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Chemical Kinetics Test - 17

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Chemical Kinetics Test - 17
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  • Question 1
    1 / -0

    Direction (Q. Nos. 1-12) This section contains 12 multiple choice questions. Each question has four choices (a), (b), (c) and (cl), out of which ONLY ONE is correct.

    Q.

    The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be (Given, R = 8.314 J K-1 mol-1, log2 = 0.3010).

    Solution


  • Question 2
    1 / -0

    In the following reaction

    N2O  N2+O

    k = (5.0 x 1011 L mol-1 s-1) e -29000R/T, Ea (energy o f activation) is 

    Solution

    By Arrhenius equation


  • Question 3
    1 / -0

    Rate of a reaction can be expressed by Arrhenius equation as k = Ae-EalRT. In this equation, Ea represents.

    Solution


    Ea (activation energy) is the energy required to activate the reactant so that they may collide and give the final product. Below point B, the reactants will not react at all.

  • Question 4
    1 / -0

    In the upper atmosphere, form ation of H2O2 takes place as

    H2O+O → 2OH → H202

    ΔH0 = 72.0 Kj mol-1 ; E= 77.0 kJ mol-1

    Ea for the bim olecular recombination of two OH radicals to form H2O and O is

    Solution



  • Question 5
    1 / -0

    How much rate is affected in the presence of catalyst at 300 K?

    Solution

    k(no catalyst) = Ae -Ea/RT 

    ∴ 

    Thus, rate is affected (28.03) times.
    k1 (no catalyst) = Ae-Ea/RT
    k2 (with catalyst) = Ae-(Ea - 2)/RT 

  • Question 6
    1 / -0

    For a reaction,

    A → Product

    t50  = 100 min at temprature T1

    and t50 = 80 min at temprature T2

    Thus, 

    Solution

    On increasing temperature, number of collisions hence kinetic energy increases.

    Thus, 


    Thus rate of the reaction or rate constant increases with increase in temperature.
    Half-life of any reaction
    Thus, half-life decreases with increase in temperature, reaction may be exothermic or endothermic.
    Thus,   

  • Question 7
    1 / -0

    Rate constant (k) of a reaction has least value at

    Solution

    k varies with temperature as given by Arrhenius equation
     

    k has least value at low 7 and high Ea.

  • Question 8
    1 / -0

    Two reactions with different activation energies have the same rate at room temperature. Which statement correctly describes the rates of these two reactions at the same higher temperature?

    Solution



    If temperature is increased to T`,

    If 
    Thus, reaction with smaller activation energy will be faster on increasing temperature.

  • Question 9
    1 / -0

    The activation energy of the reaction at a given temperature is found to (2.303 RT) J mol-1. The ratio of rate constant to the Arrhenius factor is

    Solution





  • Question 10
    1 / -0

    From the given figure, select the correct statement about activation energy.

    Activation energy of

    Solution

    Energy required to take the reactant to the activated state is (E1 + E2). Since, reactions is endothermic, product is less stable.

  • Question 11
    1 / -0

    The rate of a chemical reaction doubles for every 10°C rise of temperature. If the tem perature is raised by 50°C, the rate of the reaction increases by about

    [AIEEE 2011]

    Solution

    Number of ten degrees in 
    Increase in rate due to 10° rise in temperature = 2
    Increase in rate due to 50° rise in temperature = 25 = 32 times

  • Question 12
    1 / -0

    A reactant A forms two products B and C as given

    A  B, Activation energy Ea1

    A  C, Activation energy Ea2

    if Ea2 = 2Ea1, then k1 and K2 are related as 

    [AIEEE 2011]

    Solution






    ∴ 

  • Question 13
    1 / -0

    Direction (Q. No. 13) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

      Rate constant {k) of a reaction is given by

    Match the given property in Column I with its related value in Column II and select answer from codes given:

    Solution

    By Arrhenius equation, 

    ∴  
    Thus, (i)→(r)

    Unit of k is in min-1.

    Thus, (ii)→(p)
    At 500 K, 
    k = 10 min-1

    ∴ 
    10 min-1 (0.2M) = 2 M min-1
    Thus (iii)→(q)


    Thus, (iv)→(s)

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