Excretory Products and their Elimination Test

Result

Excretory Products and their Elimination Test - 4

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
4 / -1

Which of the following is an incorrect match?

A
Bowman's capsule - Glomerular filtration

B
DCT - Absorption of glucose

C
Henle's loop - Concentration of urine

D
PCT - Absorption of Na⁺ and K⁺ ions

Solution

In DCT (distal convoluted tubule) reabsortion of sodium ions, chloride ions and water occurs.
Question 2
4 / -1

If Henle's loop were absent from mammalian nephron, which of the following is to be expected?

A
There will be no urine formation.

B
There will be hardly any change in the quality and quantity of urine formed.

C
The urine will be more concentrated.

D
The urine will be more dilute.

Solution

Henle's loop is a U-shaed part of nephron a start at the end of proximal convoluted tubule are consists of descending limb and ascending limb. Concave current mechanism in Henle's loop and vasa recta to convertrate the urine. Maintenance of concentration gradient in the medullar interstitial fluid by the concave form the filtrate present in the collecting duct so that the concentratin of the filtrate (urine) is increased. Therefore, if Henle's loop was absent from mammalian nephew urine will be more dilute.
Question 3
4 / -1

Read the given statements and select the correct option.
Statement 1: The final reabsorption of water from the urine into the blood occurs through the collecting duct of a mammaian nephron resulting in the production of hyperosmotic urine.
Statement 2: The loop of Henle creates a sodium gradient in the interstitial fluid.

A
Both statements 1 and 2 are correct and statement 2 is the correct explanation of statement 1.

B
Both statements 1 and 2 are correct but statement 2 is not the correct explanation of statement 1.

C
Statement 1 is correct and statement 2 is incorrect.

D
Both statements 1 and 2 are incorrect.

Solution

The counter current mechanism in loop of Henle and vasa recta, helps in maintaining an increasing osmolarity of the interstitial fluid i.e. form 300 mOsmoL^-1in the cortex is about 1200 mOsmolL^-1 in the inner medulla. This gradient is mainly caused by NaCl and urea. This gradient thus helps in easy reabsorption of water from the filtrate in the collecting duct so as to produce hyperosmotic urine.
Question 4
4 / -1

Read the given statements and select the correct option.
Statement 1 : In the descending limb of loop of Henle, the urine is hypertonic, while in the ascending limb of loop of Henle, the urine becomes hypotonic.
Statement 2 : Descending limb is impermeable to Na⁺, while ascending limb is impermeable to H₂O.

A
Both statements 1 and 2 are correct and statement 2 is the correct explanation of statement 1.

B
Both statements 1 and 2 are correct but statement 2 is not the correct explanation of statement 1.

C
Statement 1 is correct and statement 2 is incorrect.

D
Both statements 1 and 2 are incorrect.

Solution

The descending limb is permeable to water but almost impermeable to electrolytes (sodium ions) and ascending limb is permeable to electrolytes (sodium ions) but impermeable to water, therefore when the filtrate through the descending limb it becomes hypertonic and as it passes through the ascending limb it becomes hypotonic.
Question 5
4 / -1

Match Column-I with Column-II and select the correct option from the codes given below.
Column-I
(A) PCT
(B) DCT
(C) Loop of Henle
(D) Counter-current mechanism
(E) Renal corpuscle
Column-II
(i) Concentrated urine formation
(ii) Filtration of blood
(iii) Reabsorption of 70-80% electrolytes
(iv) Ionic balance
(v) Maintenance of concentration gradient in medulla

A
A-(iii), B-(iv), C-(i), D-(v), E-(ii)

B
A-(iii), B-(v), C-(iv), D-(ii), E-(i)

C
A-(i), B-(iii), C-(ii), D-(v), E-(iv)

D
A-(iii), B-(i), C-(iv), D-(vi), E-(ii)