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Quantitative Aptitude Test - 8

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Quantitative Aptitude Test - 8
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  • Question 1
    1 / -0

    Directions For Questions

    Direction: Go through the statements given below and answer the question based on it.

    1. A group of students from school go on educational trip. The number of boys go on trip is 120% of number of girls go on trip.

    2. Number of boys go on trip is 60 more than the number of girls go on trip.

    3. 25% of total girls in school not go on trip and the ratio of total number of boys and girls in school is 5 ∶ 4.

    ...view full instructions

    The number of students going on the trip is approximately what percentage of total students in the school?

    Solution

    We know that

    Required percentage \(=(\frac{\text{First quantity}}{\text{second quantity}}) \times 100\)

    From the table given above

    Total student in the school \(=900\)

    And number of student go on trip \(=660\)

    \(\therefore\) Required percentage \(=(\frac{660}{900}) \times 100 \approx 73.34 \%\)

    So, the required percentage is \(73.34 \%\)

  • Question 2
    1 / -0

    Directions For Questions

    Direction: Go through the statements given below and answer the question based on it.

    1. A group of students from school go on educational trip. The number of boys go on trip is 120% of number of girls go on trip.

    2. Number of boys go on trip is 60 more than the number of girls go on trip.

    3. 25% of total girls in school not go on trip and the ratio of total number of boys and girls in school is 5 ∶ 4.

    ...view full instructions

    The number of students does not go on trips is approximate what percent less than the number of people going on trip?

    Solution

    We know that,

    Required percentage \(=(\frac{\text{First quantity}}{\text{second quantity}}) \times 100\)

    From the table given above

    Number of student go on trip \(= 360+300=660\)

    And number of student not go on trip \(=140+100=240\)

    Required percentage \(=(\frac{(660-240)}{660}) \times 100=63.63 \% \approx 64 \%\)

    So, the required percentage is \(64 \%\).

  • Question 3
    1 / -0

    Directions For Questions

    Direction: Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and give answer:

    ...view full instructions

    What is the speed of the stream?

    Statement I: The ratio of speed in upstream to the speed in downstream is 2 : 3.

    Statement II: The distance travelled in upstream in 2 hours by a man is 4 km more than distance travelled by him in downstream in 1 hour.

    Solution

    From statement I

    Let speed of boat in still water and speed of current be \(\times \mathrm{km} / \mathrm{hr}\) and \(\mathrm{y} \mathrm{km} / \mathrm{hr}\).

    Now, \(\frac{x-y}{x+y}=\frac{2}{3}\)

    \(\Rightarrow 3 x-3 y=2 x+2 y\)

    \(\Rightarrow x=5 y\)

    Thus, the data in Statement I alone are not sufficient to answer the question

    From statement II.

    \((x-y) \times 2=(x+y) \times 1+4\)

    \(\Rightarrow x=3 y+4\)

    \(\because\) Speed in upstream and downstream is not known, so speed of the stream cannot be found using these data.

    Thus, the data in Statement II alone are not sufficient to answer the question,

    Combining I and II, \(3 y+4=5 y\)

    \(\Rightarrow 2 y=4\)

    \(\Rightarrow y=2\)

  • Question 4
    1 / -0

    Directions For Questions

    Direction: Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read both the statements and give answer:

    ...view full instructions

    What will be the ratio between bigger digit to the smaller digit in the two digit number?

    I. The largest digit is 9.

    II. The sum of the digits in the number is 5 times their difference.

    Solution

    Let the tens and unit digits be \(x\) and \(y\) respectively.

    Statement I do not give the answer.

    From statement II, we have,

    \((x+y)=5(x-y)\)

    \((x+y)=5 x-5 y\)

    \(4 x=6 y\)

    \(\frac{x}{y}=\frac{6}{4}=\frac{3}{2}\)

    Therefore the required ratio \(=\frac{x}{y}=x y=3: 2\)

    Here, the data in Statement II alone are sufficient to find the answer, while the data in Statement I alone are not sufficient.

  • Question 5
    1 / -0

    Find \(X\) if; \(\cos \left(\cot ^{-1} \frac{1}{5}\right)=\sin \left(\tan ^{-1} X\right)\)

    Solution

    Given:

    \(\sin \left(\tan ^{-1} X\right)=\cos \left(\cot ^{-1} \frac{1}{5}\right)\)

    \(\Rightarrow \sin \left(\tan ^{-1} X\right)=\sin \left[90-\left(\cot ^{-1} \frac{1}{5}\right)\right]\)

    \(\Rightarrow \tan ^{-1} X=90-\cot ^{-1} \frac{1}{5}\)

    \(\Rightarrow \tan ^{-1} X=90-\left(90-\tan ^{-1} \frac{1}{5}\right)\)

    \(\Rightarrow \tan ^{-1} X=\tan ^{-1} \frac{1}{5}\)

    Taking \(\tan\) both sides

    \(\Rightarrow \tan \left(\tan ^{-1} X\right)=\tan \left(\tan ^{-1} \frac{1}{5}\right)\)

    \(\Rightarrow X=\frac{1}{5}\)

  • Question 6
    1 / -0

    Directions For Questions

    Direction: Study the following bar graph and answer the question that follows.

    The bar graph shows number of appeared candidates and failed candidates(in hundreds) in a test from five different institutions

    ...view full instructions

    Number of candidates failed from institutions C and D together is what percentage of the total number of candidates appeared from institutions C and D together?

    Solution

    Total number of candidates failed from institutions C and D together = (15+10) =25

    Total number of candidates appeared from institutions C and D together = (30+20) = 50

    Required percentage = \(\frac{25}{50}\) \(\times 100\) = 50

    \(\therefore\) Number of candidates failed from institutions C and D together is 50% of the total number of candidates appeared from institutions C and D together.

  • Question 7
    1 / -0

    Directions For Questions

    Direction: Study the following bar graph and answer the question that follows.

    The bar graph shows number of appeared candidates and failed candidates(in hundreds) in a test from five different institutions

    ...view full instructions

    What is the total number of candidates passed from institutions A, B and D together?

    Solution

    The number of candidates passed from institution A =(20-05) = 15

    The number of candidates passed from institution B =(25-10) = 15

    The number of candidates passed from institution D =(20-10) = 10

    The total number of candidates passed from institutions A, B and D together(15 + 15 + 10) = 40

    \(\therefore\) The total number of candidates passed from institutions A, B and D together is 40.

  • Question 8
    1 / -0

    Directions For Questions

    Direction: Study the following bar graph and answer the question that follows.

    The bar graph shows number of appeared candidates and failed candidates(in hundreds) in a test from five different institutions

    ...view full instructions

    From which institution the difference between the appeared candidates and failed candidates is minimum?

    Solution

    The difference between the appeared candidates and failed candidates from institute A =(20 - 05) =15

    The difference between the appeared candidates and failed candidates from institute B = (25 - 10) = 15

    The difference between the appeared candidates and failed candidates from institute C =(30 - 15) = 15

    The difference between the appeared candidates and failed candidates from institute D =(20 - 10) = 10

    The difference between the appeared candidates and failed candidates from institute E =(35 - 20) = 15

    \(\therefore\) The minimum difference between the appeared candidates and failed candidates is from institution D.

  • Question 9
    1 / -0

    Directions For Questions

    Direction: Study the following bar graph and answer the question that follows.

    The bar graph shows number of appeared candidates and failed candidates(in hundreds) in a test from five different institutions

    ...view full instructions

    What has the average number of candidates who appeared from all the institutions together?

    Solution

    Sum of number of candidates appeared from all the institutions together = \(20+25+30+20+35\) = \(130\)

    Total number of candidates appeared = \(5\)

    Required average = \(\frac{\text { Sum of number of candidates appeared from all the institutions together }}{\text { Total number of candidates appeared }}\)

    \(\Rightarrow \frac{130}{5}\) = 26

    \(\therefore\) The average number of candidates who appeared from all the institutions together is 26.

  • Question 10
    1 / -0

    Directions For Questions

    Direction: Study the following bar graph and answer the question that follows.

    The bar graph shows number of appeared candidates and failed candidates(in hundreds) in a test from five different institutions

    ...view full instructions

    What is the ratio between the number of candidates appeared from institute B and D together and candidates failed from A, C and E together?

    Solution

    Total number of candidates appeared from institute B and D together = (25 + 20) = 45

    Total number of candidates failed from A, C and E together = (5 + 15 + 20) = 40

    Required ratio = 45 : 40

    = 9 : 8

    \(\therefore\) The ratio between the number of candidates appeared from institute B and D together and candidates failed from A, C and E together is 9 : 8.

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