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D and F - Block Elements Test - 4

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D and F - Block Elements Test - 4
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  • Question 1
    4 / -1

     

    Atomic number of second transition series lies from

     

    Solution

     

     

    Since,1st transition series belongs to 3d orbital and 2nd transition series belongs to 4d-orbital. According to the given option, atomic number 39 to 48 (5s24d1-10) belongs to second transition series.

     

     

  • Question 2
    4 / -1

    Which has lower standard reduction potential (SRP) value?

    Solution

    Mn2+/ Mn have - 1.18SRPvalue.

  • Question 3
    4 / -1

    An element has configuration 4d55s2. The element belongs to

    Solution

    Ford-block elements, group number is equal to the number of electrons in (n - 1)d subshell + number of electrons in valence shell (nth shell).

  • Question 4
    4 / -1

    The electronic configuration of palladium is

    Solution

    [Kr]4d105s0

  • Question 5
    4 / -1

    Which has lowest and highest first ionisation enthalpy in 3d series?

    Solution

    Sc (3d4s2)has 631 kJ mol-1 and Zn (3d10 4s2) has 906 kJ mol-1 

  • Question 6
    4 / -1

    The electronic configuration of the element which is just above the element with atomic number 42 in the same group

    Solution

    The element lying above Z = 42 has Z value 24, i.e. chromium. Hence, Cr configuration is [Ar]3d54s1

  • Question 7
    4 / -1

    Which one of the following exists in the oxidation state other than +3?

    Solution

    The correct answer is option C

    Ce exist in the oxidation state other than +3 .

     

    (a) B - Boron has +1 and +3 oxidation state.

    (b) Al - Aluminium has +1,+2 and +3 oxidation state.

    (c) Ce - Cerium has +3 and +4 oxidation state.

    (d) Ga - Gallium has +1 and +3 oxidation state.

    Cerium (Ce) have [Xe] 4f²6s² electronic configuration.

  • Question 8
    4 / -1

    Electronic configuration of a transition element X in +3 oxidation state is [Ar] 3d5 and Y in +2 state is [Ar] 3d8. What are the atom ic numbers of the elements?

    Solution

    Fe (Z = 26) in + 3 oxidation state show Fe3+ ([Ar] 3d5) configuration. Ni(28) in +2 oxidation state show Ni2+([Ar]3d8) configuration.

  • Question 9
    4 / -1

    The atomic radii of Cu and Ag are 1.17 Å and 1.34 Å. The atomic radius of gold is expected to be

    Solution

    Due to lanthanide contraction, Ag and Au have nearly same size.

  • Question 10
    4 / -1

    A red solid is insoluble in water. However, it becomes soluble if some KI is added to water. Heating the red solid in a test tube results in liberation of some violet coloured fumes and droplets of a metal appear on the cooler parts of the test tube. The red solid is  

    Solution

  • Question 11
    4 / -1

     

    Identify the pairs in which one covalent radii of elements are almost similar.

     

    Solution

     

    Due to lanthanide contraction.

     

  • Question 12
    4 / -1

    Which one is of the following is the lightest transition element?

    Solution

    The correct answer is Option B.

    Sc has the lowest density (3.1 g cm−3). It is the lightest transition element.

  • Question 13
    4 / -1

     

    Which of the following have pseudo noble gas configuration?

     

    Solution

     

    An element with pseudo noble gas configuration has 18 electrons in the highest energy level instead of 8.

    Zn2+(28) = 3s2, 3p6, 3d10
     

     

  • Question 14
    4 / -1

    Which one of the following is a diamagnetic ion?

    Solution

    The correct answer is option A,D.
    About two–thirds of all metals crystallize in closest-packed arrays with coordination numbers of 12. Metals that crystallize in an HCP structure include Cd, Co, Li, Mg, Na, and Zn, and metals that crystallize in a CCP structure include Ag, Al, Ca, Cu, Ni, Pb, and Pt.

  • Question 15
    4 / -1

    The number of unpaired electrons in gaseous species of Mn3+, Cr3+ and V3+ respectively are:

     

  • Question 16
    4 / -1

     

    Passage

    The atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.
    The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.

    Q. Which pair of elements has nearly same atomic size? 

     

    Solution

     

     

    Due to lanthanide contraction.

     

     

  • Question 17
    4 / -1

     

    Passage

    The atomic and ionic radii for transition elements are smaller than their corresponding s-block elements and are greater than their corresponding p-block elements. The atomic and ionic radii transition elements for a given series show decreasing trend for first elements constant in the middle and slight increase towards the end. This is due to the combined effect of increasing effective nuclear charge and increasing screening effect along the period.
    The atomic and ionic radii of 4d series are greater than 3d series. However, the elements of 4d series and 5d series have almost similar sizes due to lanthanide contraction. Transition elements have low atomic volumes, high densities, high melting points.

    Q. The metal with high melting point in 3d series is

     

    Solution

     

    The high melting point of Cr metal is attributed to the involvement of greater number of electrons from (n - 1) d in addition to ns electrons in the interatomic metallic bonding.

     

  • Question 18
    4 / -1

    Matching List Type

    Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

    Q. 

    Match the Column I with Column II and mark the correct option from codes given below.

    Solution

    (i) → (s), (ii) → (r), (iii) → (q), (iv) → (p)

  • Question 19
    4 / -1

    Which one of the following ions exhibits colour in aqueous solution

    Solution


  • Question 20
    4 / -1

    Gun metal is an alloy of:

     

  • Question 21
    4 / -1

     

    Which one of the following elements shows the maximum number of different oxidation states in its compounds?

     

  • Question 22
    4 / -1

    When potassium ferrocyanide crystals are heated with concentrated sulphuric acid, the gas evolved is

     

  • Question 23
    4 / -1

     

    Zinc and mercury do not show variable valency like d-block elements because

  • Question 24
    4 / -1

    During the process of electrolytic refining of copper, some metals present as impurity settle as ‘anode mud’ These are

    Solution

    The correct answer is option C
    In Electrolytic refining, the impure metal is made to act as an anode. A strip of the same metal in pure form is used as a cathode. 
    They are put in a suitable electrolytic bath containing a soluble salt of the same metal. 
    The more basic metal remains in the solution and the less basic ones go to the anode mud.
    Copper is refined using an electrolytic method.
    Impurities from the blister copper deposit as anode mud which contains antimony, selenium, tellurium, silver, gold, and platinum; recovery of these elements may meet the cost of refining.

  • Question 25
    4 / -1

     

    Statement I : The highest oxidation state of osmium is +8.

    Statement II : Osmium is a 5-d block element.

     

    Solution

     

    Osmium has the electronic configuration 5de6s2. As 5d and 6s are close in energy, all the 8 electron can participate in bonding. highest oxidation state of osmium is +8 due to its ability to expand their octet by using its all 8 electrons (2 from 6s and 6 from 5d).

     

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