Self Studies

Redox Reactions Test - 6

Result Self Studies

Redox Reactions Test - 6
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    4 / -1

     

    Q. As2S3 (yellow precipitate) is soluble in cone. HNO3 as given in unbalanced equation

    Equivalent weight in terms of molar mass M of As2S3 is

     

    Solution

     


    Increase in oxidation number of As2S3, = 28 - 0 = 28

     

  • Question 2
    4 / -1

    In the following reaction, 2H2S(g) + SO2(g) → 3S(S) + 2H2O (l) One equivalent of H2S (g)will reduce

    Solution


    Change in oxidation number of S of H2S = 2 units
    Change in oxidation number of S of SO2 = 4 units
    Then one mole H2S = 2 equivalents H2S
    One mole SO2 = 4 equivalent SO2
    One equivalent H23 one equivalent SO2 = 0.25 mole SO2 

  • Question 3
    4 / -1

    Which has maximum number of equivalents per mole of the oxidant?

    Solution

    Oxidant is the oxidising agent (which has been reduced)



  • Question 4
    4 / -1

    Equivalent weight of H3PO2 in a reaction is found to be half of its molecular weight. It can be due to its

    Solution

    (a) It is monobasic acid, hence only oneH+ can be neutralised 



  • Question 5
    4 / -1

    KMnO4 (purple) is reduced to K2MnO4 (green) by in basic medium. 1 mole of KMnO4 is reduced by

    Solution


    Multiply by change in oxidation number

  • Question 6
    4 / -1

    Equivalent weight of K2Cr2O7 in the following reaction is

    (M = molar mass of K2Cr2O7)

    Solution



  • Question 7
    4 / -1

    In the following disproportionation of Cl2 in basic medium Cl2 + 2KOH → KCl + KClO + H2O  equivalent mass of Cl2 is

    Solution

    In a disproportionation reaction net, equivalent mass = E (oxidation part) + E (reduction part)

  • Question 8
    4 / -1

    One mole of CaOCI2 is dissolved in water and excess of Kl added. Hypo (Na2S2O3) required to react oxidised part completely is

    Solution


  • Question 9
    4 / -1

    Consider conversion of MnCI2 into

          
    Increasing order of equivalent weights of MnCI2 in these conversions is

    Solution


  • Question 10
    4 / -1

    The equivalent weight of MnSO4 is half of its molecular weight when it converts to

    Solution






  • Question 11
    4 / -1

    The number of moles of KMnO4 that will be needed to react with one mole of ferrous sulphite in acidic solution is

    Solution




  • Question 12
    4 / -1

    The number of moles of K2Cr2O7 that will be needed to react completely with one mole of ferric sulphite in acidic medium is

    Solution




  • Question 13
    4 / -1

    Photosynthesis of carbohydrates in plants takes place as

    6CO2 +12H2 C6H12O6 + 6O2 + 6H2O

    Equivalent weight of CO2 and C6H12O6 respectively are 

    Solution


    Change in oxidation number = 24 units

  • Question 14
    4 / -1

    Equivalent weight of C6H5CHO is equal to molar mass in the following reaction.

    Thus, species {A) is 

    Solution





  • Question 15
    4 / -1

     

    Equivalent w eight of KMnO4 and its reduced species in different mediums are given


     

    Solution


     

  • Question 16
    4 / -1

     

    Which is chlorate (I) ion

    Solution

    ClO3: A very reactive inorganic anion.

    The term chlorate can also be used to describe any compound containing the chlorate ion, normally chlorate salts. 

    Example: Potassium chlorate, KClO3

     

  • Question 17
    4 / -1

     

    Which of the following is not an example of redox reaction?

     

    Solution

     

    a) BaCl2 + H2SO4 → BaSO4 + 2HCl is not a redox reaction, as there is no change in the oxidation state of any element.

    It is an example of double displacement reactions.

  • Question 18
    4 / -1

    NaHC2O4 is neutralised by NaOH and can also be oxidised by KMnO4 (in acidic medium). Equivalent weight is related to m olecular w eight (M) of NaHC2O4 in these two reactions as

    Solution



    Thus, equivalent weight when reacted with NaOH = M

  • Question 19
    4 / -1

    Direction (Q. Nos. 19-20) This section contains a paragraph, wach describing theory, experiments, data etc. three Questions related to paragraph have been given.Each question have only one correct answer among the four given options (a),(b),(c),(d)

    Current fuel cells use the reaction of H2(g) and O2(g) to form H2O (/). Often the H2(g)is obtained by steam reforming of a hydrocarbon, such as

    A future possibility is a fuel cell that converts a hydrocarbon such as propane directly to CO2(g) and H2O (/)

    Q. Difference in equivalent weights of C3H8 based on I and II is

    Solution


    (oxidation number of C taking 3C-atoms together) Change in oxidation number of C = 14 units 

    (oxidation number of C taking 3C-atoms together) Change in oxidation number of C = 20 units 



    (b) From (a), it is clear that (20) electrons are exchanged. Multiply reduction part by (5) and add

  • Question 20
    4 / -1

    Current fuel cells use the reaction of H2(g) and O2(g) to form H2O (/). Often the H2(g)is obtained by steam reforming of a hydrocarbon, such as

    A future possibility is a fuel cell that converts a hydrocarbon such as propane directly to CO2(g) and H2O (/)

    Q. Select the correct statements about reaction II taking place in acidic medium.

    Solution


    (oxidation number of C taking 3C-atoms together) Change in oxidation number of C = 14 units 

    (oxidation number of C taking 3C-atoms together) Change in oxidation number of C = 20 units 



    (b) From (a), it is clear that (20) electrons are exchanged. Multiply reduction part by (5) and add

  • Question 21
    4 / -1

     

    Choice the correct combination of elements and column I and coloumn II are given as option (a), (b), (c) and (d), out of which ONE option is correct.

    Q. Match the reactions of H3PO3 (m olar mass = M)in Column I with the corresponding equivalent mass of H3PO3 in Column II


     

    Solution

     





     

  • Question 22
    4 / -1

     

    Direction (Q. Nos. 22 and 23) This section contains 2 questions. when worked out will result in an integer from 0 to 9 (both inclusive)

    Q. How many moles of are formed per mole of Mn2+ reacted in the following reaction?

     

    Solution

     


    Oxidation number of Mn2+ changes from + 2 to + 7 Thus, Mn2+ is oxidised.

    In persulphateion , there is one peroxy linkage which is source of oxidation and reduced to oxide.

     

  • Question 23
    4 / -1

     

    In certain laboratory process, it is necessary to remove ions from solution by heating with HNO3. Calculate the moles of HNO3 required by 1 mole of (NH4)2SO4

     

    Solution

     

    is oxidised to N2 and HNO3 is reduced to NO2

     

Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now