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Solid State Test - 4

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Solid State Test - 4
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  • Question 1
    4 / -1

    For the structure given below the site marked as S is a
    For the structure given below the site marked as S is a:

    Solution

    Octahedral voids occupy the position of edge centre and body centre.

  • Question 2
    4 / -1

    Which of the following statements is not about the voids?

    Solution

    Octahedral sites are created by overlapping two equilateral triangles with apices in opposite directions.

  • Question 3
    4 / -1

    In ABC packing if the number of atoms in the unit cell is n then the number of tetrahedral voids in the unit cell is equal to:

    Solution

    Number of tetrhedral voids per atom in a unit cell is 2.
    Hence the total numberof tetrahedral voids =2n.

  • Question 4
    4 / -1

    If the radius of an octahedral void is r and the radius of atoms in close packing is R, then the relation between r and R is :

    Solution


    (2R)2 = (R + r)2 + (R + r)2
    √2 R = R + r
    (√2 - 1)R = r
    0.414R = r

  • Question 5
    4 / -1

    A metal crystallises into a lattice containing a sequence of layers as AB AB AB ... . What percentage of voids are left in the lattice?

    Solution

    ABAB packing is hexagonal closepacking in which all atoms occupy 74% of the total space. Hence, 26% of voids are left in the lattice.

  • Question 6
    4 / -1

    In ccp arrangement the pattern of successive layers can be designated as

    Solution

    In ccp pattern, fourth layer is identical to first layer.

  • Question 7
    4 / -1

    Which of the following statements is not correct about hexagonal close packing?

    Solution

    The coordination number is 12

  • Question 8
    4 / -1

    A crystalline structure has radius ratio (r+/r-)  in the range of 0.225 - 0.414. The coordination number and arrangement of anions around the cations are:

    Solution

    If the radius ratio is between 0.225 and 0.414, it will have a tetrahedral void. The derivation of this actually takes place in reverse where we assume a tetrahedral void and arrive at the value, but the converse also holds true. A tetrahedral void naturally means there are 4 surrounding atoms. So, coordination number will be 4.

  • Question 9
    4 / -1

    A Crystal lattice with alternate +ve "and "-veions has radius ratio of 0.524. The coordination number of lattice is

    Solution

    Coordination number of crystal lattices which fall in the range of 0.414 - 0.732 is 6.

  • Question 10
    4 / -1

    A solid AB has a rock salt structure. If radius of cation A+ is 120 pm, what is the minimum value of radius of B− anion?

    Solution

    Limited Ratio 

    ⟹rB− = 290 pm

  • Question 11
    4 / -1

    A crystal formed by two elements X and Y in cubic structure. X atoms are at the corners of cube while Y atoms are at the face center. The formula of he compound will be:

    Solution

    No. of X atom (at the corners) = 1/8 x 8 = 1
    No. of Y atoms (fcc) = 6 × 1/2 = 3
    hence, the formula is XY3 

  • Question 12
    4 / -1

    If three elements X,Y and Z crystallizes in a ccp lattice with the X atoms at the corner, Y atoms at the cube centre and Z atom at the edge centre the formula of the compound will be:

    Solution

    No. of X atoms = 1/8 x 8 = 1
    No. of Y atoms = 1
    No. of Z atoms = 12 x 1/4 = 3
    Formula of the compound = XYZ3

  • Question 13
    4 / -1

    A compound is formed by two elements Y and Z. The element Z forms ccp and atoms Y occupy 1/3rd of tetrahedral voids. The formula of the compound is

    Solution

    Suppose no. of atoms of Z = a

    No. of tetrahedral voids = 2a

    No. of atoms of Y = 1/3 × 2a = 2a/3

    Ratio of atoms of y and Z= 2a/3 : a = 2:3

    Hence, the formula of the compound = Y2Z3

  • Question 14
    4 / -1

    A cubic solid is made up of two elements P and Q. Atoms of P are present at the corners of the cube and atoms of Q are present by body centre. What is the formula of the compound and what are coordination number of P and Q?

    Solution

    No. of atoms of P = 8 x 1/8 = 1
    No. of atoms of Q = 1 x 1 = 1
    The formula of the compound is PQ. Coordination no. of P and Q = 8:8

  • Question 15
    4 / -1

    How many chloride ions are surrounding sodium ion in a sodium chloride crystal?

    Solution

    Each Na+ ion is surrounded by 6 Cl-ions and each Cl- ion is surrounded by 6 Na+ ions in NaCl crystal.

  • Question 16
    4 / -1

    In NaCl structure,

    Solution

    Octahedral sites are occupied by Na+ ions in NaCl structure.

  • Question 17
    4 / -1

    NaCl type crystal (with coordination no. 6:6) can be converted into CsCl type crystal (with coordination no. 8:8) by applying:

    Solution

    Increase of pressure increases coordination number. Hence, by applying high pressure, NaCl type crystal can be changed into CsCl type crystal

  • Question 18
    4 / -1

    Coordination number of Cs+ and Cl- in CsCl crystal are:

    Solution

    CsCl has a bcc structure. Each Cs ion is surrounded by 8 Cl− ions and each Cl− ion is surrounded by 8 Cs+ ions. CsCl has a bcc type structure. Thus, the structure has 8 : 8 coordination number.

  • Question 19
    4 / -1

    In zinc blende structure,

    Solution

    ZnS has a ccp structure. S2− ions are present at the corners of the cube and centre of each face. Zn2+ ions occupy half of the tetrahedral sites. Each Zn2+ ion is surrounded by four S2− ions and each S2− ion is surrounded by four Zn2+ ions.

  • Question 20
    4 / -1

    Consider the unit cell given below :

    The unit cell shown in the figure belongs to

    Solution

    ZnS has a ccp structure. S2- ions at the corners of the cube and centre of each face. Zn2+ ions occupy half of the tetrahedral sites. Each Zn2+ ion is surrounded by four S2- ions and each S2- ion is  surrounded by four Zn2+ ions.

  • Question 21
    4 / -1

    Consider the unit cell given below :

    The coordination number of Y will be

    Solution

    Coordination no. of Y (Zn2+) is 4.

  • Question 22
    4 / -1

    Consider the unit cell given below :

    Which of the following about the above structure is not correct?

    Solution

    Each X ion is surrounded by 4Y ions.

  • Question 23
    4 / -1

    In  CaF2 type (fluorite structure),  Ca2+ ions form__(A)___ structure and F ions are present in all  __(B)___ voids. The coordination number of Ca2+ is ___(C)___ and F−  is___(D)____.
    (A), (B), (C) and (D) respectively are:

    Solution

    Ca2+ ions form ccp structure while F- ions in all tetrahedral holes and coordination numbers are 8 and 4.

  • Question 24
    4 / -1

    A unit of BaCl2 (fluorite structure) is made up of:

    Solution

    In fluorite structure, cations form ccp structure and anions are present in all tetrahedral holes. Hence, no. of Ba2+ ions =8 and no. of Cl− ions = 4

  • Question 25
    4 / -1

    Which of the following structures is not correctly matched ?

    Solution

    In NaCl type, Cl− ions form ccp structures while Na+ ions are present in all octahedral voids.

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