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Amines Test - 1

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Amines Test - 1
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  • Question 1
    1 / -0

    Which of the following will have the lowest pH when one mole of each of the following is hydrolysed with water?

    Solution

    Only CH3COCl gives strong acid HCl on hydrolysis. Therefore, pH of an aqueous solution of CH3COCl is lowest.

     

  • Question 2
    1 / -0

    Among the given compounds, the most susceptible to nucleophilic attack at the carbonyl group is

    Solution

    Amongst aldehydes and the acid derivatives, acid chlorides are most susceptible to nucleophilic attack.

     

  • Question 3
    1 / -0

    An ester (A) with molecular formula C9H10O2 was treated with excess of CH3MgBr and the complex so formed was treated with H2SO4 to give an olefin (B). Ozonolysis of (B) gave ketone with molecular formula C8H8O which shows +ve iodform test. The structure of (A) is

    Solution

    Since ketone with M.F. C8H8O shows +ve iodoform test, therefore, it must be a methyl ketone, i.e., C6H5COCH3. Since this ketone is obtained by the ozonolysis of an olefin (B) which is obtained by the addition of excess of CH3MgBr to an ester (A) with M.F. C9H10O2, therefore, ester (A) is C6H5COOC2H5 and the olefin (B) is C6H5(CH3) = CH2

     

  • Question 4
    1 / -0

    On mixing ethyl acetate with aqueous sodium chloride, the composition of the resultant solution is

    Solution

    NaCl being salt of a strong acid and a strong base does not undergo hydrolysis. Therefore, it will remain as such in the mixture and thus option (a) is correct.

     

     

  • Question 5
    1 / -0

    Acetyl bromide reacts with excess of CH3MgI followed by treatment with a saturated solution of NH4Cl gives

    Solution

    The aqueous solution of NH4Cl is acidic in nature and hence can be used to hydrolyse the addition product.

     

  • Question 6
    1 / -0

    Melting points are normally the highest for

    Solution

    Due to H-bonding, 1° amides have the highest melting point.

     

  • Question 7
    1 / -0

    Intermediates formed during reaction of RCONH2 with Br2 and KOH are

    Solution

    RCONHBr and RNCO are the intermediates. Refer to ‘Additional Useful Information for Competitive Examinations.

     

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