Quantitative Aptitude Test

Result

Quantitative Aptitude Test - 3

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Weekly Quiz Competition

Question 1
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Directions For Questions

Direction: Study the following pie-chart carefully and answer the following questions.

The following pie-chart shows the percentage distribution of IT Technicians in different companies.

Total IT Technicians = 2000

...view full instructions

What is the respective ratio of the number of IT Technicians who work in Wipro and the number of IT Technicians who work in L&T?

A
5 : 4

B
4 : 5

C
13 : 8

D
8 : 13

E
8 : 15

Solution

Given:

Percentage distribution of IT Technicians in L&T = 8%

Percentage distribution of IT Technicians in Wipro = 13%

No. of IT Technicians in Wipro = 13% of 2000

= $2000 \times \frac{13}{100}$ = 260

No. of IT Technicians in L&T = 8% of 2000

= $2000 \times \frac{8}{100}$ = 160

∴ Required ratio = 260 : 160

= 13 ∶ 8
Question 2
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Directions For Questions

Direction: Study the following pie-chart carefully and answer the following questions.

The following pie-chart shows the percentage distribution of IT Technicians in different companies.

Total IT Technicians = 2000

...view full instructions

What is the total no. of IT Technicians in HCL, TCS, and CTS?

A
1200

B
1140

C
1240

D
1350

E
1250

Solution

Given:

Percentage distribution of IT Technicians in HCL= 23%

Percentage distribution of IT Technicians in TCS = 27%

Percentage distribution of IT Technicians in CTS = 12%

No. of IT Technicians in HCL = 23% of 2000

= $2000 \times \frac{23}{100}$ = 460

No. of IT Technicians in TCS = 27% of 2000

= $2000 \times \frac{27}{100}$ = 540

No. of IT Technicians in CTS = 12% of 2000

= $2000 \times \frac{12}{100}$ = 240

Total no. of IT technician = No. of IT Technicians in HCL + No. of IT Technicians in TCS + No. of IT Technicians in CTS

= 460 + 540 + 240 = 1240

∴ The required answer is 1240.
Question 3
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Directions For Questions

Direction: Study the following pie-chart carefully and answer the following questions.

The following pie-chart shows the percentage distribution of IT Technicians in different companies.

Total IT Technicians = 2000

...view full instructions

What is the difference between the total number IT Technicians who work in TCS and Infosys together and the total number of IT Technicians who work in Wipro and CTS together?

A
500

B
320

C
460

D
380

E
350

Solution

Given:

Percentage distribution of IT Technicians in TCS = 27%

Percentage distribution of IT Technicians in Infosys = 17%

Percentage distribution of IT Technicians in Wipro = 13%

Percentage distribution of IT Technicians in CTS = 12%

Total IT Technicians = 2000

No. of IT Technicians in TCS = 27% of 2000

= $2000 \times \frac{27}{100}$ = 540

No. of IT Technicians in Infosys = 17% of 2000

= $2000 \times \frac{17}{100}$ = 340

No. of IT Technicians in Wipro = 13% of 2000

= $2000 \times \frac{13}{100}$ = 260

No. of IT Technicians CTS = 12% of 2000

= $2000 \times \frac{12}{100}$ = 240

Total IT Technicians in TCS and Infosys = 540 + 340 = 880

Total IT Technicians in Wipro and CTS = 260 + 240 = 500

Difference = Total IT Technicians in TCS and Infosys - Total IT Technicians in Wipro and CTS

∴ Required difference = 880 – 500 = 380
Question 4
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Directions For Questions

Direction: Study the following pie-chart carefully and answer the following questions.

The following pie-chart shows the percentage distribution of IT Technicians in different companies.

Total IT Technicians = 2000

...view full instructions

If the percentage of Wipro IT Technicians are increased by 10% and the percentage of L&T IT Technicians are decreased by 25% then what will be the total number of Wipro and L&T IT Technicians together?

A
206

B
306

C
406

D
506

E
500

Solution

Given:

Percentage distribution of IT Technicians in Wipro = 13%

Percentage distribution of IT Technicians in L&T = 8%

No. of IT Technicians in Wipro = 13% of 2000

= $2000 \times \frac{13}{100}$ = 260

No. of IT Technicians in Wipro after 10% increase = 260 + 10% of 260

= 260 + $260 \times \frac{10}{100}$

= 260 + 26 = 286

No. of IT Technicians in L&T = 8% of 2000

= $2000 \times \frac{8}{100}$ = 160

No. of IT Technicians in L&T after 25% decrease = 160 - 25% of 160

= 160 - $160 \times \frac{25}{100}$

= 160 - 40 = 120

Total number of Wipro and L&T IT Technicians = 286 + 120 = 406

∴ The required answer is 406.
Question 5
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Directions For Questions

Direction: Study the table carefully and answer the following questions given below.

The number of students who attended semesters of five different schools in three Quarters (Q1, Q2 and Q3).

...view full instructions

What is the ratio between the total number of students of A, B and C attended semesters in Quarter 3 to the Students of D and E attended semesters in Quarter 1?

A
9 : 4

B
11 : 3

C
13 : 4

D
17 : 6

E
11 : 6

Solution

Students of A, B and C attended semesters in Quarter 3 = 325

Students of D and E attended semesters in Quarter 1 = 100

$\therefore$ Required Ratio = 325 : 100 = 13 : 4
Question 6
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Directions For Questions

Direction: Study the table carefully and answer the following questions given below.

The number of students who attended semesters of five different schools in three Quarters (Q1, Q2 and Q3).

...view full instructions

Students of school C in Quarter 1 is approximately what percent of the students of school D for Quarter 2 and 3 attended the semesters?

A
44%

B
33%

C
67%

D
71%

E
81%

Solution

Students of C attended semesters in Quarter 1 = 125

Students of D attended semesters in Quarter 2 and 3 = (75+100) $=175$

$\therefore$ Required Percentage $=\left(\frac{125}{175}\right) \times 100$

$=71.43 \% \approx$ 71%
Question 7
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Directions For Questions

Direction: Study the table carefully and answer the following questions given below.

The number of students who attended semesters of five different schools in three Quarters (Q1, Q2 and Q3).

...view full instructions

For which of the following school, the semesters attended by the Students is the highest in all the quarters?

A
A

B
B

C
C

D
D

E
E

Solution

Number of students attending semesters for school A = (75+125 +100) = 300

Number of students attending semesters for school B = (25+100+50) = 175

Number of students attending semesters for school C = (125+50 +175) = 350

Number of students attending semesters for school D = (75+75+100) = 250

Number of students attending semesters for school E = (25+200+100) = 325

$\therefore$ For school C, the semesters attended by the students is the highest in all the quarters.
Question 8
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Directions For Questions

Direction: Study the table carefully and answer the following questions given below.

The number of students who attended semesters of five different schools in three Quarters (Q1, Q2 and Q3).

...view full instructions

Find the ratio of the average number of students who attended the semesters in Quarter 2 to the average number of students who attended the semesters in Quarter 1.

A
19 : 14

B
26 : 15

C
22 : 13

D
15 : 13

E
18 : 11

Solution

Average number of students who attended the semesters in Quarter 2 = $\frac{550}{5}$ = 110

Average number of students who attended the semesters in Quarter 1= $\frac{325}{5}$ = 65

$\therefore$ Required Ratio$=110: 65$ = 22 : 13
Question 9
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Directions For Questions

Direction: Study the table carefully and answer the following questions given below.

The number of students who attended semesters of five different schools in three Quarters (Q1, Q2 and Q3).

...view full instructions

Students attended the semesters of school C in all quarters is approximately how much percent more than the students attended the semesters of school E in all quarters?

A
8%

B
12%

C
10%

D
6%

E
14%

Solution

Number of students attended the semesters of school C = (125+50+175) = 350

Number of students attended the semesters of school E = (25+200+100) = 325

$\therefore$ Required Percentage = $\left[\frac{(350-325)}{325}\right] \times 100$ = $7.69 \% \approx$ 8%
Question 10
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Together, Raju and Monu can do a piece of work in 10.5 days. Raju alone takes 15 days to completed the same work. In how many days can Monu alone completed the same work?

A
105 days

B
35 days

C
15 days

D
40 days

E
30 days

Solution

Let Monu alone can do a piece of work in x days.

Then Monu's 1 day's work = $\frac{1}{x}$

Raju alone can do a piece of work in 15 days.

Then Raju's 1 day's work = $\frac{1}{15}$

Similarly, (Raju + Monu)'s 1 day's work = $\frac{1}{(10.5)}$

According to the question,

$(\frac{1}{15})$ + $(\frac{1}{x})$ = $\frac{1}{(10.5)}$

⇒ $\frac{1}{x}$ = $\frac{1}{(10.5)}$ - $(\frac{1}{15})$ ⇒ x = 35