Averages Test

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Averages Test - 2

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Weekly Quiz Competition

Question 1
2 / -0.83

A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500?

A
Rs. 4991

B
Rs. 5991

C
Rs. 6001

D
Rs. 6991

Solution

Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6) - 34009 ]
= Rs. (39000 - 34009)
= Rs. 4991.
Question 2
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The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, what is the weight of B?

A
31 kg

B
28 kg

C
32 kg

D
30 kg

Solution

Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 .... (i)
A + B = (40 x 2) = 80 .... (ii)
B + C = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)
Subtracting (i) from (iv), we get : B = 31.
B 's weight = 31 kg.
Question 3
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If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, what is the average marks of all the students?

A
53.23

B
54.68

C
51.33

D
50

Solution
Question 4
2 / -0.83

The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. What is the present age of the husband?

A
40

B
32

C
28

D
30

Solution

Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) years = 90 years.
Sum of the present ages of wife and child = (20 * 2 + 5 * 2) years = 50 years.
Husband 's present age = (90 - 50) years
= 40 years
Question 5
2 / -0.83

The average weight of 8 person 's increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person?

A
75 Kg

B
50 Kg

C
85 Kg

D
80 Kg

Solution

The average weight of 8 persons increases by 2.5 kg
Total weight of 8 persons increased = 8 ×2.5 kg = 20 kg.
New person comes in place of one of them weighing 65 kg.
Hence the increase of weight of 8 persons together is because of new person replacing the person having 65 kg weight. Accordingly
Weight of new person = 65 + 20 kg = 85 kg
Thus the person replacing the 65 kg person should have 85 kg weight, which causes increase of weight of the group together by 2.5 kg .
Question 6
2 / -0.83

There are two divisions A and B of a class, consisting of 36 and 44 students respectively. If the average weight of divisions A is 40 kg and that of division b is 35 kg. What is the average weight of the whole class?

A
38.25

B
37.25

C
38.5

D
37
Solution
Weighted Average=[(Weight of Group 1) * (Average of Group 1) + (Weight of Group 2) * (Average of Group 2)]/Total Weight
In this case, Group 1 is Division A and Group 2 is Division B.
Given information:
Weight of Division A (Weight of Group 1Weight of Group 1) = 36 students
Average weight of Division A (Average of Group 1Average of Group 1) = 40 kg
Weight of Division B (Weight of Group 2Weight of Group 2) = 44 students
Average weight of Division B (Average of Group 2Average of Group 2) = 35 kg
Now, plug these values into the formula:
Weighted Average=[(36 students ×40 kg)+(44 students ×35 kg)]/36+44
Weighted Average=37.25kg
So, the average weight of the whole class is 37.25 kg.
Question 7
2 / -0.83

A batsman makes a score of 87 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning?

A
39

B
35

C
42

D
40.5

Solution

Let the batsman ’s average after 16 innings be x.
When he scores 87 in the 17th inning, his total runs become 16x + 87.
Since his average increases by 3 after the 17th inning, his new average is x + 3.
Using this information, we can set up the equation:
(16x + 87) / 17 = x + 3
Now we can solve for x:
16x + 87 = 17(x + 3)
16x + 87 = 17x + 51
87 - 51 = 17x - 16x
36 = x
So, the batsman 's average after 16 innings was x = 36. Since his average increased by 3, his new average after the
17th inning is:
36 + 3 = 39
Answer:
The correct answer is (a) 39 .
Question 8
2 / -0.83

A student needed to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x. He found the mean to be 12. What is the value of x?

A
12

B
5

C
7

D
9

Solution

As, Mean = Total Sum of Observations / No. of Observations
Clearly, we have (3 + 11 + 7 + 9 + 15 + 13 + 8 + 19 + 17 + 21 + 14 + x) / 12 = 12.
or 137 + x = 144
⇒x = 144 - 137 = 7.
Question 9
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Arun obtained 76, 65, 82, 67 and 85 marks (out in 100) in English, Mathematics, Chemistry, Biology and Physics. What is his average mark?

A
53

B
54

C
72

D
75

Solution

Average = (76 + 65 + 82 + 67 + 85 )/ 5 = 375/5 = 75.
Question 10
2 / -0.83

Three classes X, Y and Z take an algebra test.
The average score in class X is 83.
The average score in class Y is 76.
The average score in class Z is 85.
The average score of all students in classes X and Y together is 79.
The average score of all students in classes Y and Z together is 81.
What is the average for all the three classes?

A
82

B
81

C
81.5

D
84.5

Solution

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Re-Attempt Weekly Quiz Competition

Averages Test - 2

Result

Averages Test - 2

Score

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Rank

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SHARING IS CARING

Question 1

Rs. 4991

Rs. 5991

Rs. 6001

Rs. 6991

Solution

Question 2

31 kg

28 kg

32 kg

30 kg

Solution

Question 3

53.23

54.68

51.33

50

Solution

Question 4

40

32

28

30

Solution

Question 5

75 Kg

50 Kg

85 Kg

80 Kg

Solution

Question 6

38.25

37.25

38.5

37

Solution

Question 7

39

35

42

40.5

Solution

Question 8

12

5

7

9

Solution

Question 9

53

54

72

75

Solution

Question 10

82

81

81.5

84.5

Solution

User

Question Analysis

My Perfomance

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