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Solid State Test - 6

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Solid State Test - 6
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  • Question 1
    4 / -1

    An element cyrstallises in a structure having a fcc unit cell of and edge 200 pm. Calculate its density if 200 g of this element contains 24 x 1023 atoms.

    Solution

    Molar mass = 
    = 50.19gmol−1 for fcc,  Z = 4, V = a3 =(200×10−10)3 
    d = 
    = 41.66g cm3

  • Question 2
    4 / -1

    A unit cell of sodium chloride has four formula units. The edge length of the unit cell is 0.564 nm. What is the density of sodium chloride?

    Solution

    d = 
    = 2.16 gcm−3

  • Question 3
    4 / -1

    The distance between Na+ and CI- ions in NaCl with a density 3.165 g cm-3 is

    Solution



    a3 = 122.77 × 10−24cm3
    a = 4.97 × 10−8 cm or 497 pm
    Distance between Na+ and Cl = a/2
    = 497/2
    = 248.5 pm

  • Question 4
    4 / -1

    The unit cell of aluminium is a cube with an edge length of 405 pm. The density of aluminium is 2.70 g cm-3. What is the structure of unit cell of aluminium?

    Solution


    ⇒ 2.70 = 
    Z = 4
    Hence, structure of aluminium unit cell is fcc or face- centred.

  • Question 5
    4 / -1

    The density of a metal which crystallises in bcc lattice with unit cell edge length 300 pm and molar mass 50 g mol-1 will be

    Solution


    For bcc structure, Z = 2
    d = 
    = 6.15 g cm-3

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