Amines Test

Result

Amines Test - 5

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

Propanamide on treatment with bromine in an aqueous solution of sodium hydroxide gives:

A
Propanamine

B
Butanamide

C
Ethanamine

D
Butanamie

Solution
Question 2
1 / -0

We can obtain ethylamine by Hoffmann bromamide reaction. The amide used in this reaction is:

A
Methanamide

B
Acetamide

C
Propanamide

D
Butanamide

Solution

The correct answer is option C
CH₃CH₂CONH₂ (A)⟶ CH₃ − CH₂ − NH₂ (B)⟶ CH₃ − CH₂ − OH
In the above sequence A & B respectively are Br₂/KOH and HNO₂
The first step is Hoffmann bromamide degradation reaction in which an amide (propanamide) is converted to an amine (ethylamine) containing one carbon atom less. The reagent A is bromine in presence of KOH. In the second step, aliphatic primary amine (ethyl amine) reacts with nitrous acid (reagent B) to form aliphatic primary alcohol (ethyl alcohol).
Question 3
1 / -0

Nitro compounds are reduced to amines. The catalyst that is preferred is:

A
Sn + HCl

B
Fe + HCl

C
Ethanol

D
Mg + HCl

Solution

Fe + HCl is preferred due to the following reasons:
- Scrap iron i.e Fe is cheap and commercially easily available
- FeCl₂formed will get hydrolysed and release HCl, so, HCl which is required in the reaction will be produced by itself
- Hence only small amount of HCl is required to initiate the reaction.
Question 4
1 / -0

Aniline can be prepared by:

A
Reduction of nitrobenzene

B
Nitration of nitrobenzene

C
Oxidation of nitrobenzene

D
Nitration of nitrobenzene followed by reduction

Solution

Aniline is prepared commercially by the catalytic hydrogenation of nitrobenzene or by the action of ammonia on chlorobenzene. The reduction of nitrobenzene can also be carried out with iron borings in aqueous acid. A primary aromatic amine, aniline is a weak base and forms salts with mineral acids.
Question 5
1 / -0

is a tertiary amine having IUPAC name as:

A
N,N-Dimethyl-methanamine

B
N,Phenyl-methanamine

C
N-methyl-ethanamine

D
N-Methylmethanamine
Question 6
1 / -0

Which reaction can be used for the direct conversion of amides into 1⁰ amine ?

A
Reduction with LiAlH₄

B
Perkin’s reaction

C
Claissen reaction

D
Hoffmann ammonolysis

Solution

The correct answer is option A
Reduction with LiAlH₄
Question 7
1 / -0

What is the end product in the following sequence of reactions ?
Acetamide A B

A
Ammonium acetate

B
Methylamine

C
Methyl isocyanide

D
Ethylamine

Solution

The correct answer is Option D.
Question 8
1 / -0

When Primary amide is treated with an aqueous solution of KOH and bromine, it gives a primary amine. The name of the reaction is:

A
Gabriel-phthalamine reaction

B
Reimer-Tiemann reaction

C
Ammonolysis

D
Hoffmann Bromamide reaction

Solution

Hoffmann Bromamide reaction is Treatment of alkylamide with KOH and Bromine gas which converts it into alkylamine with one less carbon atom, this reaction is generally helpful in converting Carboxylic acids to amines with one less carbon atom . For reaction you may refer to internet but i can give you a hint .

Acetamide + KOH + Bromine gas —-> Alkylamine+ KBr + K2CO3 + H20 ( not sure about the products)
Question 9
1 / -0

Gabriel phthalimide synthesis is used in the preparation of :

A
2⁰ Amines

B
Mixture of all the three

C
3⁰ Amines

D
1⁰ Amines

Solution

The correct answer is option D
The chemical reaction used for transforming primary alkyl halides into primary amines is called Gabriel phthalimide synthesis. It uses potassium phthalimide. Therefore, Gabriel phthalimide synthesis is used in the preparation of 1o
amide.
Question 10
1 / -0

To convert methyl cyanide to ethylamine we use:

A
Br₂

B
HNO₃

C
KOH

D
LiAlH₄

Solution

LiAlH₄ reduces all oxiginated functional groups to alcohol and all nitrogenated functional groups to amine thus cyanide is a nitrogenated functional group and to convert cyanide to amine LiAlH4 can be used.