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Structure of Atom Test - 4

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Structure of Atom Test - 4
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  • Question 1
    4 / -1

     

    Q. FM radio broadcasts at 900 kHz. What wavelength does this corresponds to?

     

    Solution

     

     


     

     

  • Question 2
    4 / -1

    The nucleus of helium contains

    Solution

    A helium nucleus is made of two protons and two neutrons and has a charge +2.

  • Question 3
    4 / -1

    Moseley’s equation is represented as   where, a and b are constants.

    Q. If OA = 1, then atomic number of the element showing frequency of 400 Hz is

    Solution


    Thus, graph is a straight line

     

  • Question 4
    4 / -1

    A gas absorbs photon of wavelength 355 nm and emits at two wavelengths. If one of the emissions is at 680 nm, the other is at

    [AlEEE 2011]

    Solution

    Absorbed energy = Emitted energy



  • Question 5
    4 / -1

    The longest wavelength of light capable of breaking a single (Cl — Cl) bond in Cl2 is if 

    [AlEEE 2010]

    Solution

    ΔH = 242 kJ mol-1



  • Question 6
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    Which of the following conclusions could not be derived from Rutherford’s α-particle scattering experiment?

    Solution

    Option A: Electrons (-) and nucleus (+) are held together by electrostatic forces of attraction.
    Option B: Radius of the atom (= 10-10m) > radius of the nucleus (10-15m).
    Option C: Most of the space is empty as given by the radius of the nucleus and atom.
    Option D: As electron moves in a circular path, it emits energy and ultimately falls into the nucleus.

    Thus, the correct option is D.

  • Question 7
    4 / -1

    Which of the following statements is not correct about the characteristics of cathode rays?

    Solution

    (d) Cathode rays consist of negatively charged material particles called electron. They were discovered by William Crookes. The characteristics of cathode rays do not depend upon the material of electrodes and the nature of the gas present in the cathode ray tube.

  • Question 8
    4 / -1

    Energy of a mole of radio wave photons with a frequency of 909 kHz is

    Solution

    E = N0hv
    ⇒ E = 6.02 x 1023 x 6.62 x 10-34 x 909 x10= 3.62 x 10-4 J

  • Question 9
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    Which of the following energy state is filled by an electron after the completion of 4p orbital?

     

    Solution

     

    When 4p orbital in any atom are filled completely, the next electron goes in 5s(n + l = 5 + 0 = 5) not in 4d(n + l = 4 + 2 = 6),electron first enters into the subshell which is having less (n+l) value (energy). Hence the 5s is filled first than 4d.

     

  • Question 10
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    If Aufbau rule is violated, then Ca20 will be in:

     

    Solution

     

     

  • Question 11
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    After completion of ‘np’ level, the electron enters into which level according to (n + p) rule?

     

    Solution


     

  • Question 12
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    A hypothetical electromagnetic wave is pictured here.

    Q. Energy associated with this wave is

     

    Solution

     

     


    A to E makes one complete wave.


     

     

  • Question 13
    4 / -1

    A hypothetical electromagnetic wave is pictured here.

     

    Q. A standing wave in a string 42 cm long has a total of six nodes (including those at the ends). Wavelength of the standing wave is

    Solution


    A to E makes one complete wave.



    If there are n nodes including those at the ends, in a string of length /, then

  • Question 14
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    Direction (Q. Nos. 14) Choice the correct combination of elements and column I and coloumn II are given as option (a), (b), (c) and (d), out of which ONE option is correct.

     

    Q. The colours of visible light are at different wavelength. Match the wavelengths in Column I with their colours in Column II.

    Solution

    Thus, (i)(700nm) Red (u)
    (ii) (600 nm) - Orange (t)
    (iii) (580 nm) - Yellow (s)
    (iv) (500nm) - Green (r)
    (v) (460 nm) - Blue (q)
    (vi) (400 nm) - Violet (p)

  • Question 15
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    Which of the following properties are similar for isotopes?

     

  • Question 16
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    Solution

     

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