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The p-Block Elements Test - 1

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The p-Block Elements Test - 1
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  • Question 1
    4 / -1

    Inert pair effect of p-block elements is due to the

    Solution

    Due to the presence of inner lying d and f electrons oxidation state which is 2 unit less than the group oxidation state become popular.

  • Question 2
    4 / -1

    The elements of group 14 are slightly more electronegative than group 13 elements because of

    Solution

    As we move along the period electronegativity increases due to increase in nuclear charge.

  • Question 3
    4 / -1

    In which of the following compounds, nitrogen exhibits highest oxidation state?

    Solution

  • Question 4
    4 / -1

    The function of Fe (OH)3 in the contact process is

    Solution

    Fe (OH)3 is used to remove arsenic impurities.

  • Question 5
    4 / -1

    In general, nonmetals as compared to metals have

    Solution

    Non metals have high value of ionization energy while metals have comparatively low value of ionization energy.

  • Question 6
    4 / -1

    Among the following which is the strongest oxidizing agent?

    Solution

    F2 is very strong oxidizing agent.

  • Question 7
    4 / -1

    The compounds formed by highly reactive non-metals with highly reactive metals are generally

    Solution

    Compunds formed by highly reactive non metals and metals is ionic bond.

  • Question 8
    4 / -1

    A compound X, of boron reacts with NH3 on heating to give another compound. Y which is called inorganic benzene. The compound X can be prepared by treating BF3 with Lithium aluminium hydride. The compounds X and Y are represented by the formulas.

    Solution

    BF3 reacts with LiAlH4 to form B2H6 which reacts with NH3NH3 in 1:2 ratio forming B3N3H6( Borazine , inorganic benzene

  • Question 9
    4 / -1

    Three reactions involving  are given below  

    B.

    C.   

     

    In which of the above does  act as an acid?

    Solution

    in B only  is losing its proton therefore act as acid.

  • Question 10
    4 / -1

    When Cl2 gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from

    Solution

    The correct answer is option D
    The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is
    3Cl2​ + 6NaOH⟶NaClO3​+ 5NaCl+3H2​O
    Oxidation number of Cl is 0 in Cl2​, −1 in NaCl and +5 in NaClO3​
    So the oxidation number of chlorine changes from Zero to -1 and Zero to +5.
     

  • Question 11
    4 / -1

    As we move from B to Al in the p-block elements the sum of the first three ionisation enthalpies

    Solution

    On moving from B to Al size increases so sum of ionization energies also decreases.

  • Question 12
    4 / -1

    The non-metal oxides are:

    Solution

    nonmetallic oxides are either neutral or acidic. Example CO is neutral while CO2 is acidic.

  • Question 13
    4 / -1

    Dry ice is

    Solution

    Dry ice is solid CO2

  • Question 14
    4 / -1

    The tendency of BF3, BCl3 and BBr3 to behave as Lewis acid decreases in the sequence:

    Solution

    because in BF3 there is backbonding which decreases its acidity. And as we for from BF3 to BBr3 tendency of back bonding decreases so acidity increases,.

  • Question 15
    4 / -1

    Of the following compounds the most acidic is

    Solution

    More is the oxidation number greater is the acidity of oxide

  • Question 16
    4 / -1

    Boron forms only covalent compounds and not +3 ions because

    Solution

    Due to smaller size and high nuclear charge B has very high ionization energy value so doesnot show +3 oxidation state

  • Question 17
    4 / -1

    The element having the noble gas plus 14 f- electrons plus 10 d-electron cores

    Solution

    Tl have bole gas + 14 f +10 d electrons.

  • Question 18
    4 / -1

    In trivalent state, for example, the trichlorides, being covalent are hydrolysed in water form

    Solution

    trihalides hydrolysis to form tetrahedral structure

  • Question 19
    4 / -1

    Which of the following statements regarding ozone is not correct?

    Solution

    Bond order of O-O bond in ozone is less than that in oxygen.
    Due to resonance the bond order in ozone is 1.5, hence O---O bond length in O3​ is greater than O---O bond length in O2​.

  • Question 20
    4 / -1

    XeF2 is isostructural with

    Solution

    The correct answer is option D

    XeF2 is isostructural with ICl2−.
    Both contain the same number of lone pairs and bond pairs on the central atom.
    There are 3 lone pairs and 2 bond pairs.
    This results in linear geometry.

  • Question 21
    4 / -1

    Aqueous solution of Na2S2O3 on reaction with Cl2 gives

    Solution

    Aqueous Na2S2O3 on reaction with Cl2Cl2 produces NaHSO4

  • Question 22
    4 / -1

    Which noble gas is most abundant in atmosphere? 

    Solution

    Argon

    Argon is most abundant in composition of air percent by volume. It is in 0.934% in composition of air and is one of the major gas in the Earth's atmosphere.

  • Question 23
    4 / -1

    Aqueous solution of Na2S2O3 on reaction with Cl2 gives

    Solution

    Sodium thiosulphate, Na2S2O3 gets oxidised by chlorine water

    Na2S2O3 + 4Cl + 5H2O → 2NaHSO4 + 8HCl

    Na2S2O3 get oxidised by FeCl3 into Na2S4O6

    2Na2S2O3 + 2FeCl3 → Na2S4O6 + 2FeCl2 + 2NaCl

    Further Na2S2O3 decomposes on treatment with dilute acids

    Na2S2O3 + 2HCl → 2NaCl + SO2 + S + H2O.

  • Question 24
    4 / -1

    One of the following p-block elements has unusually low melting point

    Solution

    Ga has very low melting point.

  • Question 25
    4 / -1

    In the manufacture of sulphuric acid by contact process Tyndall box is used to

    Solution

    In the manufacture of sulphuric acid by contact process, Tyndall box is used to. remove impurities. Solution : Tyndall box is for testing the presence of dust particles.

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