 3d⁹ 4s⁰. So in this compound copper undergo dsp² hybridization to give square planar structure. Since Cu²⁺ has only one unpaired electron so using, √[n(n+2)] the dipole moment comes out to be 1.73 BM.
Question 10
1 / -0

In the complexes [Fe(CN)₆]^3- and [Fe(C2O4)₃]^3-, the respective coordination numbers of Iron is

A
6 and 3

B
3 and 3

C
6 and 6

D
3 and 6

Solution

In both the complex the coordination of iron is 6 each.
Question 11
1 / -0

Directions: Consider the following reaction.

CH₃CHO+HCN→CH₃CH(OH)CN (in presence of HOH)→CH₃CH(OH)COOH

In this reaction, an asymmetric center is generated. The acid obtained would be

A
50% D + 50% L - isomer

B
20% D + 80% L - isomer

C
D - isomer

D
L - isomer

Solution

The carbonyl carbon being sp^2-hybridised has a planar arrangement of threeσ bonds and the nucleophile (here CN^-) can attack from both sides.

Hence, the product formed is a 50% - 50% mixture of both enantiomers i.e., a racemic mixture is obtained.

Therefore, 50% of molecules (lactic acid) will have the D-configuration and 50% will have the L-configuration.
Question 12
1 / -0

Which of the following is optically active?

A
Butane

B
4-Methylheptane

C
3-Methylheptane

D
2-Methylheptane

Solution

Optical activity occurs in chiral (asymmetrical) molecules, because the mirror image is different from the original one, which is the course for the optical activity measured. 3-Methylheptane is an optically active compound.
Question 13
1 / -0

How many chiral carbon atoms are present in 2, 3, 4−trichloropentane?

A
one

B
two

C
three

D
four

Solution
Question 14
1 / -0

A compound whose molecules are super imposable on their mirror images, even when they contain asymmetric carbon atoms is called

A
a meso compound

B
an erythro isomer

C
a threo isomer

D
a glycol

Solution

A compound whose molecules are super imposable on their mirror images, even when they contain asymmetric carbon atoms is called a meso compound.
Question 15
1 / -0

Which of the following exhibits stereo isomerism?

(a) 1, 2 - dichloroethylene (b) 2 - hydroxy propanoic acid

(c) 1, 1 - dichloroethylene (d) 2 - methyl propane

A
(a) and (d)

B
(b) and (d)

C
(a) and (b)

D
(c) and (d)

Solution

1,2-dichloroethylene (Cl)HC=CH(Cl) shows cis-trans isomerism whereas 2-hydroxy propanoic acid (CH3CH(OH)COOH) shows optical activity.

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Chemistry Test - 7

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Chemistry Test - 7

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Question 1

14 elements in the sixth period (atomic no. = 90 to 103) that are filling 4f sub-level

14 elements in the seventh period (atomic no. = 90 to 103) that are filling 5f sub-level

14 elements in the sixth period (atomic no. = 58 to 71) that are filling 4f sub-level

14 elements in the seventh period (atomic no. = 58 to 71) that are filling 4f sub-level

Solution

Question 2

Oxygen

Ammonia

Nitrous oxide

Nitrogen

Solution

Question 3

t2g5

t2g3eg2

t2g4eg2

t2g5eg0

Solution

Question 4

Resorcinol

Dimethyl glyoxime

Diphenyl benzidine

Potassium ferrocynide

Solution

Question 5

drying agent

oxidizing agent

reducing agent

wetting agent

Solution

Question 6

[Ni(NO2)6]4- < [Ni(NH3)6]2+ < [Ni(H2O)6]2+

[Ni(NO2)6]4- < [Ni(NH3)6]2+ < [Ni(NH3)6]2+

[Ni(H2O)6]2+ < [Ni(NH3)6]2+ < [Ni(NO2)6]4-

[Ni(NH3)6]2+ < [Ni(H2O)6]2+ < [Ni(NO2)6]4-

Solution

Question 7

[Co(NH3)5Cl]Cl2

[Co(NH3)3Cl2].2NH3

[Co(NH3)4Cl2]Cl.NH3

[Co(NH3)4Cl]Cl2.NH3

Solution

Question 8

4

3

2

0

Solution

Question 9

sp3, tetrahedral, 1.73 BM

dsp2, square planar, 1.73 BM

sp3, tetrahedral, 2.44 BM

dsp2, square planar, 2.44 BM

Solution

Question 10

6 and 3

3 and 3

6 and 6

3 and 6

Solution

Question 11

50% D + 50% L - isomer

20% D + 80% L - isomer

D - isomer

L - isomer

Solution

Question 12

Butane

4-Methylheptane

3-Methylheptane

2-Methylheptane

Solution

t₂g⁵

t₂g³eg²

t₂g⁴eg²

t₂g⁵eg⁰

[Ni(NO₂)₆]^4- < [Ni(NH₃)₆]²⁺ < [Ni(H₂O)₆]²⁺

[Ni(NO₂)₆]^4- < [Ni(NH₃)₆]²⁺ < [Ni(NH₃)₆]²⁺

[Ni(H₂O)₆]²⁺ < [Ni(NH₃)₆]²⁺ < [Ni(NO₂)₆]^4-

[Ni(NH₃)₆]²⁺ < [Ni(H₂O)₆]²⁺ < [Ni(NO₂)₆]^4-

[Co(NH₃)₅Cl]Cl₂

[Co(NH₃)₃Cl₂].2NH₃

[Co(NH₃)₄Cl₂]Cl.NH₃

[Co(NH₃)₄Cl]Cl₂.NH₃

sp³, tetrahedral, 1.73 BM

dsp², square planar, 1.73 BM

sp³, tetrahedral, 2.44 BM

dsp², square planar, 2.44 BM