Percentage Test

Result

Percentage Test - 3

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
2 / -0.83

A reduction of 20% in the price of rice enables a housewife to buy 5 kg more for rupees 1200. The reduced price per kg of rice

A
36

B
45

C
48

D
60

E
None of these

Solution
Question 2
2 / -0.83

The population of a village has increased annually at the rate of 20%. If at the end of 3 years it is 21600, the population in the beginning of the first year?

A
10000

B
12500

C
15000

D
17500

E
None of these
Solution
We can use the formula for compound growth to find the initial population:
where:
P is the final population (21600)
P₀ is the initial population (what we want to find)
r is the annual growth rate (20% or 0.20)
n is the number of years (3)
Plug in the known values:

Simplify and solve for P₀ :
21600 = P₀ ( 1.20)³
21600 = P₀ ( 12/10 x 12/10 x 12/10)
hence, P₀ = 12500
Question 3
2 / -0.83

12 percent of the voters in an election did not cast their votes. In this election there are only two candidates. The winner by obtaining 45% of the total votes and defeated his rival by 2000 votes. The total number of votes in the election

A
50,000

B
75,000

C
1,00,000

D
1,25,000

E
None of these
Solution
Let the total number of votes in the election be x.
12% of the voters did not cast their votes, so the number of valid votes is 88% of the total votes.
Valid votes = 0.88 ×x
The winner received 45% of the total votes. Therefore, the votes received by the winner are:
0.45 ×x
The remaining votes are for the rival candidate, which is:
0.88x −0.45x = 0.43x votes
The winner defeated his rival by 2000 votes. So, the difference between the winner ’s votes and the rival ’s votes is:
0.45x −0.43x = 2000
0.02x = 2000
Solving for x
Question 4
2 / -0.83

A number is first decreased by 25%. The decreased number is then increased by 20%. The resulting number is less than the original number by 40. Then the original number is –

A
100

B
200

C
300

D
400

E
None of these

Solution

Let the original number be x .
1. First , the number is decreased by 25%. So, the decreased number becomes:
Decreased number = x - (25/100) x = 0.75x
2. The decreased number is then increased by 20%. So, the resulting number becomes:
Resulting number = 0.75x + (20/100)(0.75x ) = 0.75x + 0.15x = 0.9x
3. The resulting number is 40 less than the original number:
x - 0.9x = 40
4. Simplifying the equation:
0.1x = 40
5. Solving for x :
x = 40 / 0.1 = 400
Thus, the original number is 400 .
Question 5
2 / -0.83

The number of seats in a cinema hall is decreased by 8% and also the price of the ticket is increased by 4 percent. What is the effect on the revenue collected?

A
increase 4.32%

B
decrease 4.32%

C
increase 3.32 percent

D
decrease 3.32%

E
None of these
Solution
Given:
Reduced percentage in seats = 8%
Increased percentage in price = 4%
Formula used:
Effective percentage = x - y - (xy)/100
x= increased percentage
y = Decreased percentage
Calculation:
Effective percentage = 4 - 8 - (4 ×8)/100
= - 4 - 0.32
= - 4.32%
The -ve sign means decreased percentage.
∴The correct answer is a 4.32% decrease.
Question 6
2 / -0.83

Ashwin distributes 30 sweets between Shweta and pallavi in the ratio 2 : 3. How much percentage of sweets do Pallavi get?

A
60%

B
50%

C
40%

D
70%

E
None of these
Solution
Total sweets = 30
Ratio of the sweets received by Shweta and Pallavi is 2 : 3
Let x
be ratio coefficient.
∴Sweets received by Shweta = 2x
And sweets received by Pallavi = 3x
Total sweets = 2x + 3x = 5x
But given
5x = 30
∴x = 30/5 =6
∴Sweets received by Shweta = 2 ×6
= 12
and by Pallavi = 3 ×6
= 18
Percentage of sweets received by Pallavi =
= 60%
Question 7
2 / -0.83

Weights of two friends A and B are in the ratio of 1 : 2. A ’s weight increases by 20% and the total weight of A and B together becomes 60 kg, with an increase of 30%. By what percent the weight of B increase?

A
30%

B
35%

C
40%

D
45%

E
None of these

Solution
Question 8
2 / -0.83

The marked price of an article is 20% higher than the cost price. A discount of 20% is given on the marked price. In this transaction the seller

A
bears no loss no profit

B
losses 4%

C
gain 4%

D
losses 1%

E
None of these
Solution
Let the cost price (CP) of the article be x.
The marked price (MP) is 20% higher than the cost price, so:
Marked Price (MP) = x + 20% of x = x + 0.20x = 1.2x
A discount of 20% is given on the marked price.
The selling price (SP) after the discount is:
Selling Price (SP) = MP −20% of MP = 1.2x −0.20 ×1.2x = 1.2x −0.24x = 0.96x
Now, compare the selling price (SP) with the cost price (CP):
The selling price is 0.96x, and the cost price is x.
The percentage loss or gain can be calculated as:
Thus, the seller incurs a loss of 4% in this transaction.
Question 9
2 / -0.83

When the price of rice is increased by 30 percent, a family reduces its consumption such that the expenditure is only 20 percent more than before. If 50 kg of rice is consumed by family before, then find the new consumption of family (approx.)

A
43kg

B
44kg

C
45kg

D
46kg

E
None of these
Solution
Let the original price of rice be P (per kg).
The original consumption of rice by the family is 50 kg.
The original expenditure of the family is:
Original expenditure = 50 ×P = 50P
The price of rice is increased by 30%.
The new price of rice becomes:
New price = P + 30% of P = P + 0.30P = 1.3P
The family ’s expenditure increases by 20%.
The new expenditure is:
New expenditure = 50P + 20% of 50P = 50P + 0.20 ×50P =60P
Let the new consumption of rice be x kg.
The new expenditure is the product of the new price and the new consumption:
New expenditure = x ×1.3P
Set the new expenditure equal to the previous calculation of 60P:
x ×1.3P = 60P
Thus, the new consumption of the family is approximately 46 kg .
Question 10
2 / -0.83

A man has 4000 rupees in his account two years ago. In the first year he deposited 20 percent of the amount in his account. In the next year he deposited 10 percent of the increased amount in the account. Find the total amount in the account of the person after 2 years.

A
6650

B
5280

C
5740

D
5840

E
None of these
Solution
Given:
A person had Rs.4000 in his account two years ago.
In the first year he deposited 20% in his account
Next year he deposited 10% of the increased amount.
Calculation:
In the first year,
He deposit = 20% ×4000 = Rs. 800
∴Increased amount after 1st year = 4000 + 800 = 4800
Next year,
He deposit = 10% ×4800 = 480
∴Total amount in the person 's account after 2 years = 4800 + 480
= 5280
∴ Total amount in the person 's account after 2 years = 5280
Question 11
2 / -0.83

In an election contested by two parties A and B, party A secured 25 percent of the total votes more than Party B. If party B gets 15000 votes. By how much votes does party B loses the election?

A
8000

B
10000

C
12000

D
15000

E
None of these
Solution
Let the total number of votes be T.
Party B gets 15,000 votes.
According to the problem, Party A secured 25% more votes than Party B. So, the number of votes for Party A is T −15000, and it is also 25% more than Party B ’s votes, which means:
Therefore, the total number of votes is 40,000.
Party A ’s votes = T −15000 = 40000 −15000 = 25000.
Party B ’s votes = 15,000 (as given).
The difference between Party A and Party B ’s votes is:
25000 −15000 = 10000
Thus, Party B loses the election by 10,000 votes.
Question 12
2 / -0.83

A vendor sells 50 percent of apples he had and throws away 20 percent of the remainder. Next day he sells 60 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw?

A
20%

B
22%

C
24%

D
26%

E
None of these
Solution
Let the total number of apples the vendor initially had be 100 (for simplicity).
On the first day:
The vendor sells 50% of the apples:
Apples sold on day 1 = 50% of 100 = 50
The remaining apples after selling 50% are:
Remaining apples = 100 −50 = 50
He then throws away 20% of the remaining apples:
Apples thrown away on day 1 = 20% of 50 = 10
The remaining apples after throwing away 20% are:
Remaining apples after day 1 = 50 −10 = 40
On the second day:
The vendor sells 60% of the remaining apples:
Apples sold on day 2 = 60% of 40 = 24
The remaining apples after selling 60% are:
Remaining apples after selling on day 2 = 40 −24 = 16
He throws away the rest, which is 16 apples.
Total apples thrown away:
Apples thrown away on day 1 = 10
Apples thrown away on day 2 = 16
Total apples thrown away = 10 + 16 = 26
Percentage of apples thrown away:
Thus, the vendor throws away 26% of his apples.
Question 13
2 / -0.83

40% of the women are above 30 years of age and 80 percent of the women are less than or equal to 50 years of age. 20 percent of all women play basketball. If 30 percent of the women above the age of 50 play basketball, what percent of players are less than or equal to 50 years?

A
50%

B
60%

C
70%

D
80%

E
None of these
Solution
Let the total number of women be 100 (for simplicity).
Women above 30 years of age:
40% of the women are above 30 years of age, which means:
Women above 30 years = 40% of 100 = 40 women
Women less than or equal to 50 years of age:
80% of the women are less than or equal to 50 years of age, which means:
Women less than or equal to 50 years = 80% of 100 = 80 women
Women above 50 years of age:
Since 80% are less than or equal to 50 years, the remaining 20% are above 50 years of age, which means:
Women above 50 years = 20% of 100 = 20 women
Women who play basketball:
20% of all women play basketball, which means:
Total basketball players = 20% of 100 = 20 women
Women above 50 years of age who play basketball:
30% of the women above 50 years play basketball, which means:
Basketball players above 50 years = 30% of 20 = 6 women
Women less than or equal to 50 years who play basketball:
The total number of basketball players is 20, and 6 of them are above 50 years of age.
Therefore, the number of players less than or equal to 50 years of age is:
Basketball players less than or equal to 50 years = 20 −6 = 14 women
Percentage of players who are less than or equal to 50 years of age:
Percentage of players less than or equal to 50 years =
Thus, 70% of the basketball players are less than or equal to 50 years of age.
Question 14
2 / -0.83

Alisha goes to a supermarket and bought things worth rupees 60, out of which 40 paise went on sales tax. If the tax rate is 10 percent, then what was the cost of tax free items?

A
54.60

B
55.60

C
56.60

D
57.60

E
None of these
Solution
Total cost of items = ₹60
Sales tax paid = 40 paise = ₹0.40
Tax rate = 10%. So, the tax amount is 10% of the cost of taxed items (denoted as T).
The sales tax equation is:
Solving for T:
Now, the cost of tax-free items is:
Cost of tax-free items = 60 −T −Sales tax = 60 −4 −0.40 = 55.60 rupees.
Thus, the cost of tax-free items is ₹55.60.
Question 15
2 / -0.83

60 percent of the employees of a company are women and 75% of the women earn 20000 or more in a month. Total number of employees who earns more than 20000 per month in the company is 60 percent of the total employees.What fraction of men earns less than 20000 per month?

A
5/8

B
5/7

C
1/5

D
3/4

E
None of these
Solution
Total employees = 100 (for simplicity).
Number of women = 60% of 100 = 60 women.
Number of men = 40% of 100 = 40 men.
75% of the women earn 20,000 or more:
Women earning 20,000 or more = 75% of 60 = 0.75 ×60 = 45 women.
Total number of employees earning more than 20,000 per month is 60% of the total employees:
Employees earning more than 20,000 = 60% of 100 = 60 employees.
Out of these 60 employees, 45 are women, so the remaining 15 must be men:
Men earning more than 20,000 = 15 men.
The total number of men is 40, and 15 men earn more than 20,000, so the number of men earning less than 20,000 is:
Men earning less than 20,000 = 40 −15 = 25 men.
The fraction of men earning less than 20,000 is:
Fraction = 25/40 = 5 / 8
Thus, the correct answer is A: 5/8
Question 16
2 / -0.83

In a library, 30% of the books are in History. 50% of the remaining are in English and 40% of the remaining are in German. The remaining 4200 books are in regional languages. What is the total number of books in library?

A
10000

B
15000

C
20000

D
25000

E
None of these
Solution
Let the total number of books in the library be T.
30% of the books are in History:
History books = 30% of T = 0.30 ×T
The remaining books after accounting for History are:
Remaining books = T −0.30 ×T = 0.70 ×T
50% of the remaining books are in English:
English books = 50% of the remaining = 0.50 ×0.70 ×T = 0.35 ×T
After accounting for English books, the remaining books are:
Remaining books after English = 0.70T −0.35T = 0.35T
40% of the remaining books are in German:
German books = 40% of the remaining = 0.40 ×0.35 ×T = 0.14 ×T
After accounting for German books, the remaining books are:
Remaining books after German = 0.35T −0.14T = 0.21T
The remaining 4200 books are in regional languages, so:
0.21 ×T = 4200
Solving for T:
T = 4200/0.21 = 20000
Thus, the total number of books in the library is 20,000.
Question 17
2 / -0.83

A got 30% of the maximum marks in an examination and failed by 10 marks.However, B who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What were the passing marks in the examination?

A
65

B
75

C
80

D
90

E
85
Solution
Let maximum marks in the examination be 100x and passing marks be yy
A got 30% of the maximum marks, => 30x + 10=y ----------(i)
Similarly, for B = 40x −15 = y -------(ii)
Subtracting equation (i) from (ii), => 10x = 25
=> x = 2.5
Substituting it in equation (ii), we get: Passing marks = y = 85.
Question 18
2 / -0.83

The population of a town is 15000. It increases by 10 percent in the first year and 20 percent in the second year. But in the third year it decreases by 10 percent. What will be the population after 3 years.

A
16820

B
15820

C
17820

D
19820

E
None of these
Solution
Initial population = 15,000.
First year: Population increases by 10%.
New population after the first year:
Second year: Population increases by 20%.
New population after the second year:
Third year: Population decreases by 10%.
New population after the third year:
Thus, the population after 3 years will be 17,820 .
Question 19
2 / -0.83

30 litre of solution contains alcohol and water in the ratio 2:3. How much alcohol must be added to the solution to make a solution containing 60% of alcohol?

A
10

B
12

C
14

D
15

E
None of these
Solution
The initial solution contains 30 liters, with alcohol and water in the ratio 2:3.
The amount of alcohol in the solution is:
The amount of water in the solution is:
We need to add some amount of alcohol (let it be x) to make the alcohol content 60% of the total solution.
After adding x liters of alcohol, the new total volume of the solution will be 30 + x liters, and the amount of alcohol will be 12 + x liters.
The concentration of alcohol should be 60%, so:
Solving the equation:
Thus, 15 liters of alcohol must be added to the solution.
Question 20
2 / -0.83

720 sweets are distributed equally among the children in such a way that the number of sweets given to each child is equal to 20% of the total number of children. How many sweets did each child get?

A
11

B
15

C
12

D
14

E
None of these
Solution
Given,
Total number of sweets = 720
Concept:
x% of any value = Actual value ×(x/100)
Calculation:
Let number of children be x, then
Number of sweets each child get = x ×(20/100)
According to the question
x ×x ×20/100 = 720
⇒x² /5 = 720
⇒x² = 720 ×5
⇒x² = 3600
⇒x = √3600
⇒x = 60
∴Number of sweets each child get is = 60/5 = 12