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Inequalities Test - 5

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Inequalities Test - 5
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  • Question 1
    2 / -0.83

    In drilling world’s deepest hole, it was found that the temperature T in degree Celsius, x km below the surface of Earth, was given by T = 30 + 25 (x – 3), 3 < x < 15. If the required temperature lies between 200o C and 300o C, then the depth, x will lie between

    Solution

    T = 30 + 25 (x – 3), 3 < x < 15
    It is given 200 < T < 300
    200 < 30 + 25 (x – 3) < 300
    170 < 25(x - 3) < 270
    170/25  (x - 3) < 270/25
    6.8 + 3 < x < 10.8 + 3
    9.8 < x < 13.8

  • Question 2
    2 / -0.83

    A solution of 10% boric acid is to be diluted by adding a 4% boric acid solution to it. The resulting mixture is to be more than 5% but less than 8% boric acid. If we have 750 litres of the 10% solution, then the quantity of the 4% solution that has to be added will lie between

    Solution

    Let x litres of 4% boric acid solution is required to be added
    Then, total mixture = (x + 750)litres
    This resulting mixture is to be  more than 5% but less than 8% boric acid
    Total amount of acid = 750 of 10% + x of 4%
    ATQ  
    5/100(750 + x) <(750*10 + 4x)/100 <8/100(750 + x)
    3750 + 5x <7500 + 4x ; 7500 + 4x <6000 + 8x
    x <3750  ;  x >375  
    375 and 3750

  • Question 3
    2 / -0.83

    Pairs of consecutive even positive integers, both of which are larger than 7 such that their sum is less than 28, are

    Solution

    Let x be the smaller of the two consecutive even positive integers .
    Then the other integer is x+2.
    Since both the integers are larger than 7,x >7 ....(1)
    Also the sum of the two integers is less than 28.
    x + (x + 2) <28
    ⇒2x + 2 <28
    ⇒2x <28 −2
    ⇒2x <26
    =>x <13 …...(2)
    From(1) and (2), we get
    7 Since x is an even number, x can take the values 8, 10 and 12.
    Thus the required possible pairs are (8,10),(10,12) and (12,8).

  • Question 4
    2 / -0.83

    The longest side of a triangle is 4 times the shortest side and the third side is 4 cm shorter than the longest side. If the perimeter of the triangle is at least 59 cm, then the minimum length of the shortest side is

  • Question 5
    2 / -0.83

    In an experiment a solution of hydrochloric acid is to be kept between 30 and 35 degree celcius. What is the range of temperature in degree Fahrenheit if conversion formula is given by  4664_fb54d051facfd6cfd3b8a748ec7d4c02 ,where C and F represent temperature in degree celsius and degree fahrenheit, respectively?

    Solution

    Temperature is defined as the degree of hotness.
    Temperature is measured using different scales in different regions.
    we know that
     C = temperature in celcius.
    F = temperature in Fahrenheit.
    F= 9(C)/5 + 32
    1) C = 30
    F= 9(30)/5 + 32
    F= 54 + 32 = 86F
    2) C = 35
    F= 9(35)/5 + 32
    F= 63 + 32 = 95F
    The range of temperatures in degree Fahrenheit is 86 F to 95 F.

  • Question 6
    2 / -0.83

    A man wants to cut three lengths from a single piece of board of length 91 cm. The second length is to be 6 cm longer than the shortest and the third length is to be thrice as long as the shortest. If the third piece is to be at least 4 cm longer than the second, then the length of the shortest board will lie between

    Solution

    Let the length of the shortest piece, The length of the second price is (x+6)cm. The length of the third piece is 3x cm, Total length of the three prieces must be ≤91cm.
    xcm+(x+6)cm+3xcm ≤91cm
    =>5x+6 ≤91
    Subtracting 6 from number 5 on both sides, 5x/5 ≤85/5
    x ≤17----(1)
    Step 2:
    Also third piece is at least 4 cm longer than the second piece. therefore
    3x ≥(x+6)+4
    =>3x ≥x+10
    Subtracting x from both sides,
    3x −x ≥10
    x ≥5 -----(2)
    Step 3:
    From (1) and (2)
    5 ≤x ≤17

  • Question 7
    2 / -0.83

    A plumber can be paid under two schemes as given below:
    I: Rs 600 and Rs 50 per hour.
    II: Rs 170 per hour.
    If the job takes n hours, then the values of n for which the scheme I will give the plumber better wages are

    Solution

    Your question is not complete it should be,
    I: &600 fix and &50 per hourNow solving the question,Let the work is done in n hour as per given , So After n hour according to first scheme he will get an amount
    = 600+50n After n hour according to second scheme he will get an amount,
    =170nNow we are asked for values of n such that scheme
    I give better wages so 600+50n >170n600 >120nor n <5 .SO if the numbers of hour are less than 5 then he will get better wages by first scheme.

  • Question 8
    2 / -0.83

    In the first four examinations, each of 100 marks, Dipika got 94, 73, 72, 84 marks. If a final average greater than or equal to 80 and less than 90 is needed to obtain a final grade B in a course, then the range of marks, Dipika must score in the fifth examination in order to obtain grade B is

    Solution

  • Question 9
    2 / -0.83

    The cost and revenue functions of a product are given by C(x) = 2x + 400 and R(x) = 6x + 20 respectively, where x is the number of items produced by the manufacturer. The minimum number of items that the manufacturer must sell to realize some profit is

    Solution

    Profit = revenue - cost
    But given profit >0
    therefore R(x) - C(x) >0
    therefore 4x - 380 >0
    therefore 4x >380
    therefore x >95  manufacturer must sell 96 items.

  • Question 10
    2 / -0.83

    IQ of a person is given by the formula  9034_image019 , where M A is mental age and CA is chronological age. If 85 < IQ < 145  for a group of 12-year children, then the mental age will lie between

    Solution

    85 ≤MA/CA ×100 ≤145
    (85*12)/100 ≤MA/CA ×100 ≤(145*12)/100
    10.2 ≤MA ≤17.4
    range of mental age is[10.2,17.4].

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