Quantitative Aptitude Test

Result

Quantitative Aptitude Test - 2

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Directions For Questions

Direction: In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

...view full instructions

I. 3x² – 2 $\sqrt{21}$ x + 7 = 0

II. 3y² + $\sqrt{3}$ y – 2 = 0

A
x > y

B
x < y

C
x ≥ y

D
x ≤ y

E
x = y or relationship between x and y cannot be established

Solution

Question 2

1 / -0

Directions For Questions

Direction: In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.

...view full instructions

I. 2x² + 5x – 250 = 0

II. 7y² – 22y + 3 = 0

x > y

x < y

x ≥ y

x ≤ y

x = y or relationship between x and y cannot be established

Solution

I. 2x² + 5x – 250 = 0

⇒ 2x² – 20x + 25x – 250 = 0

⇒ 2x(x – 10) + 25(x – 10) = 0

⇒ (2x + 25) (x – 10) = 0

⇒ x = $\frac{- 25}{2}$ , 10

II. 7y² – 22y + 3 = 0

⇒ 7y² – 21y – y + 3 = 0

⇒ 7y(y – 3) – 1(y – 3) = 0

⇒ (7y – 1) (y – 3) = 0

⇒ y = $\frac{1}{7}$ , 3

Value of x	Value of y	Relation
$\frac{- 25}{2}$	$\frac{1}{7}$	x < y
$\frac{- 25}{2}$	3	x < y
10	$\frac{1}{7}$	x > y
10	3	x > y

So, the relationship between x and y cannot be established.

Question 3
1 / -0

One card is drawn from a pack of $52$ cards, each of the $52$ cards being equally likely to be drawn find the probability the card drawn is black.

A
$\frac{1}{2}$

B
$\frac{2}{3}$

C
$\frac{3}{4}$

D
$\frac{2}{5}$

E
$\frac{1}{8}$

Solution

As we know,
When one card is drawn from a pack of $52$ cards.
The numbers of possible outcomes $\mathrm{n}(\mathrm{s})=52$
We know that there are 26 black cards in the pack of $52$ cards.
The numbers of favorable outcomes $\mathrm{n}(\mathrm{E})=26$
Probability of occurrence of an event $P(E)=\frac{\text { Number of favorable outcomes }}{\text { Numeber of possible outcomes }}=\frac{n(E)}{n(S)}$
$\therefore$ Required probability $=\frac{26 }{ 52}=\frac{1 }{2}$
Question 4
1 / -0

Directions For Questions

Direction:The following line graph gives the annual percent profit earned by a Company during the period 1995 - 2000.

...view full instructions

If the expenditures in 1996 and 1999 are equal, then the approximate ratio of the income in 1996 and 1999 respectively is:

A
1:1

B
2:3

C
13:14

D
9:10

E
11:12

Solution

Let the expenditure in 1996 = x

Also, let the incomes in 1996 and 1999 be $I_{1}$ and $I_{2}$ respectively.

Then,

For the year 1996, we have:

$55=\frac{I_{1}-x}{x} \times 100 $

$\Rightarrow \frac{55}{100}=\frac{I_{1}}{x}-1$

$ \Rightarrow I_{1}=\frac{155 x}{100} \ldots$ (i)

For the year 1999, we have:

$70=\frac{I_{2}-x}{x} \times 100 $

$\Rightarrow \frac{70}{100}=\frac{I_{2}}{x}-1$

$ \Rightarrow I_{2}=\frac{170 x}{100} \ldots \text {... (ii) }$

From equation (i) and (ii), we get:

$\frac{I_{1}}{I_{2 }}=\frac{\left(\frac{155 x}{100}\right)}{(\frac{170 x}{100})}$

$\Rightarrow \frac{I_{1}}{I_{2 }}=\frac{155}{170}$ $ \approx \frac{0.91}{1} $ $\approx 9: 10$
Question 5
1 / -0

Directions For Questions

Direction:The following line graph gives the annual percent profit earned by a Company during the period 1995 - 2000.

...view full instructions

If the income in 1998 was Rs. 264 crores, what was the expenditure in 1998?

A
Rs. 104 crores

B
Rs. 145 crores

C
Rs. 160 crores

D
Rs. 185 crores

E
Rs. 180 crores

Solution

Given,

The income in 1998 was Rs. 264 crores

Let the expenditure is 1998 be Rs. $x$ crores.

Then,

$65=\frac{264-x}{x} \times 100$

$\Rightarrow \frac{65}{100}=\frac{264}{x}-1$

$\Rightarrow x=\frac{264 \times 100}{165}$

$=160$

$\therefore$ Expenditure in $1998=$ Rs. 160 crores.
Question 6
1 / -0

Directions For Questions

Direction:The following line graph gives the annual percent profit earned by a Company during the period 1995 - 2000.

...view full instructions

In which year is the expenditure minimum?

A
2000

B
1997

C
1996

D
1998

E
Cannot be determined

Solution

The line-graph gives the comparison of percent profit for different years but the comparison of the expenditures is not possible without more data. Therefore, the year with minimum expenditure cannot be determined.
Question 7
1 / -0

Directions For Questions

Direction:The following line graph gives the annual percent profit earned by a Company during the period 1995 - 2000.

...view full instructions

If the profit in 1999 was Rs. 4 crores, what was the profit in 2000?

A
Rs. 4.2 crores

B
Rs. 6.6 crores

C
Rs. 6.8 crores

D
Rs. 7.6 crores

E
Cannot be determined

Solution

From the line-graph we obtain information about the percentage profit only. To find the profit in 2000 we must have the data for the income or expenditure in 2000.

Therefore, the profit for 2000 cannot be determined.
Question 8
1 / -0

Directions For Questions

Direction:The following line graph gives the annual percent profit earned by a Company during the period 1995 - 2000.

...view full instructions

What is the average profit percent earned for the given years?

A
$50 \frac{2}{3} \%$

B
$55 \frac{5}{6} \%$

C
$60 \frac{1}{6} \%$

D
$335 \%$

E
$52 \frac{5}{6} \%$

Solution

Percentage profit earned in different years:

In the year 1995 = 40%

In the year 1996 = 55%

In the year 1997 = 45%

In the year 1998 = 65%

In the year 1999 = 70%

In the year 2000 = 60%

Average profit percent $=\frac{1}{6} \times[40+55+45+65+70+60]\%$

$=\frac{335}{6}\%$%

$=55 \frac{5}{6}\%$
Question 9
1 / -0

A dishonest shopkeeper professes to sell his goods at the cost price but use faulty measure. His $1 kg$ weight measures $950 gms$ only. Find his gain percent.

A
$7 \frac{3}{19} \%$

B
$5 \frac{7}{19} \%$

C
$5 \frac{5}{19} \%$

D
$4 \frac{5}{19} \%$

E
$3 \frac{2}{19} \%$

Solution

Let, the cost price of $1 g$ sugar be $Rs .1$

Assume he sells $1000 g$ sugar.

Since he uses false weight he actually sells only $950 g$ sugar. Therefore, the actual cost price for him is Rs. $950 $.

Selling price $=$ Rs. $1000 $

Profit percentage $=\frac{(1000-950)}{950} \times 100$

$=\frac{100}{19} \%$

$=5 \frac{5}{19} \%$
Question 10
1 / -0

Directions For Questions

Direction: Study the following pie-chart carefully and answer the following questions.

The following pie-chart shows the percentage distribution of IT Technicians in different companies.

Total IT Technicians = 2000

...view full instructions

If one – fourth of the IT Technicians who work in Infosys is female, then number of male IT Technicians in Infosys is approximately what percentage of the total number of IT Technicians who work in HCL?

A
48%

B
60%

C
50%

D
55%

E
65%

Solution

Given:

Percentage distribution of IT Technicians in Infosys = 17%

Percentage distribution of IT Technicians in HCL= 23%

One – fourth of the IT Technicians who work in Infosys is female

No. of IT Technicians in Infosys = 17% of 2000

= $2000 \times \frac{17}{100}$ = 340

No. of female IT Technicians in Infosys = $\frac{1}{4} \times 340$ = 85

No. of male IT Technicians in Infosys = 340 - 85 = 255

No. of IT Technicians in HCL = 23% of 2000

= $2000 \times \frac{23}{100}$ = 460

Required percentage = $\frac{Male IT Technicians in Infosys}{No . of IT Technicians in HCL} \times 100$

= $\frac{255}{460} \times 100$ = 55%

∴ The required answer is 55%.