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Chemical Kinetics Test - 7

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Chemical Kinetics Test - 7
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  • Question 1
    4 / -1

     

    The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be (Given, R = 8.314 J K-1 mol-1, log2 = 0.3010).

     

    Solution

     


     

  • Question 2
    4 / -1

    In the following reaction

    N2O  N2+O

    k = (5.0 x 1011 L mol-1 s-1) e -29000R/T, Ea (energy o f activation) is 

    Solution

    By Arrhenius equation


  • Question 3
    4 / -1

    Rate of a reaction can be expressed by Arrhenius equation as k = Ae-EalRT. In this equation, Ea represents.

    Solution


    Ea (activation energy) is the energy required to activate the reactant so that they may collide and give the final product. Below point B, the reactants will not react at all.

  • Question 4
    4 / -1

    In the upper atmosphere, form ation of H2O2 takes place as

    H2O+O → 2OH → H202

    ΔH0 = 72.0 Kj mol-1 ; E= 77.0 kJ mol-1

    Ea for the bim olecular recombination of two OH radicals to form H2O and O is

    Solution



  • Question 5
    4 / -1

    How much rate is affected in the presence of catalyst at 300 K?

    Solution

    k(no catalyst) = Ae -Ea/RT 

    ∴ 

    Thus, rate is affected (28.03) times.
    k1 (no catalyst) = Ae-Ea/RT
    k2 (with catalyst) = Ae-(Ea - 2)/RT 

  • Question 6
    4 / -1

    For a reaction,

    A → Product

    t50  = 100 min at temprature T1

    and t50 = 80 min at temprature T2

    Thus, 

    Solution

    On increasing temperature, number of collisions hence kinetic energy increases.

    Thus, 


    Thus rate of the reaction or rate constant increases with increase in temperature.
    Half-life of any reaction
    Thus, half-life decreases with increase in temperature, reaction may be exothermic or endothermic.
    Thus,   

  • Question 7
    4 / -1

    Rate constant (k) of a reaction has least value at

    Solution

    k varies with temperature as given by Arrhenius equation
     

    k has least value at low 7 and high Ea.

  • Question 8
    4 / -1

    Two reactions with different activation energies have the same rate at room temperature. Which statement correctly describes the rates of these two reactions at the same higher temperature?

    Solution



    If temperature is increased to T`,

    If 
    Thus, reaction with smaller activation energy will be faster on increasing temperature.

  • Question 9
    4 / -1

    The activation energy of the reaction at a given temperature is found to (2.303 RT) J mol-1. The ratio of rate constant to the Arrhenius factor is

    Solution





  • Question 10
    4 / -1

     

    From the given figure, select the correct statement about activation energy.

    Activation energy of

     

    Solution

     

     

    Energy required to take the reactant to the activated state is (E1 + E2). Since, reactions is endothermic, product is less stable.

     

     

  • Question 11
    4 / -1

    The rate of a chemical reaction doubles for every 10°C rise of temperature. If the tem perature is raised by 50°C, the rate of the reaction increases by about

    [AIEEE 2011]

    Solution

    Number of ten degrees in 
    Increase in rate due to 10° rise in temperature = 2
    Increase in rate due to 50° rise in temperature = 25 = 32 times

  • Question 12
    4 / -1

    A reactant A forms two products B and C as given

    A  B, Activation energy Ea1

    A  C, Activation energy Ea2

    if Ea2 = 2Ea1, then k1 and K2 are related as 

    [AIEEE 2011]

    Solution






    ∴ 

  • Question 13
    4 / -1

     

    Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

      Rate constant {k) of a reaction is given by

    Match the given property in Column I with its related value in Column II and select answer from codes given:

     

    Solution

     

    By Arrhenius equation, 

    ∴  
    Thus, (i)→(r)

    Unit of k is in min-1.

    Thus, (ii)→(p)
    At 500 K, 
    k = 10 min-1

    ∴ 
    10 min-1 (0.2M) = 2 M min-1
    Thus (iii)→(q)


    Thus, (iv)→(s)

  • Question 14
    4 / -1

     

    Direction (Q. Nos. 14-17)This section contains 2 paragraphs, which describing theory, experiments, data, etc. Four questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

    Passage I

    For the displacement reaction,

    [Co(NH3)5Cl]2+ (aq) + H2O (l) → [Co(NH3)5H2O]3+ + Cl- (aq)

    The rate constant is given by

    Q. 

    Rate constant at 25°C is 

     

    Solution

     






  • Question 15
    4 / -1

    Passage I

    For the displacement reaction,

    [Co(NH3)5Cl]2+ (aq) + H2O (l) → [Co(NH3)5H2O]3+ + Cl- (aq)

    The rate constant is given by

    Q. 

    Energy of activation for this reaction is

    Solution


    At 298 K, log k (min-1)




  • Question 16
    4 / -1

    Passage II

    For the opposing reaction,

    Ea (forward reaction) = 100 kJ mol-1

    Pre-exponential factor A = 1.0 x 1010 M-1s-1

    Q. 

    The value of k1 and k2 at 700K respectively are

    Solution




    Also,

    =345 M-1s-1




    ∴ 
     

  • Question 17
    4 / -1

    Passage II

    For the opposing reaction,

    Ea (forward reaction) = 100 kJ mol-1

    Pre-exponential factor A = 1.0 x 1010 M-1s-1

    Q. 

    The rate constant (k1) for the forward reaction at 1000 K is

    Solution




    Also,
     
    345 m-1s-1




    ∴ 
     

  • Question 18
    4 / -1

     

    Direction (Q. Nos. 18-20) This section contains 3 questions. When worked out will result in one integer from 0 to 9 (both inclusive).

    At room temperature (27°C) milk turns sour in about 64 h. In a refrigerator at -3°C, milk can be stored x times as long before it sours. The activation energy of the reaction that causes the souring of milk is 11.231 kcal mol-1.
    What is the value of x?

     

    Solution

     

    Rate of souring of milk at 27°C (300 K) is  times faster than at-3°C(270K).
    ∴ 
    ∴ 
    11.231 kcal mol-1 = 2.303 x 2 x10-3 kcal mol-1k-1

  • Question 19
    4 / -1

     

    The Arrhenius equations for the rate constant of decomposition of methyi nitrite and ethyl nitrite are


    Find the temperature (in °C), at which rate contants are equal.

     

    Solution

     

    Both are first order reactions (unit of k beings-1)






     
     

  • Question 20
    4 / -1

     

    For the following sequence of reactions

    Thus, observed Ea is .....kJ mol-1.

     

    Solution

     





    ∴ 

  • Question 21
    4 / -1

     

    The half life of a first order reaction is equal to:

    Solution

     

    The correct answer is Option C

    For a first-order reaction, the half-life is given by: t1/2 = 0.693/k

  • Question 22
    4 / -1

     

    The half life period of first order reaction is 15 min. Its rate constant will be equal to

     

    Solution

     

    The half life of a reaction is 15 min
    So,
    Here we go..
    Formula to be used :

    K =0.693/t = 0.693/15
    __= 0.462/10 = 0.0462 min^-1

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