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Three Dimensional Geometry Test - 2

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Three Dimensional Geometry Test - 2
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  • Question 1
    2 / -0.83

    The coordinates of the centroid of a triangle whose vertices are (2, –1, 6), (3, 3, –2) and (–2, 1, –1) are:

    Solution

    Centroid of a triangle with vertices (x1 ,y1 );(x2 ,y2 ) and (x3 ,y3 ) is calculated by the formula (x1 +x2 +x3 )/3 , (y1 +y2 +y3 ​)/3, (z1 +z2 +z3 ​)/3
    So, centroid =[(2+3-2)/3 , (-1+3+1)/3 , (6-2-1)/3]
    = [1,1,1]

  • Question 2
    2 / -0.83

    The ratio, in which YZ-plane divides the line joining (2, 4, 5) and (3, 5, 7) is

    Solution

    Let the YZ plane divide the line segment joining points (2,4,5) and (3,5,7) in the ratio k:1.
    Hence, by section formula, the coordinates of point of intersection are given by :
    [k(3)+2]/(k+1), [k(5)+4]/(k+1), [k(8)+7]/(k+1)
    On the YZ plane, the x-coordinate of any point is zero.
    (3k+2)/(k+1) = 0
    3k + 2 = 0
    k = -2/3

  • Question 3
    2 / -0.83

    The ratio in which the join of points (1, –2, 3) and (4, 2, –1) is divided by XOY plane is:

    Solution

  • Question 4
    2 / -0.83

    Three vertices of a parallelogram PQRS are P(3, –1, 2), Q (1, 2, –4) and R (- 1, 1, 2). Find the coordinates of the fourth vertex.

    Solution

  • Question 5
    2 / -0.83

    A point R with x-coordinate 1 lies on the line segment joining the points P(-2, 3,5) and Q (7, 0, -1). The coordinates of the point R are

    Solution

    The coordinates of points P and Q are given as P(2,−3,5) and (7,0,-1)
    Let R divide line segment PQ in the ratio k:1
    Hence by section formula, the coordinates of point R are given by,
    (k(7)+2/k+1,k(0)−3/k+1, k(-1)+5/k+1)
    =(7k+2/k+1, −3/k+1, -1k+5/k+1)
    It is given that the x-coordinate of point R is 1.
    ∴7k+2/k+1=1
    ⇒7k+2=k+1
    ⇒6k=-1
    ⇒k=-1/6
    Hence the coordinates of R are (1,2,3).

  • Question 6
    2 / -0.83

    If the origin is the centroid of the triangle ABC with vertices A (2a, 14, 6), B (8, 3b, -10) and C(-4, 2, 2c), then the values of a and c are.

    Solution

    The coordinates of the centroid of △ABC
    =[(2a −8+4)/3 , (3b+14+2)0/3 , (6 −10+2c)/3]
    =[(2a-4)/3 , (3b+16)/3 , (2c −4)/3]​
    It is given that origin is the centroid of △ABC
    ∴(0,0,0)=[(2a+4)/3 , (3b+16)/3 , (2c −4)/3]
    (2a+4)/3 = 0 , (3b+16)/3 = 0and (2c −4)/3 = 0
    ⇒a=−2 and c=2

  • Question 7
    2 / -0.83

    If the origin is the centroid of the triangle PQR with vertices P(2a, 2, 6), Q(-4, 3b, -10) and (8, 14, 2c), then the values of a, b and c are:

    Solution

    The coordinates of the centroid of △PQR
    =[(2a −4+8)/3 , (2+3b+14)/3 , (6 −10+2c)/3] =((2a+4)/3, (3b+16)/3 ,(2c −4)/3)
    It is given that origin is the centroid of △PQR
    ∴(0,0,0)=((2a+4)/3, (3b+16)/3, (2c −4)/3)
    ⇒(2a+4)/3 =0, (3b+16)/3 = 0 and (2c −4)/3=0
    ⇒a =−2,b =−16/3 and c = 2

  • Question 8
    2 / -0.83

    The ratio in which the join of points (1, –2, 3) and (4, 2, –1) is divided by XOY plane is:

    Solution

    Let P be the point where the line joining the given two points (1,−2,3) and (4,2,−1) intersects the X −Y plane in m:n ratio. We are to find m:n.
    Now the co-ordinate of the point P be [(4m+n)/m+n , (2m −2n)/m+n , (−m+3n)/m+n)].
    As the point P lies on the X −Y plane, (−m+4n)/m+n = 0
    or, −m+3n=0
    or, m/n = 3/1
    or, m:n = 3:1

  • Question 9
    2 / -0.83

    The coordinates of the point R which divides the line segment joining two points P (x1 , y1 , z1 ) and Q (x2 , y2 , z2 ) externally in the ratio m : n are given by

    Solution

    Using section formula
     The coordinates of point R that divides the line segment joining points P (x1 , y1 , z1 ) and Q (x2 , y2 , z2 ) externally in the ratio m: n are .

  • Question 10
    2 / -0.83

    The ratio in which the line joining the points (1, 2, 3) and (-3.4, -5) is divided by the xy-plane is:

    Solution

    Since line is divided by xy plane
    so z=0
    for z axis
    0=-5k+3 (1)/k+1
    -5k+3=0
    k=3/5
    ratio = 3:5

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