Thermodynamics Test

Result

Thermodynamics Test - 1

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Which of the following equations represent standard heat of formation C₂H₆

A
2C (diamond) + 2H₂(g) → C₂H₄ (g)

B
2C (graphite) + 2H₂(g) → C₂H₄ (g)

C
2C (diamond) + 4H(g) → C₂H₄ (g)

D
2C (graphite) + 4H(g) → C₂H₄ (g)

Solution

Standard heat of formation of C₂H₅ is the heat change when 1 mole of C₂H₄ is formed from its elements in the standard state (carbon as graphite and hydrogen as H₂)
Question 2
1 / -0

For an endothermic reaction where ΔH represents the enthalpy of the reaction in kJ/mol, the minimum value for the energy of activation will be

A
less than ΔH

B
Zero

C
more than ΔH

D
equal to ΔH

Solution

equal to ΔH
Question 3
1 / -0

Under the same conditions how many ml of 1 M KOH and 0.5 M H₂SO₄ solutions respectively, when mixed to form total volume of 100 ml produces the highest rise in temperature

A
67, 33

B
33, 67

C
40, 60

D
50, 50

Solution

This gives the neutralization of 1 mole H⁺ and 1 mole of OH¯ ions.
Question 4
1 / -0

Standard molar enthalpy of formation of CO₂ is equal to

A
Zero

B
the standard molar enthalpy of formation of CO₂is equal to

C
the sum of standard molar enthalpy of formation of CO and O₂

D
the standard molar enthalpy of combustion of carbon (graphite)

Solution

C(graphite) + O₂(g) → CO₂(g)

The standard molar enthalpy of formation of CO₂ is equal to the standard molar enthalpy of combustion of carbon (graphite)