Quantitative Aptitude Test - 12

In first solution of syrup quantity of water = 15%

In second solution syrup quantity of water = 35%

Let, x litres of first solution must be added.

According to the question,

Total litres of first solution×15% water +Total litres of second solution × 35% water = (Total litres of first solution +Total litres of second solution)× 23% water

⇒ \(x \times(\frac{15}{100})+40 \times(\frac{35}{100})=(x+40) \times(\frac{23}{100})\)

\(\Rightarrow 0.15 x+14=0.23 x+9.2\)\(\Rightarrow x=60\)

Given,

Raktim can complete \(\frac{7}{16}\) part of a work in = \(21\) days

Raktim and Puja can complete the remaining work together in = \(18\) days

Let Raktim and Puja together can complete the total work in X days.

Remaining work \(=(1-\frac{7}{16})=\frac{9}{16}\)

Raktim and Puja can do the remaining work together in \(18\) days.

Raktim and Puja 1 day's work \(=\frac{9}{(16 \times 18)}=\frac{1}{ 32}\)

Raktim and Puja can complete the total work together in = \(32\) days

∴ Time needed to complete the remaining work is \(32\) days.

From statement I:

\(\frac{\text { Height of cone }}{\text { Height of the cylinder }}=\frac{5}{8}\)

Statement I alone is not sufficient to answer the question.

From statement II:

Area of the square = 144 cm²

⇒ Side of the square = 12 cm

Perimeter of the square = 12 × 4 = 48 cm

⇒ Height of the cylinder = 2 × 48 = 96 cm

Statement II alone is not sufficient to answer the question.

From statement III:

Diameter of the cone = 3 × breadth of the rectangle

Perimeter of the rectangle = 2 × (l + b) = 84 cm

∵ Breadth cannot be determined.

⇒ Statement III alone is not sufficient to answer the question.

If we combine all the statements, we can determine the height of the cone but not the radius or the slant height.

∴ None statement is sufficient to answer.

Hence, the correct option is (E).

Total number of shoes sale in Kanpur and Mumbai = 350 + 550 = 900

Total number of shoes sale in Allahabad and Delhi = 800 + 900 = 1700

∴ Required percentage \(= \frac{900 }{1700} \times 100= 52.94\%\)

Total sale of Kanpur store for two year = 200 + 150 = 350

Total sale of Mumbai store for two year = 250 + 300 = 550

∴ Ratio \(= \frac{350}{ 550} = 0.636\)

Average sale of all four year in 2014 \(=\frac{1250}{ 4}=312.5\)

Average sale of all four year in 2015 \(=\frac{1350}{4}=337.5\)

\(\therefore\) Required ratio is \(=\frac{312.5}{337.5}=0.926\)

Average sales of shoes in delhi, Kanpur, Mumbai \(=\frac{1800}{3}=600\)

Average sales of shoes in Allahabad, Kanpur, delhi \(=\frac{2050}{3}=683.33\)

\(\therefore\) Required percentage\(= \frac{600 }{683.33} \times 100= 87.80\%\)

In 2014 total sale in delhi and Mumbai \(=500+250=750\)

In 2015 total sale in delhi and Mumbai \(=400+300=700\)

\(\therefore\) Required percentage\(= \frac{700 }{750} \times 100= 93.33\%\)

Given:

\(55-[13+\{12 \div(8-2)\}] \times 10 \div 3=?\)

\(\Rightarrow 55-[13+\{12 \div 6\}] \times 10 \div 3=?\)

\(\Rightarrow 55-[13+2] \times 10 \div 3=?\)

\(\Rightarrow 55-15 \times 10 \div 3=?\)

\(\Rightarrow 55-15 \times 10 \times \frac{1 }{ 3}=?\)

\(\Rightarrow 55-50=5\)

Given:

\(25 \times 40+20 \div ?=1020\)

\(\Rightarrow 1000+(\frac{20}{?})=1020\)

\(\Rightarrow \frac{20}{?}=1020-1000\)

\(\Rightarrow \frac{20 }{?}=20\)

\(\Rightarrow ?=\frac{20}{20}\)

\(\Rightarrow ?=1\)

\(\therefore 1\) will come in place of the question mark ('?').