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Some Basic Concepts Of Chemistry Test - 1

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Some Basic Concepts Of Chemistry Test - 1
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  • Question 1
    4 / -1

    The prefix used for 10-18 is:

    Solution

    The prefix used for 10-18 is atto-

    Additional Information:metric prefix is a unit prefix that precedes a basic unit of measure to indicate a multiple or submultiple of the unit. Each prefix has a unique symbol that is prepended to any unit symbol. Some important prefixes are given below: 

    What is a prefix ? Give some common prefixes for multiples and submultiples  - CBSE Class 11 Physics - Learn CBSE Forum

  • Question 2
    4 / -1

    One atomic mass unit (amu) is closest to:​

    Solution

    • An atomic mass unit (symbolized AMU or amu) is defined as precisely 1/12 the mass of an atom of carbon-12.
    • The carbon-12 (C-12) atom has six protons and six neutrons in its nucleus.
    • In imprecise terms, one AMU is the average of the proton rest mass and the neutron rest mass.
    • 1 AMU = 1.67377 x 10 -27 kilogram or 1.67377 x 10 -24 gram.

  • Question 3
    4 / -1

    The number of base SI units is:

    Solution

    The standard units of measurement defined by the ISU for the seven base quantities are SI base units All other SI units are derived from it.

    Additional Information: 7 Basic SI units with their quantities are: 

     

  • Question 4
    4 / -1

    The SI unit of time is:

    Solution

    The S.I. unit of time is second(s).
    Additional Information: A second can be defined as  1/86400th part of a mean solar day,  i.e., =1/86400 × one mean solar day.

  • Question 5
    4 / -1

    The two effective drugs which act as life-saving drugs for cancer therapy and AIDS victims respectively are:

    Solution

    • Cisplatin is particularly effective against testicular cancer.
    • Taxol (paclitaxel) is a mitotic inhibitor used in cancer chemotherapy.
    • AZT is used for helping AIDS victims.

    Additional Information: Its mode of action has been linked to its ability to crosslink with the purine bases on the DNA; interfering with DNA repair mechanisms, causing DNA damage, and subsequently inducing apoptosis in cancer cells. 

  • Question 6
    4 / -1

    Which of the following statements is/are correct?

    Solution

    • A molecule is made up of atoms bonded together. 
    • The law of definite proportions, sometimes called Proust's law, or the law of constant composition states that a given chemical compound always contains its component elements in a fixed ratio (by mass) and does not depend on its source and method of preparation.

    Since both statements A and B are correct, the correct option is D. 

  • Question 7
    4 / -1

    The coefficient in 6.65 × 104 is:

    Solution

    Here, 6.65 is the coefficient and 10is the exponent.

    Explanation: A coefficient is a number or an alphabet that is multiplied by a variable of a single term or the terms of a polynomial. For example, in the term 7x, 7 is the coefficient. 

  • Question 8
    4 / -1

    The ‘Candela’ is the unit of:

    Solution

    • Luminous intensity is a measure of the wavelength-weighted power emitted by a light source in a particular direction per unit solid angle.
    • The SI unit of luminous intensity is the candela, an SI base unit.

  • Question 9
    4 / -1

    The number of significant figures in 3256 is:

    Solution

    • The significant figures of numbers are digits to convey the meaning that contributes to its measurement resolution.
    • Non-zero digits are always significant.
    • Here, 3256, this number has four non-zero numbers.
    • That's why it has four significant figures.

  • Question 10
    4 / -1

    The SI unit of electric current is:

    Solution

    • Electric current is defined as the rate of flow of charge
    • Since the charge is measured in coulombs and time in seconds, the electric current unit is Coulomb/Sec ( C/s )
    • Where, coulomb/sec is defined as Ampere

    So the Ampere is the SI unit of the current.

  • Question 11
    4 / -1

    A number of significant figures in 0.001520 is:

    Solution

    • The significant figures of numbers are digits to convey the meaning that contributes to its measurement resolution.
    • Non-zero digits are always significant.
    • Here, the number of Significant figures in 0.001520 is 4.

  • Question 12
    4 / -1

    If the true value for a result is 2.00 g and a student takes 2 measurements and reports the results as 1.95 g and 1.93 g, then we can conclude that:​

    Solution

    • Precision indicates how closely repeated measurements match each other.
    • Since both the values are close to each other, they are precise and since there is a difference between the mean value and true value, they are not accurate.

  • Question 13
    4 / -1

    The unit of amount of substance is:

    Solution

    • The mole, denoted by the symbol mol, is the SI unit of the amount of substance.
    • One mole contains exactly 6.022 140 76 x 1023 elementary entities.
    • This number is the fixed numerical value of the Avogadro constant, NA, when expressed in the unit mol–1 and is known as the Avogadro number.
    • The value of Avogadro’s number is fixed and the value is NA = 6.022 x 1023.

  • Question 14
    4 / -1

    Out of the numbers: 6.26, 5.8, 0.00267, 0.03, the one with the least significant figures is:​

    Solution

    • The significant figures of numbers are digits to convey the meaning that contributes to its measurement resolution.
    • Non-zero digits are always significant.
    • 6.26 & 0.00267 contains 3 significant figures while 5.8 has two significant figures and 0.03 contains least that is 1.

    Therefore, the correct answer is 0.03

  • Question 15
    4 / -1

    If the true value for a result is 3.00 m and a student records two readings as 3.01 m and 2.99 m, then we can conclude that:​

    Solution

    • Precision indicates how closely repeated measurements match each other.
    • Accuracy indicates how closely a measurement matches the correct or expected value.

    Since the readings closely match the result and the expected value, the correct answer is that the values are both accurate and precise. 

  • Question 16
    4 / -1

    The number of significant figures in 3.1205 are:

    Solution

    The answer is 5 because all non zero digits and zero between the non zero digits are significant.

  • Question 17
    4 / -1

    The scientific notation for 0.00016 is:​

    Solution

    Move the decimal point to the right of 0.00016 up to 4  places.

    The decimal point was moved 7 places to the right to form the number 1.6

    Since the numbers are less than 10 and the decimal is moved to the right, so we use a negative exponent here.

    ⇒ 0.00016 = 1.6 × 10-4

    Explanation: 

    • Scientific notation is a form of presenting very large numbers or very small numbers in a simpler form.
    • Scientific notation is used to represent the numbers that are very huge or very tiny in a form of multiplication of a single-digit number and 10 raised to the power of the respective exponent.
    • The exponent is positive if the number is very large and it is negative if the number is very small. 

  • Question 18
    4 / -1

    Suppose the elements X and Y combine to form two compounds XY2 and X3Y2. When 0.1 mole of XY2 weighs 10 g and 0.05 mole of X3Y2 weighs 9 g, the atomic weights of X and Y are:

    Solution

    Let atomic weight of element X is x and that of element Y is y.

  • Question 19
    4 / -1

    If we add the numbers 6.68 and 0.8, the result will be:​

    Solution

    The correct option is B

    7.5

    In addition, the result cannot have more digits to the right of the decimal point than either of the original numbers.

    Since there is only 1 digit after the decimal point in 0.8 so the result 7.48 should be rounded off to 1 decimal point i.e. 7.5.

  • Question 20
    4 / -1

    Molecular mass of glucose molecule (C6H12O6) is:

    Solution

    Molecular mass: The sum of the atomic masses of all the atoms in a molecule of a substance is called the molecular mass of the molecule.

    Generally, we use relative atomic masses of atoms for calculating the molecular mass of 1 mole of any molecular or ionic substances.

    The molecular formula of glucose is C6H12O6

    • The atomic mass of H = 1
    • The atomic mass of C = 12
    • The atomic mass of O = 16

    Molecular mass of C6H12O6 = 12 (Atomic mass of Hydrogen) + 6(Atomic mass of carbon) + 6(Atomic mass of oxygen)

    = 12 × 1 + 6 × 12 + 6 × 16

    = 12 + 72 + 96 = 180 u.

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