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Physics Test - 13

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Physics Test - 13
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  • Question 1
    1 / -0

    The binary representation of hexadecimal number C3 is

    Solution

    To convert C3 into hexadecimal, we will write down the respective values of C 12 and 3 into 4-digit binary form.

    12 - 1100

    3 - 0011

    Hence, C3 - 11000011

  • Question 2
    1 / -0

    The value of 25 in octal system is

    Solution

    25 = (32)10

    (32)10 = (40)8

  • Question 3
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    NAND and NOR gates are called 'Universal' gates primarily because:

    Solution

    A universal gate is a gate that can implement any Boolean function without the need to use any other gate type. The NAND and NOR gates are universal gates. They can be combined to produce AND, OR and NOR gate.

    (i) NOR gates can be converted into the NOT gate by just connecting the inputs of a NOR gate. As a NOR gate is equivalent to an OR gate leading to NOT gate, this is automatically seen to the OR part of the NOR gate, eliminating it from consideration and leaving only the NOT part.

    (ii) To convert the NOR into the OR gate, connect by just connecting the NOT gate followed to the NOR gate. As a result, outputs of this gate are opposite to that of the OR gate when the inputs are kept the same.

    (iii) An AND gate gives the output as 1 when both of its inputs are 1. Therefore, an AND gate is made by inverting the inputs of a NOR gate.

    (iv) A NAND gate can be converted into the NOT gate, by just connecting the inputs of NAND gates together.

    (v) Not only AND, OR, and NOT gates, we can also combine the NAND gates to perform the EX-OR and NOR operations too.

  • Question 4
    1 / -0

    The expression for exclusive NOR gate is

    Solution

    Truth table of EX - NOR Gate is

    Hence only option 2 satisfies.

  • Question 5
    1 / -0

    Solution

  • Question 6
    1 / -0

    An AND gate has four inputs A, B, C, D. The input that produces an output 1 is

    Solution

    An AND gate always produces an output 1, only when all the inputs are 1.

  • Question 7
    1 / -0

    Solution

    We can check from options and only option 2 satisfies the given truth table.

  • Question 8
    1 / -0

    If the position of the resultant of two like parallel forces P and Q is unaltered, when the positions of P and Q are interchanged, then

    Solution

  • Question 9
    1 / -0

    A particle moves towards east from a point A to a point B at the rate of 4 km/h and then towards north from B to C at rate of 5 km/h. If AB = 12 km and BC = 5 km, then its average speed for its journey from A to C and resultant average velocity direct from A to C respectively are

    Solution

  • Question 10
    1 / -0

    Solution

  • Question 11
    1 / -0

    With two forces acting at a point, the maximum effect is obtained when their resultant is 4N. If they act at right angles, then their resultant is 3N. Then the forces are

    Solution

  • Question 12
    1 / -0

    ​​​​​​​

    Solution

  • Question 13
    1 / -0

    The difference in the variation of resistance with temperature in a metal and a semiconductor arises essentially due to the difference in the

    Solution

    There are different charge carriers in case of a metal and a semiconductor. Resistance depends upon the number of charge carriers present. So, resistance variation is there due to charge carrier variation.

  • Question 14
    1 / -0

    Consider the following two statements A and B, and identify the correct answer.

    A: During amplification, the frequency of the signal is increased.

    B: The voltage gain is more in common base transistor amplifier than in common emitter transistor amplifier.

    Solution

  • Question 15
    1 / -0

    A transistor is operated in common emitter configuration at constant collector voltage Vc = 1.5 V such that a change in the base current from 100 µA to 150 µA produces a change in the collector current from 5 mA to 10 mA. The current gain (b) is

    Solution

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