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Chemical Bonding and Molecular Structure Test - 3

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Chemical Bonding and Molecular Structure Test - 3
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  • Question 1
    4 / -1

    The electronic configuration of four atoms are given in brackets:

    L(1s22s22p1); 
    M(1s22s22p5);
    Q(1s22s22p63s1);
    R(1s22s22p2);

    The element that would most readily form a diatomic molecule is

    Solution

    By sharing of 1electron each, both the atoms of M will get a completed octet.

  • Question 2
    4 / -1

    Two elements P and Q combine to form a compound. If P has 2 and Q has 6 electrons in their outermost shell, what will be formula of the compound formed?

    Solution

    Valence electrons in P is 2; Valence electrons in Q is 6.

    P - 2e- → P2+

    Q + 2e- → Q2- 

    Since both show a valency of 2, the formula for the compound will be PQ.

  • Question 3
    4 / -1

    How many number of electrons are involved in the formation of a nitrogen molecule?

    Solution

    Number of electrons involved in bonding is 6.

  • Question 4
    4 / -1

    In which of the following molecules octet rule is not followed?

    Solution

    For NO, the octet rule is not followed due to the presence of odd electrons on N.

  • Question 5
    4 / -1

    A pair of electrons present between two identicalnon-metals.

    Solution

    An electron pair is equally shared between two identical atoms like F — F, H — H.
    It is pulled towards a more electronegative atom in case of dissimilar atoms.

  • Question 6
    4 / -1

    During a coordinate bond formation,

    Solution

    In a coordinate or dative bond, electrons required for sharing are contributed by one atom. The atom which contributes the electrons for sharing is called donor atom and the atom which shares the electrons is called acceptor atom.

  • Question 7
    4 / -1

    Which of the following molecules contains covalent and coordinate bonds?

    Solution

  • Question 8
    4 / -1

    Which of the following shows the Lewis dot formula for CO2?

    Solution

    Step I: Skeleton OCO

    Step II: A = 1 x 4 for C + 2 x 6 for O = 4 + 12 = 16 electrons

    Step III : Total no. of electrons needed to achieve noble gas configuration (N)
    N= 1 x 8 + 2 x 8 = 24

    Step IV : Shared electrons, S = N- A = 24-16 = 8 electrons

  • Question 9
    4 / -1

    How many and what types of bonds are present in NH4+?

    Solution

  • Question 10
    4 / -1

    What is the formal charge on carbon atom in the following two structures?

    Solution

    Formal charge on C atom = Valence electrons
    -Lone pair of electrons −1/2× Bonding electrons

    formal charge on C atom =0

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