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Quantitative Aptitude Test - 5

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Quantitative Aptitude Test - 5
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  • Question 1
    1 / -0

    A mixture of 60 liters of wine and water contains 20% of water. How much water should be added to the mixture so that the water will be 36% in the final mixture?

    Solution

    The total quantity of the mixture is 60 liters

    In the mixture water is 20%

    After adding water, it will be 36% in the final mixture.

    According to the question, We will add only water to the final mixture

    So, we will consider 100% of the water will be added to the final mixture so that in the final mixture the water will be 36%

    So, the ratio of the initial quantity of the mixture to the quantity of the water added to the mixture will be 4 ∶ 1

    Let the initial quantity of the mixture be 4x and the added water be x

    So, we can say 4x = 60

    ⇒ x = 604 ⇒ x = 15

  • Question 2
    1 / -0

    The ratio of present age of P and Q is 7 : 5. Q’s present age is 5/6 times of R’s present age. If P is 5 years older than R, then find the ratio of age of P and R, 5 years from now.

    Solution

    Let us consider the present age of P, Q and R as P years, Q years and R years respectively.

    given, P = 7Q5

    Also, R = 6Q5

    And, P - R = 5

    ⇒ 7Q5 - 6Q5 = 5

    ⇒ Q = 25 years

    ⇒ P = 35 years and R = 30 years

    ∴ the ratio of age of P and R, 5 years from now = 35 + 5 : 30 + 5 = 8 : 7

  • Question 3
    1 / -0

    A batsman has a definite average for \(11\) innings. The batsman score \(120\) runs in his \(12^{\text {th }}\) inning due to which his average increased by \(5\) runs. Accordingly, what is the average of the batsman after \(12\) innings?

    Solution

    Given:

    Batsman scored in \(12^{\text {th }}\) innings \(=120\) run

    His average increased \(=5\) runs

    Formula used:

    Average \(=\frac{\text { Sum of observations }}{\text { Number of observations }}\)

    Let average score of \(11\) innings be \(x\).

    According to the question,

    \(\Rightarrow 11 x+120=(x+5) \times 12\)

    \(\Rightarrow 11 x+120=12 x+60\)

    \(\Rightarrow x=60\)

    The average of the batsman after \(12\) innings \(=(60+5)=65\)

    \(\therefore\) Required average is \(65\).

  • Question 4
    1 / -0

    Directions For Questions

    Direction: What will come in the place of the question mark (?) in the following question?

    ...view full instructions

    \(\sqrt{144} \div 4 \times 6-\sqrt{196} \div \sqrt{4 9}+5=?\)

    Solution

    Given,

    \(\sqrt{144} \div 4 \times 6-\sqrt{196} \div \sqrt{49}+5=?\)

    \(\Rightarrow 12 \div 4 \times 6-14 \div 7+5=?\)

    \(\Rightarrow 3 \times 6-2+5=?\)

    \(\Rightarrow 18-2+5=?\)

    \(\Rightarrow ?=21\)

    \(\therefore\) The value of \(?\) is \(21\).

  • Question 5
    1 / -0

    Directions For Questions

    Direction: What will come in the place of the question mark (?) in the following question?

    ...view full instructions

    680 × 24 ÷  12 ÷ 17 + 12 of 6 = ?

    Solution

    Given, 

    \(680 \times 24 \div 12 \div 17+12\) of \(6=?\)

    \(\Rightarrow680 \times 2 \div 17+12\times 6=?\)

    \(\Rightarrow 680 \times \frac{2}{17}+12 \times 6=?\)

    \(\Rightarrow 80+72=?\)

    \(\Rightarrow ? =152\)

    \(\therefore\) The value of \(?\) is \(152\). 

  • Question 6
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the related question.

    Rajesh invested Rs. 50000 in Scheme at 20% compound interest for 2 years. After 2 years he withdraws all his money and that money was used to purchase a TV Rs. 36000 and with remaining amount 20% in SIP Mutual funds and with remaining money he purchased 2 bike B1 and B2 for an equal amount after that he sells Bike B1 at 10% profit and Bike B2 at 20% profit.

    ...view full instructions

    What was the amount received after 2 years of his investment?

    Solution

    Given:

    Rajesh invested Rs. 50000.

    Invested 20% \(=20+20+\frac{(20 \times 20)}{ 100}\)

    Invested return = 44%

    Rajesh total amount \(= 50000 × \frac{44 }{100}\) = Rs. 22000

    Total amount of Rajesh = Rs. 50000 + Rs. 22000 = Rs. 72000

     The amount received after 2 years is Rs. 72000.

     

     

  • Question 7
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the related question.

    Rajesh invested Rs. 50000 in Scheme at 20% compound interest for 2 years. After 2 years he withdraws all his money and that money was used to purchase a TV Rs. 36000 and with remaining amount 20% in SIP Mutual funds and with remaining money he purchased 2 bike B1 and B2 for an equal amount after that he sells Bike B1 at 10% profit and Bike B2 at 20% profit.

    ...view full instructions

    What was the amount invested in SIP mutual funds?

    Solution

    Given:

    Invested 20% \(=20+20+\frac{(20 \times 20)}{100}\)

    Invested return = 44%

    Rajesh total amount \(=50000 \times \frac{44}{100}\) = Rs. 22000

    Total amount of Rajesh = Rs. 50000 + Rs. 22000 = Rs. 72000

    Remaining amount after TV buy = Rs. 72000 – Rs. 36000 = Rs. 36000

    SIP in Mutual funds \(= 36000 × \frac{20}{100} \) = Rs. 7200

  • Question 8
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the related question.

    Rajesh invested Rs. 50000 in Scheme at 20% compound interest for 2 years. After 2 years he withdraws all his money and that money was used to purchase a TV Rs. 36000 and with remaining amount 20% in SIP Mutual funds and with remaining money he purchased 2 bike B1 and B2 for an equal amount after that he sells Bike B1 at 10% profit and Bike B2 at 20% profit.

    ...view full instructions

    What was the selling price of Bike 1?

    Solution

    Given:

    Rajesh invested Rs. 50000.

    Invested 20% \(=20+20+\frac{(20 \times 20)}{100}\)

    Invested return = 44%

    Rajesh total amount \(=50000 \times \frac{44}{100}=2000\)

    Total amount of Rajesh = Rs. 50000 + Rs. 22000 = Rs. 72000

    Remaining amount after TV buy = Rs. 72000 – Rs. 36000 = Rs. 36000

    SIP in Mutual funds \(= 36000 × \frac{20}{100} = 7200\)

    Remaining amount = Rs. 36000 – Rs. 7200 = Rs. 28800

    That amount used in the buy two Bikes.

    B1 bike profit \(= 14400 × \frac{10}{100} =\) Rs. 1440

    ∴ The selling price of Bike B1 = Rs. 14400 + Rs. 1440 = Rs. 15840

  • Question 9
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the related question.

    Rajesh invested Rs. 50000 in Scheme at 20% compound interest for 2 years. After 2 years he withdraws all his money and that money was used to purchase a TV Rs. 36000 and with remaining amount 20% in SIP Mutual funds and with remaining money he purchased 2 bike B1 and B2 for an equal amount after that he sells Bike B1 at 10% profit and Bike B2 at 20% profit.

    ...view full instructions

    What was the amount left with Rajesh after buying a TV?

    Solution

    Given:

    Rajesh invested Rs. 50000.

    Invested 20% \(=20+20+\frac{(20 \times 20)}{100}\)

    Invested return = 44%

    Rajesh total amount \(=50000 \times \frac{44}{100}\) = Rs. 2000

    Total amount of Rajesh = Rs. 50000 + Rs. 22000 = Rs. 72000

    Remaining amount  = Rs. 72000 – Rs. 36000 = Rs. 36000

    The amount left with Rajesh after buying a TV is Rs. 36000.

  • Question 10
    1 / -0

    Directions For Questions

    Direction: Study the following information carefully and answer the related question.

    Rajesh invested Rs. 50000 in Scheme at 20% compound interest for 2 years. After 2 years he withdraws all his money and that money was used to purchase a TV Rs. 36000 and with remaining amount 20% in SIP Mutual funds and with remaining money he purchased 2 bike B1 and B2 for an equal amount after that he sells Bike B1 at 10% profit and Bike B2 at 20% profit.

    ...view full instructions

    What was the average Selling price of the Bike B1 and Bike B2?

    Solution

    Given:

    Rajesh invested Rs. 50000.

    Invested 20% \(=20+20+\frac{(20 \times 20)}{100}\)

    Invested return = 44%

    Rajesh total amount \(=50000 \times \frac{44}{100}\) = Rs. 2000

    Total amount of Rajesh = Rs. 50000 + Rs. 22000 = Rs. 72000

    Remaining amount after TV buy = Rs. 72000 – Rs. 36000 = Rs. 36000

    SIP in Mutual funds \(= 36000 × \frac{20}{100}\) = Rs. 7200

    Remaining amount = Rs. 36000 – Rs. 7200 = Rs. 28800

    That amount used in the buy two Bikes.

    B1 bike profit \(= 14400 × \frac{10}{100}\) = Rs. 1440

    Total profit amount Bike B1 = Rs. 14400 + Rs. 1440 = Rs. 15840

    B2 bike profit \(= 14400 × \frac{20}{100}\) = Rs. 2880

    Total Selling amount Bike B2 = Rs. 14400 + Rs. 2880 = Rs. 17280

    Then the average Selling price of Bike1 and Bike2 \(= \frac{(15840 + 17280)}{2}\)

    ∴ Average selling price of Bike1 and Bike2 = Rs. 16560

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