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Profit and Loss Test - 3

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Profit and Loss Test - 3
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  • Question 1
    2 / -0.83

    A toy is sold for Rs.336, if the % of profit is equal to cost price, then find CP ?

    Solution

    (100+x)% of X = 336
    100x+x2  = 33600
    x2  +100x –33600 = 0
    (x+240x)(x-140x) =0
    X = 140

  • Question 2
    2 / -0.83

    Shopkeeper purchased some goods for Rs.900 and sold one-third of the goods at a loss of  what 12%, then at gain % should the remainder goods he sold to gain 18% profit on the whole transaction ?

    Solution

    1/3rd  at 12% loss = 900/3 =300*88/100 =264
    900*18/100 = 108 =>600+162+36 = 798
    198/600 *100 = 33%

  • Question 3
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    A bought ‘X ’quantity of pencils for Rs.500 and he sold 2/5 part for 5% loss and at which percent he must sell his rest of the quantity so that he would gain overall 10% profit ?

    Solution

    500*2/5 = 200
    5%L = 200*95/100 = 190
    500+10+(500*10/100) = 510+50 = 560
    60/500 * 100 = 20%

  • Question 4
    2 / -0.83

    A dealer marked the price of an item 20% above cost price. He allowed two successive discounts of 10% and 25% to a customer. A a result he incurred a loss of Rs.684. At what price did he sell the item to the customer ?

    Solution

    CP = 100
    MP = 120
    120*90/100 = 108; 108*75/100 = 81
    Loss = 100 –81 = 19%
    CP = 100/19*684 = 3600
    SP = 3600*81/100 = 2916

  • Question 5
    2 / -0.83

    A man gains 15% by selling an article for a certain price. If he sells it at double the price, then the % of profit will be

    Solution

    CP = 100, 15% GAIN = 115
    SP = 230
    P = 230-100 = 130
    % = 130%

  • Question 6
    2 / -0.83

    A man went to shop to buy mobile for Rs.3500, the rate of sales tax being 8%. He tell the shopkeeper to reduce the price of mobile to such an extent that has to pay Rs.3500, inclusive of all taxes. Find the reduction price.

    Solution

    3500*100/108 = 3240
    3500-3240 = 260

  • Question 7
    2 / -0.83

    An item was bought at Rs. X and sold at Rs.Y, thereby earning a profit of 15%. Had the value of X been 15% less and the value of Y been Rs.52 less, a profit of 20% would have been earned, What was the value of X ?

    Solution

    x(1.15)=y ———–1
    x(0.85)(1.2)=y-52 ——————-2
    Sub 1 in 2, and solve x
    (1.15)x-(1.02)x=52
    (0.13)x=52
    x=400

  • Question 8
    2 / -0.83

    An article passing threw two hands, is sold at profit of 40 % at the original price , if the first dealer makes a profit of 15 % , then the profit made by second dealer.

    Solution

    Total Profit = [P1 + P2 +(P1*P2/100)] 40 = 15 + P2 + (15*P2)
    25-p2 = 15P2/100
    2500 = 15p2+100p2
    P2 = 2500/115 = 21.7% = 22%

  • Question 9
    2 / -0.83

    A boy  sells a Radio to B at a 10 % loss, B sells it to C at 25 % gain and C sells it to D at a loss of 8 %, if D pays Rs 1625 for it then how much does A pay for.

    Solution

    Cost price of A = 1625*[(100*100*100)/(90*125*92)] = 1570

  • Question 10
    2 / -0.83

    What is the maximum % discount that a man can offer on her MP so that he ends up selling at no profit or loss, if he had initially marked his goods up by 35% (approximately)?

    Solution

    35-x-(35*x/100) = 0
    3500/100 –(100x+35x/100) = 0
    35 = 135/100
    X = 35*100/135 = 25.9 = 26%

  • Question 11
    2 / -0.83

    A vendor fixed Selling Price of a product at 40% above the cost price. He sells half the stock at this price, one-quarter of that stock at a discount of 25% on the original selling price and rest at a discount of 30% on the original selling price. Find the gain percentage all together?

    Solution

    Let CP = 100;
    marked price=140;
    Revenue = [(1/2)*140 + (1/4)*0.75*140 + (1/4)*0.7*140] = 70 + 26.25 + 24.5 = 120.75;
    % profit = 20.75/100 = 20.75%

  • Question 12
    2 / -0.83

    A vendor sold two magazines namely A and B. He sold magazine ‘A ’at a loss of 20% and magazine ‘B ’at a profit of 25% but finally there is no loss or no gain. If the total Selling price of both magazines is Rs.450. Find the difference between the Cost Price of Magazine ‘A ’and ‘B ’?

    Solution

    20% of x = 25% of y ; x + y = 450
    x/y = 5/4
    Difference = Rs.50

  • Question 13
    2 / -0.83

    Deepak found that he had made a loss of 10% while selling his smartphone. He also found that had he sold it for Rs.50 more, he would have made a profit of 5%. The initial loss was what percentage of the profit earned, had he sold the smartphone for a 5% profit ?

    Solution

    Profit= 5%
    5% of CP = Rs. 50
    CP = Rs. 1000
    Now, Loss% = 10%
    Loss =Rs. 100
    Required % = (100/50)*100 = 200%

  • Question 14
    2 / -0.83

    Mukesh and Rakesh wants to make 25% profit on selling good. Mukesh calculating it on cost price while Rakesh on the selling price, the difference in the profits earned by both being Rs. 100 and selling price being the same in both the cases. Find out the Selling Price of both goods?

    Solution

    Profit = 25% = 1/4
    Let CP of Mukesh ’s article = 4x &Profit = x; SP = 4x + x = 5x
    Let CP of Rakesh ’s article = 4y = 5x —(1)[Selling price of Mukesh ’s article = Cost Price of Rakesh ’s article] x –y = 100 —-(2)
    y = 500
    Selling price = 5x = 4y = 2000

  • Question 15
    2 / -0.83

    Ananya buys two bangle set for a total cost of Rs. 900. By selling one bangle set for 4/5 of its cost and the other for 5/4 of its cost, She makes a profit of Rs. 90 on the whole transaction. The cost of the lower priced bangle set is?

    Solution

    CP of 1st bangle set = x
    CP of 2nd bangle set = 900-x
    SP of 1st bangle set = 4x/5
    SP of 2nd bangle set=(900-X)5/4
    Profit=SP-CP
    90=4x/5+(900-X)5/4-900
    X = 300 = Lower priced bangle set = Rs.300

  • Question 16
    2 / -0.83

    A book shop owner wants to sell his old edition books(Total No: 40). If he sells them at Rs. 148 per book, he would be able to sell all the books. But for every Rs.8 increase in price of the book, he will be left with one extra unsold book. Assuming that unsold books remain with him. If he wants to maximise his profit, then how many unsold books remain with him?

    Solution

    From options
    unsold books = 12 ->(12*8 = 96); CP per book = 148 + 96 = 244 ; Revenue = 244 * 28 = 6832
    unsold books = 11 ->(11*8 = 88); CP per book = 148 + 88 = 236 ; Revenue = 236 * 29 = 6844
    unsold books = 10 ->(10*8 = 80); CP per book = 148 + 80 = 228 ; Revenue = 228 * 30 = 6840

  • Question 17
    2 / -0.83

    Akshay sells an article for Rs 500 and earned some profit. The profit of that article is equalled to the ten times of the loss incurred when it is sold for Rs.225. If he wants to make a profit of 30%, then what will be the Selling Price?

    Solution

    Selling price of an article = Rs 500; Let the cost price of the article = x
    Profit = Rs (500 –x)
    Selling price of the article = Rs 225; Loss = Rs (x –225)
    ⇒(500 –x) = 10 (x –225)
    ⇒500 –x = 10x –2250
    ⇒11x = 2750
    ⇒x = 250
    The cost prise of the article = Rs 250; Profit = 30%
    Selling price = 250 x (100 + 130) / 100 = 325

  • Question 18
    2 / -0.83

    A Vendor sells apples at a certain price in order to make a profit of 30%. If he charges Rs. 1.5 higher per apple he would get a profit of 60%. Find the original price at which he sold an apple?

    Solution

    CP of an apple = Rs. x
    Profit = 30%
    SP = Rs. 1.30x
    If SP = x + Rs.1.5
    Profit = 60%
    1.60x = x + 1.5 or x = Rs. 2.5
    Hence, Original SP = Rs 1.5x = Rs. 3.75

  • Question 19
    2 / -0.83

    Aaradhana buys rice at Rs.10/kg and sell it in order to earn a profit of 40%. However, her faulty balance shows 1000gm when it is actually 800gm. What is her actual gain percentage?

    Solution

    Let price of 1 kg rice = Rs.10.
    CP of 800 gm rice = Rs.8.
    She wants to earn a profit of 40% on per Kg
    SP = 10 + 40% of 10 = Rs. 14 per kg.
    Faulty balance shows 800 gm = 1000 gm (1 kg)
    She sells 800 gm for Rs.14.
    Profit = 14 –8 = Rs. 6.
    Profit(%) = 6/8 * 100 = 75%.

  • Question 20
    2 / -0.83

    Mr. Richard bought two watches  which together cost him Rs.440. He sold one of the watches at a loss of 20% and the other one at a gain of 40%. The selling price of both watches is same. Then find out the cost price of both watches.

    Solution

    80/100 * x = 140/100 * y
    x = 7/4y
    x + y = 440
    7/4 y + y = 440
    y = 160 ; x = 280

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