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Hydrocarbons Test - 9

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Hydrocarbons Test - 9
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  • Question 1
    4 / -1

    The electrophile in sulphonation of benzene using fuming sulphuric acid is

    Solution

     

    The correct answer is Option B.
    Fuming sulphuric acid, H2S2O7, can be thought of as a solution of SO3 in sulphuric acid - and so is a much richer source of the SO3. Sulphur trioxide is an electrophile because it is a highly polar molecule with a fair amount of positive charge on the sulphur.

     

  • Question 2
    4 / -1

    In nitration of benzene using cone. H2SO4 and cone. HNO3, the role of nitric acid is

    Solution

    The correct answer is Option B.
    Nitration is electrophilic substitution reaction; in its first step HNO3 takes protons from sulphuric acid and then forms −NO2+ so here HNO3 acts as base.
     
    Mechanism of reaction as shown

  • Question 3
    4 / -1

    The increasing order of reactivity of the following compounds towards electrophilic aromatic substitution reaction is

  • Question 4
    4 / -1

    What is the correct increasing order of reactivity of the following compounds towards electrophilic aromatic substitution reaction?

    Solution

    The correct answer is option B

  • Question 5
    4 / -1

    What is major product of the reaction below?

    Solution

    The correct answer is option D

  • Question 6
    4 / -1

    Predict major product of the following reaction.

  • Question 7
    4 / -1

    Which of the following act as electrophile in halogenation?

    Solution

    Halonium ion act as electrophile in halogenation. Nitronium ion is used in nitration. Sulphonium ion is used in sulphonation. Acylium ion is used in acylation.

  • Question 8
    4 / -1

    Identify the correct order of reactivity of following towards aromatic electrophilic substitution reaction.

    I. Toluene
    II. Benzene
    III. Chlorobenzene
    IV. Nitrobenzene

    Solution

    The correct answer is Option A
    Toluene is having one methyl group which is an electron-donating group causing a negative charge on the carbon atom of the ring so it is highly reactive towards electrophile which is already electron deficient.
    Benzene has a delocalised set of electron clouds which attracts electrophile while chloro and nitro group are electronegative causing positive charge on carbon atoms so are not reactive towards electrophilic substitution.
    Cl shows -I effect and −NO2 shows a strong electron-withdrawing effect. So least reactive
    a)IV < III < II < I
     

  • Question 9
    4 / -1

    Predict the major product in the following reaction.

    [IIT JEE 2001]

  • Question 10
    4 / -1

    What is true about sulphonation of C6H6?

  • Question 11
    4 / -1

     

    During nitration of benzene, the active nitrating agent is:

     

  • Question 12
    4 / -1

     

    The halogen which is most reactive in the halogenation of alkanes under sunlight is:

    Solution

    The correct answer is Option B.

    Fluorination (155 kJ/mol) seems to have relatively high activation energy. The initial reaction (chain initiation) - that is, the homolytic cleavage of a halogen molecule - must, however, occur only a few times. 
    The subsequent reactions (chain propagation) between a halogen radical and methane, and then between a methyl radical and a halogen molecule, yield another halogen radical. 
    Therefore, one start reaction may initiate thousands of fluorination reactions. In addition, fluorination is very exothermic, the reaction enthalpy is −431 kJ/mol. As a result, the reaction itself provides enough energy for additional initiation reactions.

    Hence, the halogenation of alkanes is violent and very fast in Fluorine.

    So the correct option is B.

     

  • Question 13
    4 / -1

     

    Necessary condition for halogenation in benzene is:

     

    Solution

    THE HALOGENATION OF BENZENE

    This page gives you the facts and a simple, uncluttered mechanism for the electrophilic substitution reaction between benzene and chlorine or bromine in the presence of a catalyst such as aluminium chloride or iron.

     

  • Question 14
    4 / -1

     Which among these is not a representative arene compound?

  • Question 15
    4 / -1

     

    Nitration of benzene by nitric acid and sulphuric acid is:

     

  • Question 16
    4 / -1

    Direction (Q. Nos. 16 - 21) This section contains 2 paragraphs, each describing theory, experiments, data, etc. Six questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

    Passage I

    Consider the following road-map reaction,

     

    Q. The most likely structure of A is

  • Question 17
    4 / -1

    Passage I

    Consider the following road-map reaction,

     

    Q. What is correct about D?

  • Question 18
    4 / -1

    Passage I

    Consider the following road-map reaction,

     

    Q. If A is treated with cone. HNO3 and cone. H2SO4 mixture, mononitration at phenyl ring takes place. What is the structure of major nitration product?

  • Question 19
    4 / -1

    Passage II

    Consider the following road-map reaction,

     

    Q. The most likely structure of A is

  • Question 20
    4 / -1

    Passage II

    Consider the following road-map reaction,

     

    Q. What is true about C?

  • Question 21
    4 / -1

    Passage II

    Consider the following road-map reaction,

     

    Q. What is the structure of E?

  • Question 22
    4 / -1

     

    Direction (Q. No. 22 - 25) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

    Q. C6H4Br2(P) is a dibromo benzene and it is the less polar isomer of its two polar isomers. If P is treated with conc. HNO3 and conc -H2SO4 mixture, in principle, how many mono nitration products are expected?

     

  • Question 23
    4 / -1

     

    How many isomers of C7H8O exists that has a phenyl ring?

     

    Solution

     

    C7H8 is toluene: that’s the only benzenoid isomer possible. To get C7H8O, you must mentally “insert an oxygen atom” somewhere.
    There are 5 ways you can mentally insert an oxygen atom into a C-C or C-H bond of toluene.
    So the isomers of C7H8O are:
    2-methylphenol = o-cresol
    3-methylphenol = m-cresol
    4-methylphenol = p-cresol
    benzyl alcohol = phenylmethanol = (hydroxymethyl)benzene
    methoxybenzene = anisole = methyl phenyl ether

     

  • Question 24
    4 / -1

     

    If the following compound is treated with Br2-Fe, how many mono bromination products are formed in principle?

     

    Solution

     

    The correct answer is:

     

  • Question 25
    4 / -1

     

    How many of the following have an activated aromatic ring for electrophilic substitution reaction?


     

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