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Hydrocarbons Te...

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  • Question 1
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    Which molecule will give the following dicarboxylic acid upon treatment with acidic solution of KMnO4?

  • Question 2
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    Propose major product of the following reaction.

  • Question 3
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    An  optically active alky bromide X (C6H13Br) upon treatment with ethanolic KOH solution forms two alkenes Y and Z with their molecular formula (C6H12). Y and Z are positional isomers. Z upon treatment with cold, dilute alkaline KMnO4 solution gives a meso-diol. Hence, X is

  • Question 4
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    Which starting material should be used to produce the compound shown below?

  • Question 5
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    When reacted with an alkene, which of the following reagent would not introduce I atleast one hydroxyl (— OH) group into final product?

  • Question 6
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    0.92 g of an organic compound was analysed by combustion method. The mass of the U-tube increased by 1.08 g. What is the percentage of hydrogen in the compound?

  • Question 7
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    An organic compound gave 0.4655 g of CO2 on complete combustion. If the mass of the compound taken was 0.2115 g, what is the percentage of C in it?

  • Question 8
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    In kjeldahl's method of estimation of nitrogen, nitrogen is quantitatively converted to ammonium sulphate. It is the treated with the standard solution of alkali. The nitrogen which is present is estimated as:

     

  • Question 9
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    2.18 g of an organic compound containing sulphur produces 1.02g of BaSO4. Thepercentage of sulphur in the compound is

  • Question 10
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    Direction (Q. Nos. 10-14) This section contains 2 paragraphs, each describing theory, experiments, data, etc. Six questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

    Passage I

    An unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.

     

    Q. The correct statement concerning X is

  • Question 11
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    Passage I

    An unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.

    Q.
    What is true regarding reaction of Y with cold, dilute alkaline KMnO4 solution?

  • Question 12
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    Passage I

    An unknown compound X (C5HgBr) does not decolourise purple colour of alkaline permanganate solution. Upon treatment with C2H5OK/C2H5OH, X gives Y (C5H8) as only structural isomer. Catalytic hydrogenation of Y gives methyl cyclobutane. Ozonolysis of Y gives Z (C5H8O2) which can exist as a pair of enantiomers.

     

    Q. What is correct skeleton of Z? 

  • Question 13
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    Passage II

    An organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.

     

    Q. The structure of compound X is

  • Question 14
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    Passage II

    An organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.

     

    Q. The correct statement regarding produces) formed by the reaction of X with HBr in th e presence of H2O2 is

  • Question 15
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    Passage II

    An organic compound X (C7H11Br) shows optical isomerism as well as decolourises brown colour of bromine water solution. X on treatment with HBr in the absence of a peroxide forms a pair of diastereomers, both of them are optically active. Also, X with C2H5ONa in C2H5OH gives a single product Y (C7H10). Y on treatment with ozone followed by reduction with (CH3)2S gives 1, 3,-cyclopentanedione as one product.

     

    Q. The correct statement concerning product(s) formed when Y is treated with excess of HCI is

  • Question 16
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    Direction (Q. Nos. 16 - 19) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

     

    Q. 
    How many different isomers of alkene (X)can give the above reaction?

     

  • Question 17
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    If all stereoisomers of 2-pentene are treated with cold, dilute and alkaline KMn04 solution, how many different diols would be expected?

     

  • Question 18
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    If 4-methyl cyclopentene is treated with OsO4 followed by work-up with NaHSO3/H2O, how many different diols would result?

     

  • Question 19
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    A mixture containing all the stereoisomers of 3, 4, 5-trimethyl cyclopentene is treated with O3 followed by Zn-hydrolysis, how many different isomers of products would result?

     

  • Question 20
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    Direction (Q. Nos. 20 and 21) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

    Statement I :  In reductive ozonolysis, dimethylsulphide is better reducing reagent than Zn- H2O.
    Statement II : (CH3)2S brings about homogeneous catalysis.

  • Question 21
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    Statement I :  cis-2-butene with cold, dilute, alkaline KMnO4 gives meso-2,3- butanediol.
    Statement II :  In alkaline solution, under cold condition, KMnO4 acts as a mild oxidising agent.

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