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Redox Reaction Test - 11

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Redox Reaction Test - 11
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  • Question 1
    1 / -0

    Direction (Q. Nos. 1-15) This section contains 15 multiple choice questions. Each question has four
    choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

    Q. As2S3 (yellow precipitate) is soluble in cone. HNO3 as given in unbalanced equation

    Equivalent weight in terms of molar mass M of As2S3 is

    Solution


    Increase in oxidation number of As2S3, = 28 - 0 = 28

  • Question 2
    1 / -0

    In the following reaction, 2H2S(g) + SO2(g) → 3S(S) + 2H2O (l) One equivalent of H2S (g)will reduce

    Solution


    Change in oxidation number of S of H2S = 2 units
    Change in oxidation number of S of SO2 = 4 units
    Then one mole H2S = 2 equivalents H2S
    One mole SO2 = 4 equivalent SO2
    One equivalent H23 one equivalent SO2 = 0.25 mole SO2 

  • Question 3
    1 / -0

    Which has maximum number of equivalents per mole of the oxidant?

    Solution

    Oxidant is the oxidising agent (which has been reduced)



  • Question 4
    1 / -0

    Equivalent weight of H3PO2 in a reaction is found to be half of its molecular weight. It can be due to its

    Solution

    (a) It is monobasic acid, hence only oneH+ can be neutralised 



  • Question 5
    1 / -0

    KMnO4 (purple) is reduced to K2MnO4 (green) by in basic medium. 1 mole of KMnO4 is reduced by

    Solution


    Multiply by change in oxidation number

  • Question 6
    1 / -0

    Equivalent weight of K2Cr2O7 in the following reaction is

    (M = molar mass of K2Cr2O7)

    Solution



  • Question 7
    1 / -0

    In the following disproportionation of Cl2 in basic medium Cl2 + 2KOH → KCl + KClO + H2O  equivalent mass of Cl2 is

    Solution

    In a disproportionation reaction net, equivalent mass = E (oxidation part) + E (reduction part)

  • Question 8
    1 / -0

    One mole of CaOCI2 is dissolved in water and excess of Kl added. Hypo (Na2S2O3) required to react oxidised part completely is

    Solution


  • Question 9
    1 / -0

    Consider conversion of MnCI2 into

          
    Increasing order of equivalent weights of MnCI2 in these conversions is

    Solution


  • Question 10
    1 / -0

    The equivalent weight of MnSO4 is half of its molecular weight when it converts to

    Solution






  • Question 11
    1 / -0

    The number of moles of KMnO4 that will be needed to react with one mole of ferrous sulphite in acidic solution is

    Solution




  • Question 12
    1 / -0

    The number of moles of K2Cr2O7 that will be needed to react completely with one mole of ferric sulphite in acidic medium is

    Solution




  • Question 13
    1 / -0

    Photosynthesis of carbohydrates in plants takes place as

    6CO2 +12H2 C6H12O6 + 6O2 + 6H2O

    Equivalent weight of CO2 and C6H12O6 respectively are 

    Solution


    Change in oxidation number = 24 units

  • Question 14
    1 / -0

    Equivalent weight of C6H5CHO is equal to molar mass in the following reaction.

    Thus, species {A) is 

    Solution





  • Question 15
    1 / -0

    Equivalent w eight of KMnO4 and its reduced species in different mediums are given


    Solution



     

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