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Alcohol, Phenol and Ether Test - 19

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Alcohol, Phenol and Ether Test - 19
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Only One Option Correct Type

    Direction (Q. Nos. 1-8) This section contains 8 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

    Consider the following reaction,

    CH2 = CH2 + Cl2 - H2O → ClCH2 — CH2OH  HOCH2CH2OH

    Q. 

    The most appropriate reagent X for the above reaction is

    Solution

    A slightly weaker base (NaHCO3) is used in the second step SN2 reaction otherwise oxirane formation would be preferred.

  • Question 2
    1 / -0

    Which is the most suitable condition for the following transformation?

    Solution

    Epoxide, upon hydrolysis in either acidic or alkaline medium gives anti, vicinal diol.

  • Question 3
    1 / -0

    What is the increasing order of solubility of the following in water?

    Solution

    Greater the number of hydroxy groups, greater the solubility in water. Between (II) and (III), (III) is slightly less soluble due to greater hydrophobic alkyl fraction.

  • Question 4
    1 / -0

    How many different diols product are formed in the following reaction?

    Solution

    At planar carbonyl carbons, hydride ion attacks from both sides giving both stereomers. Hence, the product diols would be all stereomers of 2, 3 - butanediol.

  • Question 5
    1 / -0

    Which does not form dihalide when treated with ethylene glycol?

    Solution

    (d) PI3 does not form di iodide with vicinal diols.

  • Question 6
    1 / -0

    What is the major organic product of the following reaction?

     

    Solution


    Both oxirane hydrolysis and halide substitution (SN2) take place.

  • Question 7
    1 / -0

    What is formed as the major product in the reaction given below?

    Solution


  • Question 8
    1 / -0

    The major organic product formed below is

     

    Solution

    Ethylene glycol on heating with concentrated H2SO4 gives 1 , 4-dioxane

  • Question 9
    1 / -0

    Matching List Type

    Direction (Q . Nos. 9 and 10) C hoices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

    Q.

    Match the reactant from Column I with the reaction(s) from Column II and mark the correct option from the codes given below.


    Solution







  • Question 10
    1 / -0

    Match the compounds in Column I with their reaction and product(s) in Column II and mark the correct option from the codes given below.

     

    Solution

    (i) It is a symmetrical, 3° diol, gives (CH3)2CO with HIO4, a single pinacolone (CH3)3C —COCH3 and a single cyclic a mine :

    (ii) With HIO4 gives (CH3)2CO and (C6H5)2CO. (ii) is unsymmetrical, 3° diol, gives more than one pinacolone in rearrangement reaction. However it gives a single cyclic amine.

    (iii) with HIO4 gives a single ketone-acetophenone. It gives two different pinacolone in rearrangement reaction.

    (iv) It is unsymmetrical, 3° diol, gives two different ketones with HIO4 and more than one pinacolone in rearrangement reaction.

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